Laws of Motion
Q. A 1 kg ball is thrown vertically upwards with a velocity of 20 m/s. What is the maximum height it reaches? (g = 10 m/s²) (2021)
A.
20 m
B.
30 m
C.
40 m
D.
10 m
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Solution
Using the formula h = v² / (2g) = (20 m/s)² / (2 × 10 m/s²) = 20 m.
Correct Answer: A — 20 m
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Q. A 10 kg block is pushed with a force of 50 N. What is its acceleration? (2023)
A.
2 m/s²
B.
5 m/s²
C.
10 m/s²
D.
15 m/s²
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Solution
Using Newton's second law, F = ma, we have a = F/m = 50 N / 10 kg = 5 m/s².
Correct Answer: B — 5 m/s²
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Q. A 10 kg object is subjected to a net force of 30 N. What is its acceleration? (2022)
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
5 m/s²
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Solution
Using F = ma, acceleration a = F/m = 30 N / 10 kg = 3 m/s².
Correct Answer: B — 3 m/s²
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Q. A 12 kg object is pushed with a force of 36 N. What is its acceleration? (2023)
A.
1 m/s²
B.
2 m/s²
C.
3 m/s²
D.
4 m/s²
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Solution
Using F = ma, we find a = F/m = 36 N / 12 kg = 3 m/s².
Correct Answer: C — 3 m/s²
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Q. A 15 kg object is dropped from a height. What is the force acting on it due to gravity? (2023)
A.
15 N
B.
30 N
C.
45 N
D.
150 N
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Solution
Using F = mg, where g = 9.8 m/s², we have F = 15 kg * 9.8 m/s² = 147 N, which rounds to 150 N.
Correct Answer: B — 30 N
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Q. A 15 kg object is moving with a velocity of 4 m/s. What is its momentum? (2019)
A.
60 kg m/s
B.
30 kg m/s
C.
45 kg m/s
D.
75 kg m/s
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Solution
Momentum = mass × velocity = 15 kg × 4 m/s = 60 kg m/s.
Correct Answer: A — 60 kg m/s
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Q. A 2 kg object is subjected to a net force of 8 N. What is its acceleration? (2020)
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
5 m/s²
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Solution
Using F = ma, a = F/m = 8 N / 2 kg = 4 m/s².
Correct Answer: C — 4 m/s²
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Q. A 20 kg cart is pulled with a force of 80 N. What is the acceleration of the cart? (2023)
A.
2 m/s²
B.
4 m/s²
C.
6 m/s²
D.
8 m/s²
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Solution
Using F = ma, we find a = F/m = 80 N / 20 kg = 4 m/s².
Correct Answer: B — 4 m/s²
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Q. A 25 kg object is acted upon by a force of 100 N. What is its acceleration? (2023)
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
5 m/s²
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Solution
Using F = ma, we find a = F/m = 100 N / 25 kg = 4 m/s².
Correct Answer: D — 5 m/s²
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Q. A 4 kg block is pulled with a force of 20 N. What is the acceleration of the block? (2020)
A.
5 m/s²
B.
4 m/s²
C.
3 m/s²
D.
2 m/s²
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Solution
Using F = ma, acceleration (a) = F/m = 20 N / 4 kg = 5 m/s².
Correct Answer: A — 5 m/s²
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Q. A 50 kg crate is pushed with a force of 200 N. If the frictional force is 50 N, what is the acceleration of the crate? (2022)
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
5 m/s²
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Solution
Net force = 200 N - 50 N = 150 N. Acceleration a = F/m = 150 N / 50 kg = 3 m/s².
Correct Answer: B — 3 m/s²
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Q. A 50 kg crate is pushed with a force of 200 N. What is the acceleration of the crate? (Assume no friction) (2021)
A.
2 m/s²
B.
4 m/s²
C.
5 m/s²
D.
10 m/s²
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Solution
Using F = ma, acceleration a = F/m = 200 N / 50 kg = 4 m/s².
Correct Answer: B — 4 m/s²
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Q. A 50 kg object is moving with a velocity of 5 m/s. What is its momentum? (2023)
A.
100 kg·m/s
B.
150 kg·m/s
C.
200 kg·m/s
D.
250 kg·m/s
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Solution
Momentum p = mv = 50 kg * 5 m/s = 250 kg·m/s.
Correct Answer: A — 100 kg·m/s
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Q. A 50 kg object is pulled with a force of 200 N. What is its acceleration? (2023)
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
5 m/s²
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Solution
Using F = ma, we find a = F/m = 200 N / 50 kg = 4 m/s².
Correct Answer: D — 5 m/s²
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Q. A 50 kg object is pushed with a force of 200 N. What is the frictional force if the object moves with constant velocity? (2023)
A.
0 N
B.
50 N
C.
200 N
D.
100 N
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Solution
If the object moves with constant velocity, the frictional force equals the applied force, which is 200 N.
Correct Answer: C — 200 N
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Q. A ball is thrown horizontally from a height of 20 m. How long does it take to hit the ground? (2019)
A.
1 s
B.
2 s
C.
3 s
D.
4 s
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Solution
Using the equation of motion for free fall: h = (1/2)gt². 20 m = (1/2)(9.8)t². Solving gives t ≈ 2 s.
Correct Answer: B — 2 s
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Q. A ball is thrown upwards with a velocity of 20 m/s. How high will it go before coming to rest? (2023)
A.
10 m
B.
20 m
C.
30 m
D.
40 m
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Solution
Using the formula h = v²/(2g), where g = 10 m/s², h = (20 m/s)² / (2 * 10 m/s²) = 20 m.
Correct Answer: C — 30 m
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Q. A ball is thrown vertically upwards with a speed of 20 m/s. How high will it go? (g = 10 m/s²) (2023)
A.
10 m
B.
20 m
C.
30 m
D.
40 m
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Solution
Using the formula h = v²/(2g), we have h = (20 m/s)² / (2 * 10 m/s²) = 20 m.
Correct Answer: B — 20 m
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Q. A block of mass 5 kg is pulled on a horizontal surface with a force of 20 N. If the frictional force is 5 N, what is the acceleration of the block? (2020)
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
5 m/s²
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Solution
Net force = Applied force - Frictional force = 20 N - 5 N = 15 N. Using F = ma, a = F/m = 15 N / 5 kg = 3 m/s².
Correct Answer: B — 3 m/s²
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Q. A block of mass 5 kg is resting on a frictionless surface. A force of 10 N is applied to it. What will be its acceleration? (2020)
A.
2 m/s²
B.
5 m/s²
C.
10 m/s²
D.
20 m/s²
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Solution
Using Newton's second law, F = ma, acceleration (a) = F/m = 10 N / 5 kg = 2 m/s².
Correct Answer: B — 5 m/s²
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Q. A car accelerates from rest at a constant rate of 2 m/s². How far does it travel in 5 seconds? (2021)
A.
10 m
B.
20 m
C.
25 m
D.
50 m
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Solution
Using the equation of motion: s = ut + (1/2)at². Here, u = 0, a = 2 m/s², t = 5 s. So, s = 0 + (1/2)(2)(5²) = 25 m.
Correct Answer: C — 25 m
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Q. A car accelerates from rest at a rate of 2 m/s². What is its speed after 5 seconds? (2023)
A.
5 m/s
B.
10 m/s
C.
15 m/s
D.
20 m/s
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Solution
Using the formula v = u + at, where u = 0, a = 2 m/s², and t = 5 s, we get v = 0 + 2 * 5 = 10 m/s.
Correct Answer: B — 10 m/s
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Q. A car accelerates from rest to a speed of 30 m/s in 10 seconds. What is the acceleration of the car? (2022)
A.
3 m/s²
B.
2 m/s²
C.
1 m/s²
D.
4 m/s²
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Solution
Acceleration (a) = (final velocity - initial velocity) / time = (30 m/s - 0) / 10 s = 3 m/s².
Correct Answer: A — 3 m/s²
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Q. A cyclist accelerates at 3 m/s² for 4 seconds. What is the final velocity if the initial velocity is 2 m/s? (2023)
A.
10 m/s
B.
11 m/s
C.
14 m/s
D.
20 m/s
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Solution
Using v = u + at, we have v = 2 m/s + (3 m/s² * 4 s) = 2 + 12 = 14 m/s.
Correct Answer: B — 11 m/s
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Q. A cyclist accelerates from rest to a speed of 10 m/s in 5 seconds. What is the acceleration? (2023)
A.
1 m/s²
B.
2 m/s²
C.
3 m/s²
D.
4 m/s²
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Solution
Acceleration = (final velocity - initial velocity) / time = (10 m/s - 0) / 5 s = 2 m/s².
Correct Answer: B — 2 m/s²
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Q. A cyclist accelerates from rest to a speed of 10 m/s in 5 seconds. What is the cyclist's acceleration? (2021)
A.
1 m/s²
B.
2 m/s²
C.
3 m/s²
D.
4 m/s²
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Solution
Acceleration a = (final velocity - initial velocity) / time = (10 m/s - 0) / 5 s = 2 m/s².
Correct Answer: B — 2 m/s²
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Q. A force of 15 N is applied to a 3 kg mass. What is the resulting acceleration? (2023)
A.
3 m/s²
B.
5 m/s²
C.
7 m/s²
D.
10 m/s²
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Solution
Using F = ma, acceleration a = F/m = 15 N / 3 kg = 5 m/s².
Correct Answer: B — 5 m/s²
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Q. A force of 30 N is applied to a 6 kg object. What is the object's acceleration? (2023)
A.
3 m/s²
B.
4 m/s²
C.
5 m/s²
D.
6 m/s²
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Solution
Using F = ma, we find a = F/m = 30 N / 6 kg = 5 m/s².
Correct Answer: B — 4 m/s²
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Q. An object is thrown vertically upwards with a velocity of 20 m/s. How high will it rise? (Assume g = 10 m/s²) (2020)
A.
20 m
B.
30 m
C.
40 m
D.
50 m
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Solution
Using h = v²/(2g) = (20 m/s)² / (2 × 10 m/s²) = 20 m.
Correct Answer: A — 20 m
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Q. An object moves with a constant velocity of 10 m/s. What is the net force acting on it? (2023)
A.
0 N
B.
10 N
C.
20 N
D.
100 N
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Solution
If the object moves with constant velocity, the net force acting on it is 0 N.
Correct Answer: A — 0 N
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