Motion in Two Dimensions

Q. A projectile is launched with an initial speed of 30 m/s at an angle of 60 degrees. What is the horizontal component of its velocity?

A. 15 m/s
B. 20 m/s
C. 25 m/s
D. 30 m/s

Solution

Horizontal component (vx) = u * cos(θ) = 30 * 0.5 = 15 m/s.

Correct Answer: B — 20 m/s

Learn More →

Q. A projectile is launched with an initial speed of 40 m/s at an angle of 30 degrees. What is the time of flight?

A. 4 s
B. 5 s
C. 6 s
D. 8 s

Solution

Time of flight (T) = (2u * sin(θ)) / g = (2 * 40 * (√3/2)) / 9.8 ≈ 6.1 s.

Correct Answer: C — 6 s

Learn More →

Q. A projectile is launched with an initial speed of 40 m/s at an angle of 60 degrees. What is the horizontal component of its velocity?

A. 20 m/s
B. 30 m/s
C. 40 m/s
D. 50 m/s

Solution

Horizontal component (vx) = u * cos(θ) = 40 * 0.5 = 20 m/s.

Correct Answer: B — 30 m/s

Learn More →

Q. A projectile is launched with an initial speed of 50 m/s at an angle of 30 degrees. What is the horizontal component of the velocity?

A. 25 m/s
B. 35 m/s
C. 43.3 m/s
D. 50 m/s

Solution

Horizontal component (vx) = u * cos(θ) = 50 * cos(30) = 50 * (√3/2) = 43.3 m/s.

Correct Answer: C — 43.3 m/s

Learn More →

Q. A projectile is launched with an initial speed of 50 m/s at an angle of 60 degrees. What is the horizontal component of its velocity?

A. 25 m/s
B. 50 m/s
C. 43.3 m/s
D. 30 m/s

Solution

Horizontal component (v_x) = u * cos(θ) = 50 * 0.5 = 25 m/s.

Correct Answer: C — 43.3 m/s

Learn More →

Q. A projectile is launched with an initial velocity of 30 m/s at an angle of 60 degrees. What is the horizontal component of the velocity?

A. 15 m/s
B. 20 m/s
C. 25 m/s
D. 30 m/s

Solution

Horizontal component (u_x) = u * cos(θ) = 30 * 0.5 = 15 m/s.

Correct Answer: B — 20 m/s

Learn More →

Q. A projectile is launched with an initial velocity of 40 m/s at an angle of 45 degrees. What is the vertical component of its velocity?

A. 20 m/s
B. 28.28 m/s
C. 30 m/s
D. 40 m/s

Solution

Vertical component Vy = u * sin(θ) = 40 * (√2/2) = 28.28 m/s.

Correct Answer: B — 28.28 m/s

Learn More →

Q. A projectile is launched with an initial velocity of 40 m/s at an angle of 45 degrees. What is the vertical component of the velocity?

A. 20 m/s
B. 28.28 m/s
C. 30 m/s
D. 40 m/s

Solution

Vertical component Vy = u * sin(θ) = 40 * (√2/2) = 28.28 m/s.

Correct Answer: B — 28.28 m/s

Learn More →

Q. A projectile is launched with an initial velocity of 40 m/s at an angle of 45 degrees. What is the time of flight?

A. 4 s
B. 5 s
C. 6 s
D. 7 s

Solution

Time of flight (T) = (2u * sin(θ)) / g = (2*40*sin(45))/9.8 = 5.14 s.

Correct Answer: B — 5 s

Learn More →

Q. A projectile is thrown with a speed of 20 m/s at an angle of 45 degrees. What is the vertical component of the velocity?

A. 10 m/s
B. 14.14 m/s
C. 20 m/s
D. 28.28 m/s

Solution

Vertical component (u_y) = u * sin(θ) = 20 * (√2/2) = 14.14 m/s.

Correct Answer: B — 14.14 m/s

Learn More →

Q. A stone is dropped from a height of 45 m. How far will it have fallen after 2 seconds?

A. 10 m
B. 20 m
C. 30 m
D. 40 m

Solution

Distance fallen (s) = (1/2)gt² = (1/2)(9.8)(2²) = 19.6 m.

Correct Answer: C — 30 m

Learn More →

Q. A stone is dropped from a height of 45 m. How far will it have fallen after 3 seconds?

A. 10.5 m
B. 20 m
C. 30 m
D. 40.5 m

Solution

Distance fallen (s) = (1/2)gt² = (1/2)(9.8)(3²) = 44.1 m.

Correct Answer: D — 40.5 m

Learn More →

Q. A stone is dropped from a height of 45 m. How far will it travel horizontally if it is thrown horizontally with a speed of 10 m/s?

A. 20 m
B. 30 m
C. 40 m
D. 50 m

Solution

Time to fall (t) = √(2h/g) = √(2*45/9.8) ≈ 3 s; horizontal distance = v*t = 10*3 = 30 m.

Correct Answer: B — 30 m

Learn More →

Q. A stone is dropped from a height of 45 m. How far will it travel horizontally if it is projected horizontally with a speed of 10 m/s?

A. 20 m
B. 30 m
C. 40 m
D. 50 m

Solution

Time to fall t = √(2h/g) = √(90/9.8) ≈ 4.27 s; horizontal distance = 10 * 4.27 ≈ 42.7 m.

Correct Answer: C — 40 m

Learn More →

Q. A stone is dropped from a height of 45 m. How long does it take to reach the ground?

A. 3 s
B. 4 s
C. 5 s
D. 6 s

Solution

Using h = (1/2)gt², we have 45 = (1/2)(9.8)t², solving gives t ≈ 4.3 s.

Correct Answer: B — 4 s

Learn More →

Q. A stone is dropped from a height of 80 m. How long does it take to hit the ground?

A. 4 s
B. 5 s
C. 6 s
D. 8 s

Solution

Time (t) = √(2h/g) = √(2*80/9.8) = 4.04 s.

Correct Answer: A — 4 s

Learn More →

Q. A stone is dropped from a height of 80 m. How long will it take to reach the ground?

A. 2 s
B. 4 s
C. 6 s
D. 8 s

Solution

Using h = (1/2)gt², we get t = √(2h/g) = √(2*80/9.8) = 4.04 s.

Correct Answer: B — 4 s

Learn More →

Q. A stone is thrown vertically upward with a speed of 20 m/s. How high will it rise before coming to rest?

A. 10 m
B. 20 m
C. 30 m
D. 40 m

Solution

Maximum height (H) = (u²)/(2g) = (20²)/(2*9.8) ≈ 20.4 m.

Correct Answer: C — 30 m

Learn More →

Q. An object is moving in a circular path with a radius of 10 m at a speed of 5 m/s. What is the period of the motion?

A. 2π s
B. 4π s
C. 10 s
D. 20 s

Solution

Period (T) = 2πr/v = 2π(10)/5 = 4π s.

Correct Answer: A — 2π s

Learn More →

Q. An object is projected at an angle of 60 degrees with an initial speed of 30 m/s. What is the horizontal component of its velocity?

A. 15 m/s
B. 25 m/s
C. 30 m/s
D. 20 m/s

Solution

Horizontal component (v_x) = u * cos(θ) = 30 * (1/2) = 15 m/s.

Correct Answer: B — 25 m/s

Learn More →

Q. An object is projected at an angle of 60 degrees with an initial speed of 30 m/s. What is the vertical component of its velocity?

A. 15 m/s
B. 25 m/s
C. 30 m/s
D. 20 m/s

Solution

Vertical component (v_y) = u * sin(θ) = 30 * (√3/2) = 25.98 m/s.

Correct Answer: B — 25 m/s

Learn More →

Q. An object is projected at an angle of 60 degrees with an initial velocity of 30 m/s. What is the time of flight?

A. 3 s
B. 5 s
C. 6 s
D. 10 s

Solution

Time of flight (T) = (2u * sin(θ)) / g = (2 * 30 * √3/2) / 9.8 = 5.18 s.

Correct Answer: C — 6 s

Learn More →

Q. An object is projected at an angle of 60 degrees with an initial velocity of 30 m/s. What is the horizontal component of its velocity?

A. 15 m/s
B. 25 m/s
C. 30 m/s
D. 20 m/s

Solution

Horizontal component Vx = u * cos(θ) = 30 * (1/2) = 15 m/s.

Correct Answer: B — 25 m/s

Learn More →

Q. An object is thrown at an angle of 30 degrees with a speed of 40 m/s. What is the time of flight until it returns to the same vertical level?

A. 4 s
B. 5 s
C. 6 s
D. 8 s

Solution

Time of flight (T) = (2 * u * sin(θ)) / g = (2 * 40 * 0.5) / 9.8 ≈ 4.08 s.

Correct Answer: C — 6 s

Learn More →

Q. An object is thrown horizontally from the top of a 45 m high cliff. How far from the base of the cliff will it land if it is thrown with a speed of 10 m/s?

A. 20 m
B. 30 m
C. 40 m
D. 50 m

Solution

Time of flight (t) = √(2h/g) = √(2*45/9.8) = 3.03 s. Horizontal distance = speed * time = 10 * 3.03 = 30.3 m.

Correct Answer: B — 30 m

Learn More →

Q. An object is thrown horizontally from the top of a 45 m high cliff. How far from the base of the cliff will it land if the initial speed is 10 m/s?

A. 10 m
B. 20 m
C. 30 m
D. 40 m

Solution

Time of flight (t) = √(2h/g) = √(2*45/9.8) = 3.03 s. Horizontal distance = speed * time = 10 * 3.03 = 30.3 m.

Correct Answer: B — 20 m

Learn More →

Q. An object is thrown horizontally from the top of a cliff 80 m high. How long does it take to hit the ground?

A. 2 s
B. 4 s
C. 5 s
D. 8 s

Solution

Using h = (1/2)gt^2, we have 80 = (1/2)(9.8)t^2, solving gives t ≈ 4 s.

Correct Answer: B — 4 s

Learn More →

Q. An object is thrown horizontally from the top of a cliff of height 80 m. How long does it take to hit the ground?

A. 2 s
B. 4 s
C. 5 s
D. 8 s

Solution

Using h = (1/2)gt^2, we have 80 = (1/2)(9.8)t^2, solving gives t ≈ 4 s.

Correct Answer: B — 4 s

Learn More →

Q. An object is thrown vertically upward with a speed of 20 m/s. How high will it rise before coming to rest?

A. 10 m
B. 20 m
C. 30 m
D. 40 m

Solution

Maximum height (H) = (u²)/(2g) = (20²)/(2*9.8) ≈ 20.4 m.

Correct Answer: C — 30 m

Learn More →

Q. An object is thrown vertically upwards with a speed of 20 m/s. How long will it take to reach the maximum height?

A. 1 s
B. 2 s
C. 3 s
D. 4 s

Solution

Time to reach maximum height (t) = u/g = 20/9.8 = 2.04 s.

Correct Answer: B — 2 s

Learn More →

Showing 31 to 60 of 70 (3 Pages)

Motion in Two Dimensions

On a scale of 0–10, how likely are you to recommend The Soulshift Academy?