Q. If a 10 N force is applied at an angle of 60 degrees to the horizontal while moving an object 3 m, what is the work done? (2020)
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A.
15 J
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B.
30 J
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C.
25 J
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D.
5 J
Solution
Work done = Force × Distance × cos(θ) = 10 N × 3 m × cos(60°) = 10 N × 3 m × 0.5 = 15 J
Correct Answer: A — 15 J
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Q. If a 1000 kg car is moving at a speed of 15 m/s, what is its kinetic energy?
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A.
112,500 J
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B.
225,000 J
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C.
150,000 J
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D.
75,000 J
Solution
Kinetic Energy = 0.5 × mass × velocity² = 0.5 × 1000 kg × (15 m/s)² = 112,500 J
Correct Answer: B — 225,000 J
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Q. If a 1000 kg car is moving with a speed of 15 m/s, what is its kinetic energy?
-
A.
112,500 J
-
B.
225,000 J
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C.
75,000 J
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D.
150,000 J
Solution
Kinetic Energy = 0.5 × mass × velocity² = 0.5 × 1000 kg × (15 m/s)² = 112,500 J
Correct Answer: B — 225,000 J
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Q. If a 1000 W motor runs for 2 hours, how much work does it do? (2000)
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A.
7200 J
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B.
2000 J
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C.
3600000 J
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D.
100000 J
Solution
Work = Power × Time = 1000 W × (2 hours × 3600 s/hour) = 1000 W × 7200 s = 7200000 J
Correct Answer: C — 3600000 J
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Q. If a 100Ω resistor is connected in series with a 200Ω resistor, what is the total resistance? (2023)
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A.
300Ω
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B.
100Ω
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C.
200Ω
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D.
400Ω
Solution
In series, R_total = R1 + R2 = 100Ω + 200Ω = 300Ω.
Correct Answer: A — 300Ω
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Q. If a 10Ω resistor is connected in parallel with a 5Ω resistor, what is the equivalent resistance? (2022)
-
A.
3.33Ω
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B.
5Ω
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C.
7.5Ω
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D.
15Ω
Solution
For parallel resistors, 1/R_eq = 1/R1 + 1/R2 = 1/10 + 1/5 = 1/10 + 2/10 = 3/10. Therefore, R_eq = 10/3 = 3.33Ω.
Correct Answer: A — 3.33Ω
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Q. If a 10Ω resistor is connected in parallel with a 5Ω resistor, what is the total resistance? (2022)
-
A.
3.33Ω
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B.
5Ω
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C.
7.5Ω
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D.
15Ω
Solution
For resistors in parallel, 1/R_eq = 1/R1 + 1/R2 = 1/10 + 1/5 = 1/10 + 2/10 = 3/10. Therefore, R_eq = 10/3 = 3.33Ω.
Correct Answer: A — 3.33Ω
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Q. If a 1500 kg car is moving at a speed of 30 m/s, what is its kinetic energy?
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A.
675,000 J
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B.
450,000 J
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C.
225,000 J
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D.
900,000 J
Solution
Kinetic Energy = 0.5 × mass × velocity² = 0.5 × 1500 kg × (30 m/s)² = 675,000 J
Correct Answer: B — 450,000 J
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Q. If a 15Ω resistor is connected in parallel with a 5Ω resistor, what is the equivalent resistance? (2023)
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A.
3.75Ω
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B.
4Ω
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C.
5Ω
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D.
10Ω
Solution
1/R_eq = 1/15 + 1/5 = 1/15 + 3/15 = 4/15; R_eq = 15/4 = 3.75Ω.
Correct Answer: A — 3.75Ω
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Q. If a 2 kg object is dropped from a height, what is its velocity just before hitting the ground (g = 10 m/s²)? (2023)
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A.
10 m/s
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B.
20 m/s
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C.
30 m/s
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D.
40 m/s
Solution
Using v = √(2gh), for h = 10 m, v = √(2 * 10 m/s² * 10 m) = √200 = 20 m/s.
Correct Answer: B — 20 m/s
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Q. If a 2 kg object is dropped from a height, what is its velocity just before hitting the ground? (g = 9.8 m/s², h = 20 m) (2023)
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A.
14 m/s
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B.
19.6 m/s
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C.
20 m/s
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D.
28 m/s
Solution
Using v² = u² + 2gh, where u = 0, we find v = √(2 * 9.8 * 20) = 19.6 m/s.
Correct Answer: B — 19.6 m/s
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Q. If a 2 kg object is lifted to a height of 10 m, what is the potential energy gained by the object? (g = 9.8 m/s²)
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A.
19.6 J
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B.
98 J
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C.
39.2 J
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D.
78.4 J
Solution
Potential Energy (PE) = mgh = 2 kg × 9.8 m/s² × 10 m = 196 J.
Correct Answer: B — 98 J
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Q. If a 2 kg object is lifted to a height of 3 m, what is the potential energy gained by the object? (g = 9.8 m/s²)
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A.
58.8 J
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B.
19.6 J
-
C.
29.4 J
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D.
39.2 J
Solution
Potential Energy (PE) = mgh = 2 kg × 9.8 m/s² × 3 m = 58.8 J.
Correct Answer: A — 58.8 J
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Q. If a 2 kg object is moving with a velocity of 15 m/s, what is its kinetic energy?
-
A.
225 J
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B.
150 J
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C.
300 J
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D.
450 J
Solution
Kinetic Energy = 1/2 * m * v^2 = 1/2 * 2 kg * (15 m/s)^2 = 225 J.
Correct Answer: A — 225 J
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Q. If a 2 kg object is moving with a velocity of 3 m/s, what is its kinetic energy?
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A.
9 J
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B.
6 J
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C.
3 J
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D.
12 J
Solution
Kinetic Energy = 0.5 * m * v² = 0.5 * 2 kg * (3 m/s)² = 9 J.
Correct Answer: A — 9 J
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Q. If a 3 kg object is moving with a speed of 4 m/s, what is its kinetic energy?
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A.
12 J
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B.
24 J
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C.
36 J
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D.
48 J
Solution
KE = 0.5 × m × v² = 0.5 × 3 kg × (4 m/s)² = 0.5 × 3 × 16 = 24 J.
Correct Answer: B — 24 J
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Q. If a 4 kg object is moving with a speed of 5 m/s, what is its kinetic energy?
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A.
50 J
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B.
40 J
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C.
100 J
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D.
80 J
Solution
Kinetic Energy (KE) = 0.5 × m × v² = 0.5 × 4 kg × (5 m/s)² = 0.5 × 4 × 25 = 50 J.
Correct Answer: D — 80 J
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Q. If a 5 kg object is dropped from a height of 10 m, what is its potential energy just before it hits the ground? (g = 9.8 m/s²)
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A.
490 J
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B.
980 J
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C.
245 J
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D.
2450 J
Solution
Potential Energy (PE) = m × g × h = 5 kg × 9.8 m/s² × 10 m = 490 J.
Correct Answer: B — 980 J
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Q. If a 5 kg object is dropped from a height of 10 m, what is its potential energy just before it hits the ground? (2021)
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A.
50 J
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B.
100 J
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C.
150 J
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D.
200 J
Solution
PE = m × g × h = 5 kg × 9.8 m/s² × 10 m = 490 J.
Correct Answer: B — 100 J
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Q. If a 5 kg object is moving with a speed of 10 m/s, what is its total mechanical energy assuming no potential energy?
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A.
250 J
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B.
500 J
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C.
100 J
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D.
50 J
Solution
Total Mechanical Energy = Kinetic Energy = 0.5 * m * v² = 0.5 * 5 kg * (10 m/s)² = 250 J.
Correct Answer: B — 500 J
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Q. If a 5 kg object is moving with a velocity of 3 m/s, what is its kinetic energy? (2023)
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A.
22.5 J
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B.
30 J
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C.
45 J
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D.
60 J
Solution
Kinetic Energy = 0.5 × mass × velocity² = 0.5 × 5 kg × (3 m/s)² = 22.5 J
Correct Answer: C — 45 J
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Q. If a 5 kg object is moving with a velocity of 3 m/s, what is its momentum? (2023)
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A.
5 kg·m/s
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B.
10 kg·m/s
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C.
15 kg·m/s
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D.
20 kg·m/s
Solution
Momentum p = mv = 5 kg * 3 m/s = 15 kg·m/s.
Correct Answer: C — 15 kg·m/s
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Q. If a 5 kg object is subjected to a net force of 20 N, what is its acceleration? (2023)
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A.
2 m/s²
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B.
4 m/s²
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C.
5 m/s²
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D.
10 m/s²
Solution
Using F = ma, we find a = F/m = 20 N / 5 kg = 4 m/s².
Correct Answer: B — 4 m/s²
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Q. If a 5Ω resistor is connected in series with a 10Ω resistor, what is the total resistance? (2022)
-
A.
15Ω
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B.
5Ω
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C.
10Ω
-
D.
20Ω
Solution
In series, R_eq = R1 + R2 = 5Ω + 10Ω = 15Ω.
Correct Answer: A — 15Ω
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Q. If a 5Ω resistor is connected to a 10V source, what is the power dissipated? (2023)
-
A.
2W
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B.
5W
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C.
10W
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D.
20W
Solution
Power P = V²/R = (10V)² / 5Ω = 100 / 5 = 20W.
Correct Answer: C — 10W
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Q. If a 6Ω and a 3Ω resistor are connected in parallel, what is the equivalent resistance? (2022)
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A.
2Ω
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B.
4Ω
-
C.
1.5Ω
-
D.
9Ω
Solution
Using the formula for parallel resistors: 1/R_eq = 1/R1 + 1/R2 = 1/6 + 1/3 = 1/6 + 2/6 = 3/6. Therefore, R_eq = 2Ω.
Correct Answer: A — 2Ω
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Q. If a 6Ω resistor is connected in parallel with a 3Ω resistor, what is the equivalent resistance? (2023)
-
A.
2Ω
-
B.
1.5Ω
-
C.
4Ω
-
D.
9Ω
Solution
Using the formula 1/R_eq = 1/R1 + 1/R2, we get 1/R_eq = 1/6 + 1/3 = 1/6 + 2/6 = 3/6, thus R_eq = 2Ω.
Correct Answer: A — 2Ω
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Q. If a 9V battery is connected to a 3Ω resistor, what is the current flowing through it? (2021)
Solution
Using Ohm's law, I = V/R = 9V / 3Ω = 3A.
Correct Answer: B — 2A
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Q. If a 9V battery is connected to a 3Ω resistor, what is the power dissipated in the resistor? (2023)
Solution
Power (P) can be calculated using P = V²/R = (9V)² / 3Ω = 81 / 3 = 27W.
Correct Answer: A — 3W
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Q. If a 9V battery is connected to a 3Ω resistor, what is the voltage drop across the resistor? (2023)
Solution
The voltage drop across the resistor is equal to the battery voltage, which is 9V.
Correct Answer: C — 9V
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