Q. If a body is moving in a circular path with a constant speed, what type of acceleration does it experience?
-
A.
Centripetal acceleration
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B.
Linear acceleration
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C.
Angular acceleration
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D.
No acceleration
Solution
A body moving in a circular path experiences centripetal acceleration directed towards the center of the circle.
Correct Answer: A — Centripetal acceleration
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Q. If a capacitor is charged to 12V and has a capacitance of 6μF, what is the stored energy? (2022)
-
A.
0.432 mJ
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B.
0.072 mJ
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C.
0.864 mJ
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D.
0.216 mJ
Solution
Energy = 0.5 × C × V² = 0.5 × 6 × 10^-6 × 12² = 0.432 mJ.
Correct Answer: A — 0.432 mJ
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Q. If a car accelerates from rest to a speed of 20 m/s, and its mass is 1000 kg, what is the kinetic energy of the car at that speed? (2020)
-
A.
200 J
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B.
1000 J
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C.
2000 J
-
D.
4000 J
Solution
Kinetic Energy = 0.5 × mass × velocity² = 0.5 × 1000 kg × (20 m/s)² = 200000 J = 2000 J
Correct Answer: C — 2000 J
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Q. If a car accelerates from rest to a speed of 20 m/s, and its mass is 1000 kg, what is the kinetic energy gained by the car? (2021)
-
A.
200,000 J
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B.
100,000 J
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C.
50,000 J
-
D.
400,000 J
Solution
Kinetic Energy (KE) = 0.5 × mass (m) × velocity² (v²). KE = 0.5 × 1000 kg × (20 m/s)² = 200,000 J.
Correct Answer: B — 100,000 J
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Q. If a car accelerates from rest to a speed of 20 m/s, what is the kinetic energy of the car if its mass is 1000 kg?
-
A.
200,000 J
-
B.
100,000 J
-
C.
50,000 J
-
D.
400,000 J
Solution
Kinetic Energy = 0.5 × mass × velocity² = 0.5 × 1000 kg × (20 m/s)² = 200,000 J
Correct Answer: B — 100,000 J
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Q. If a car travels at a speed of 60 km/h, how far will it travel in 2 hours? (2022)
-
A.
120 km
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B.
100 km
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C.
150 km
-
D.
90 km
Solution
Distance = Speed × Time = 60 km/h × 2 h = 120 km.
Correct Answer: A — 120 km
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Q. If a car with a mass of 1200 kg is moving at a speed of 15 m/s, what is its kinetic energy? (2021)
-
A.
13500 J
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B.
9000 J
-
C.
18000 J
-
D.
27000 J
Solution
Kinetic Energy = 0.5 × mass × velocity² = 0.5 × 1200 kg × (15 m/s)² = 13500 J
Correct Answer: A — 13500 J
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Q. If a charge of +2μC is placed in an electric field of 1000 N/C, what is the force experienced by the charge? (2023)
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A.
2 N
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B.
0.002 N
-
C.
2000 N
-
D.
0.2 N
Solution
The force (F) on a charge in an electric field is given by F = qE. Here, F = 2μC * 1000 N/C = 2 N.
Correct Answer: A — 2 N
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Q. If a charge of +2μC is placed in an electric field of strength 1000 N/C, what is the force acting on the charge? (2023)
-
A.
2 N
-
B.
0.002 N
-
C.
2000 N
-
D.
0.2 N
Solution
The force (F) on a charge in an electric field is given by F = qE. Here, F = (2 * 10^-6 C)(1000 N/C) = 2 N.
Correct Answer: A — 2 N
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Q. If a charge of 5 μC is placed in an electric field of 2000 N/C, what is the force experienced by the charge? (2023)
-
A.
10 N
-
B.
1 N
-
C.
0.1 N
-
D.
100 N
Solution
The force (F) on a charge in an electric field is given by F = qE. Here, F = 5 × 10^-6 C * 2000 N/C = 10 N.
Correct Answer: A — 10 N
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Q. If a circuit has a resistance of 5 ohms and a current of 2 A, what is the voltage? (2014)
-
A.
10 V
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B.
5 V
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C.
2 V
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D.
1 V
Solution
Using Ohm's Law, V = I × R = 2 A × 5 Ω = 10 V.
Correct Answer: A — 10 V
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Q. If a circuit has a total resistance of 12Ω and a current of 1.5A flows through it, what is the voltage across the circuit? (2022)
-
A.
18V
-
B.
12V
-
C.
15V
-
D.
10V
Solution
Using Ohm's law, V = IR = 1.5A * 12Ω = 18V.
Correct Answer: A — 18V
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Q. If a circuit has a total resistance of 12Ω and a current of 1.5A, what is the voltage across the circuit? (2021)
-
A.
18V
-
B.
12V
-
C.
15V
-
D.
10V
Solution
Using Ohm's law, V = IR = 1.5A * 12Ω = 18V.
Correct Answer: A — 18V
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Q. If a circuit has a total resistance of 12Ω and a current of 3A flows through it, what is the voltage across the circuit? (2020)
-
A.
36V
-
B.
12V
-
C.
4V
-
D.
24V
Solution
Using Ohm's law, V = IR = 3A * 12Ω = 36V.
Correct Answer: A — 36V
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Q. If a circuit has a total resistance of 12Ω and a current of 4A, what is the voltage across the circuit? (2023)
-
A.
48V
-
B.
36V
-
C.
24V
-
D.
12V
Solution
Using Ohm's law, V = IR = 4A * 12Ω = 48V.
Correct Answer: A — 48V
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Q. If a circuit has a total resistance of 5Ω and a current of 2A, what is the voltage across the circuit? (2022)
Solution
Using Ohm's law, V = I * R = 2A * 5Ω = 10V.
Correct Answer: A — 10V
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Q. If a circuit has a total resistance of 8Ω and a current of 4A, what is the voltage across the circuit? (2023)
-
A.
32V
-
B.
24V
-
C.
16V
-
D.
12V
Solution
Using Ohm's law, V = IR = 4A * 8Ω = 32V.
Correct Answer: A — 32V
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Q. If a force of 10 N is applied to a mass of 2 kg, what is the acceleration of the mass? (2020)
-
A.
2 m/s²
-
B.
5 m/s²
-
C.
10 m/s²
-
D.
20 m/s²
Solution
Using F = ma, acceleration a = F/m = 10 N / 2 kg = 5 m/s².
Correct Answer: B — 5 m/s²
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Q. If a force of 10 N is applied to move an object 3 m in the direction of the force, what is the work done?
-
A.
30 J
-
B.
10 J
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C.
3 J
-
D.
0 J
Solution
Work done = Force * Distance = 10 N * 3 m = 30 J.
Correct Answer: A — 30 J
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Q. If a force of 15 N is applied to a 3 kg object, what is the net force acting on the object if it is already moving with a velocity of 5 m/s? (2022)
-
A.
15 N
-
B.
3 N
-
C.
0 N
-
D.
18 N
Solution
The net force is still 15 N as it does not depend on the velocity of the object.
Correct Answer: A — 15 N
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Q. If a force of 15 N is applied to a mass of 3 kg, what is the acceleration of the mass? (2023)
-
A.
3 m/s²
-
B.
4 m/s²
-
C.
5 m/s²
-
D.
6 m/s²
Solution
Using F = ma, a = F/m = 15 N / 3 kg = 5 m/s².
Correct Answer: B — 4 m/s²
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Q. If a force of 20 N moves an object 5 m in the direction of the force, what is the work done?
-
A.
100 J
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B.
50 J
-
C.
20 J
-
D.
200 J
Solution
Work = Force * Distance = 20 N * 5 m = 100 J.
Correct Answer: A — 100 J
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Q. If a machine does 3000 J of work in 10 seconds, what is its power output?
-
A.
300 W
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B.
150 W
-
C.
600 W
-
D.
1000 W
Solution
Power (P) = Work (W) / Time (t) = 3000 J / 10 s = 300 W.
Correct Answer: A — 300 W
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Q. If a person does 300 J of work in 15 seconds, what is their average power output?
-
A.
20 W
-
B.
15 W
-
C.
25 W
-
D.
30 W
Solution
Power = Work / Time = 300 J / 15 s = 20 W
Correct Answer: A — 20 W
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Q. If a person does 300 J of work in 15 seconds, what is their power output?
-
A.
20 W
-
B.
15 W
-
C.
25 W
-
D.
30 W
Solution
Power = Work / Time = 300 J / 15 s = 20 W
Correct Answer: A — 20 W
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Q. If a person does 500 J of work in 5 seconds, what is their power output?
-
A.
100 W
-
B.
50 W
-
C.
200 W
-
D.
150 W
Solution
Power (P) = Work (W) / Time (t) = 500 J / 5 s = 100 W.
Correct Answer: A — 100 W
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Q. If a person lifts a 20 kg box to a height of 2 m, what is the work done against gravity? (g = 9.8 m/s²)
-
A.
392 J
-
B.
196 J
-
C.
588 J
-
D.
784 J
Solution
Work = m * g * h = 20 kg * 9.8 m/s² * 2 m = 392 J.
Correct Answer: B — 196 J
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Q. If a physical quantity has dimensions [M^0 L^1 T^-1], what is it? (2020)
-
A.
Velocity
-
B.
Acceleration
-
C.
Force
-
D.
Energy
Solution
The dimensions [M^0 L^1 T^-1] correspond to velocity, which is defined as distance traveled per unit time.
Correct Answer: A — Velocity
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Q. If a physical quantity has dimensions [M^2 L^3 T^-1], what could it represent? (2020)
-
A.
Force
-
B.
Pressure
-
C.
Volume flow rate
-
D.
Energy
Solution
The dimensions [M^2 L^3 T^-1] correspond to volume flow rate, which is volume per unit time.
Correct Answer: C — Volume flow rate
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Q. If a vehicle accelerates from 0 to 60 m/s in 12 seconds, what is its acceleration?
-
A.
2 m/s²
-
B.
4 m/s²
-
C.
5 m/s²
-
D.
6 m/s²
Solution
Using the formula: a = (v - u) / t = (60 - 0) / 12 = 5 m/s².
Correct Answer: B — 4 m/s²
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