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A projectile is launched with an initial velocity of 30 m/s at an angle of 60 de
A projectile is launched with an initial velocity of 30 m/s at an angle of 60 degrees. What is the horizontal component of the velocity?
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Practice Questions
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Q1
A projectile is launched with an initial velocity of 30 m/s at an angle of 60 degrees. What is the horizontal component of the velocity?
15 m/s
20 m/s
25 m/s
30 m/s
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Horizontal component (u_x) = u * cos(θ) = 30 * 0.5 = 15 m/s.
Questions & Step-by-step Solutions
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Q
Q: A projectile is launched with an initial velocity of 30 m/s at an angle of 60 degrees. What is the horizontal component of the velocity?
Solution:
Horizontal component (u_x) = u * cos(θ) = 30 * 0.5 = 15 m/s.
Steps: 7
Show Steps
Step 1: Identify the initial velocity (u) of the projectile, which is given as 30 m/s.
Step 2: Identify the angle (θ) at which the projectile is launched, which is given as 60 degrees.
Step 3: Use the formula to find the horizontal component of the velocity: u_x = u * cos(θ).
Step 4: Calculate cos(60 degrees). The value of cos(60 degrees) is 0.5.
Step 5: Substitute the values into the formula: u_x = 30 m/s * 0.5.
Step 6: Perform the multiplication: 30 * 0.5 = 15 m/s.
Step 7: Conclude that the horizontal component of the velocity is 15 m/s.
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