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In a seesaw, if one child exerts a force of 30 N at a distance of 2 m from the p
In a seesaw, if one child exerts a force of 30 N at a distance of 2 m from the pivot, what is the torque exerted by that child?
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Practice Questions
1 question
Q1
In a seesaw, if one child exerts a force of 30 N at a distance of 2 m from the pivot, what is the torque exerted by that child?
15 Nm
30 Nm
60 Nm
0 Nm
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Torque (τ) = F × r = 30 N × 2 m = 60 Nm.
Questions & Step-by-step Solutions
1 item
Q
Q: In a seesaw, if one child exerts a force of 30 N at a distance of 2 m from the pivot, what is the torque exerted by that child?
Solution:
Torque (τ) = F × r = 30 N × 2 m = 60 Nm.
Steps: 5
Show Steps
Step 1: Identify the force exerted by the child, which is 30 N.
Step 2: Identify the distance from the pivot to where the force is applied, which is 2 m.
Step 3: Use the formula for torque, which is Torque (τ) = Force (F) × Distance (r).
Step 4: Substitute the values into the formula: τ = 30 N × 2 m.
Step 5: Calculate the result: τ = 60 Nm.
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