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If a 5 kg object is dropped from a height of 10 m, what is its potential energy
If a 5 kg object is dropped from a height of 10 m, what is its potential energy just before it hits the ground? (2021)
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If a 5 kg object is dropped from a height of 10 m, what is its potential energy just before it hits the ground? (2021)
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PE = m × g × h = 5 kg × 9.8 m/s² × 10 m = 490 J.
Questions & Step-by-step Solutions
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Q: If a 5 kg object is dropped from a height of 10 m, what is its potential energy just before it hits the ground? (2021)
Solution:
PE = m × g × h = 5 kg × 9.8 m/s² × 10 m = 490 J.
Steps: 7
Show Steps
Step 1: Identify the mass of the object. In this case, the mass (m) is 5 kg.
Step 2: Identify the height from which the object is dropped. Here, the height (h) is 10 m.
Step 3: Identify the acceleration due to gravity (g). The standard value is approximately 9.8 m/s².
Step 4: Use the formula for potential energy (PE), which is PE = m × g × h.
Step 5: Substitute the values into the formula: PE = 5 kg × 9.8 m/s² × 10 m.
Step 6: Calculate the result: 5 × 9.8 × 10 = 490 J.
Step 7: Conclude that the potential energy just before the object hits the ground is 490 Joules.
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