Torque
Q. If two forces of equal magnitude are applied at opposite ends of a lever arm, what is the net torque about the center?
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A.
Zero
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B.
Equal to the force
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C.
Twice the force
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D.
Depends on the distance
Solution
The net torque is zero because the torques produced by the two forces cancel each other out.
Correct Answer: A — Zero
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Q. In a seesaw, if one child exerts a force of 30 N at a distance of 1.5 m from the pivot, what is the torque produced by this child?
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A.
15 Nm
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B.
30 Nm
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C.
45 Nm
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D.
60 Nm
Solution
Torque (τ) = F × r = 30 N × 1.5 m = 45 Nm.
Correct Answer: C — 45 Nm
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Q. In a seesaw, if one child exerts a force of 30 N at a distance of 2 m from the pivot, what is the torque exerted by that child?
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A.
15 Nm
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B.
30 Nm
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C.
60 Nm
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D.
0 Nm
Solution
Torque (τ) = F × r = 30 N × 2 m = 60 Nm.
Correct Answer: C — 60 Nm
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Q. In a seesaw, if one child exerts a torque of 30 N·m on one side, what torque must the other child exert to balance it?
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A.
15 N·m
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B.
30 N·m
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C.
45 N·m
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D.
60 N·m
Solution
To balance the seesaw, the other child must exert an equal torque of 30 N·m.
Correct Answer: B — 30 N·m
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Q. What is the torque about a pivot if a force of 12 N is applied at a distance of 0.25 m at an angle of 90 degrees?
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A.
3 Nm
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B.
6 Nm
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C.
12 Nm
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D.
24 Nm
Solution
Torque = Force × Distance = 12 N × 0.25 m = 3 Nm.
Correct Answer: C — 12 Nm
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Q. What is the torque about a pivot if a force of 8 N is applied perpendicular to a lever arm of 0.75 m?
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A.
4 Nm
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B.
6 Nm
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C.
8 Nm
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D.
10 Nm
Solution
Torque = Force × Distance = 8 N × 0.75 m = 6 Nm.
Correct Answer: C — 8 Nm
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Q. What is the torque produced by a 60 N force acting at a distance of 0.75 m from the pivot point?
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A.
45 Nm
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B.
60 Nm
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C.
75 Nm
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D.
90 Nm
Solution
Torque = Force × Distance = 60 N × 0.75 m = 45 Nm.
Correct Answer: A — 45 Nm
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Q. What is the torque produced by a 60 N force applied at a distance of 0.75 m from the pivot point?
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A.
45 Nm
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B.
60 Nm
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C.
75 Nm
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D.
90 Nm
Solution
Torque = Force × Distance = 60 N × 0.75 m = 45 Nm.
Correct Answer: A — 45 Nm
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Q. What is the torque produced by a force of 10 N applied at a distance of 2 m from the pivot point, perpendicular to the lever arm?
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A.
5 Nm
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B.
10 Nm
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C.
20 Nm
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D.
15 Nm
Solution
Torque (τ) = Force (F) × Distance (r) = 10 N × 2 m = 20 Nm.
Correct Answer: C — 20 Nm
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Q. What is the torque produced by a force of 15 N acting at an angle of 90 degrees to the lever arm of 0.5 m?
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A.
0 Nm
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B.
7.5 Nm
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C.
15 Nm
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D.
30 Nm
Solution
Torque = Force × Distance × sin(θ) = 15 N × 0.5 m × sin(90°) = 15 Nm.
Correct Answer: C — 15 Nm
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Q. What is the torque produced by a force of 25 N acting at an angle of 90 degrees to the lever arm of 0.5 m?
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A.
12.5 Nm
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B.
25 Nm
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C.
50 Nm
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D.
0 Nm
Solution
Torque = Force × Distance × sin(90°) = 25 N × 0.5 m × 1 = 12.5 Nm.
Correct Answer: B — 25 Nm
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Q. What is the unit of torque in the SI system?
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A.
Newton
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B.
Joule
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C.
Newton-meter
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D.
Pascal
Solution
The unit of torque in the SI system is Newton-meter (Nm).
Correct Answer: C — Newton-meter
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Q. Which of the following factors does NOT affect the torque exerted by a force?
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A.
Magnitude of the force
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B.
Distance from the pivot
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C.
Angle of application
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D.
Mass of the object
Solution
The mass of the object does not affect the torque; torque depends on the force, distance from the pivot, and angle of application.
Correct Answer: D — Mass of the object
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Q. Which of the following factors does NOT affect the torque produced by a force?
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A.
Magnitude of the force
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B.
Distance from the pivot
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C.
Angle of application
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D.
Mass of the object
Solution
The mass of the object does not affect the torque; torque depends on force, distance, and angle.
Correct Answer: D — Mass of the object
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Q. Which of the following statements about torque is true?
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A.
Torque is a scalar quantity.
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B.
Torque depends on the angle of application.
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C.
Torque is always positive.
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D.
Torque does not depend on the point of rotation.
Solution
Torque depends on the angle of application, as it is calculated using τ = F × d × sin(θ).
Correct Answer: B — Torque depends on the angle of application.
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