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What is the torque produced by a force of 25 N acting at an angle of 90 degrees
What is the torque produced by a force of 25 N acting at an angle of 90 degrees to the lever arm of 0.5 m?
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Practice Questions
1 question
Q1
What is the torque produced by a force of 25 N acting at an angle of 90 degrees to the lever arm of 0.5 m?
12.5 Nm
25 Nm
50 Nm
0 Nm
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Torque = Force × Distance × sin(90°) = 25 N × 0.5 m × 1 = 12.5 Nm.
Questions & Step-by-step Solutions
1 item
Q
Q: What is the torque produced by a force of 25 N acting at an angle of 90 degrees to the lever arm of 0.5 m?
Solution:
Torque = Force × Distance × sin(90°) = 25 N × 0.5 m × 1 = 12.5 Nm.
Steps: 8
Show Steps
Step 1: Identify the force applied, which is 25 N.
Step 2: Identify the distance from the pivot point to where the force is applied, which is 0.5 m.
Step 3: Determine the angle at which the force is applied, which is 90 degrees.
Step 4: Calculate the sine of the angle. Since sin(90°) = 1, we can use this value.
Step 5: Use the torque formula: Torque = Force × Distance × sin(angle).
Step 6: Substitute the values into the formula: Torque = 25 N × 0.5 m × 1.
Step 7: Perform the multiplication: 25 N × 0.5 m = 12.5 Nm.
Step 8: Conclude that the torque produced is 12.5 Nm.
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