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A projectile is launched with an initial velocity of 40 m/s at an angle of 45 de
A projectile is launched with an initial velocity of 40 m/s at an angle of 45 degrees. What is the vertical component of its velocity?
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Practice Questions
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Q1
A projectile is launched with an initial velocity of 40 m/s at an angle of 45 degrees. What is the vertical component of its velocity?
20 m/s
28.28 m/s
30 m/s
40 m/s
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Vertical component Vy = u * sin(θ) = 40 * (√2/2) = 28.28 m/s.
Questions & Step-by-step Solutions
1 item
Q
Q: A projectile is launched with an initial velocity of 40 m/s at an angle of 45 degrees. What is the vertical component of its velocity?
Solution:
Vertical component Vy = u * sin(θ) = 40 * (√2/2) = 28.28 m/s.
Steps: 7
Show Steps
Step 1: Identify the initial velocity (u) of the projectile, which is given as 40 m/s.
Step 2: Identify the angle of launch (θ), which is given as 45 degrees.
Step 3: Convert the angle from degrees to radians if necessary, but for 45 degrees, we can use the sine value directly.
Step 4: Calculate the sine of the angle: sin(45 degrees) = √2/2.
Step 5: Use the formula for the vertical component of velocity: Vy = u * sin(θ).
Step 6: Substitute the values into the formula: Vy = 40 * (√2/2).
Step 7: Calculate the result: Vy = 40 * 0.7071 (approximately) = 28.28 m/s.
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