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A projectile is launched with an initial speed of 40 m/s at an angle of 60 degre
A projectile is launched with an initial speed of 40 m/s at an angle of 60 degrees. What is the horizontal component of its velocity?
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Practice Questions
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Q1
A projectile is launched with an initial speed of 40 m/s at an angle of 60 degrees. What is the horizontal component of its velocity?
20 m/s
30 m/s
40 m/s
50 m/s
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Horizontal component (vx) = u * cos(θ) = 40 * 0.5 = 20 m/s.
Questions & Step-by-step Solutions
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Q
Q: A projectile is launched with an initial speed of 40 m/s at an angle of 60 degrees. What is the horizontal component of its velocity?
Solution:
Horizontal component (vx) = u * cos(θ) = 40 * 0.5 = 20 m/s.
Steps: 6
Show Steps
Step 1: Identify the initial speed of the projectile, which is given as 40 m/s.
Step 2: Identify the angle of launch, which is given as 60 degrees.
Step 3: Use the formula to find the horizontal component of velocity: vx = u * cos(θ).
Step 4: Calculate cos(60 degrees). The value of cos(60 degrees) is 0.5.
Step 5: Substitute the values into the formula: vx = 40 m/s * 0.5.
Step 6: Perform the multiplication: vx = 20 m/s.
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