Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol. Mass = moles x molar mass = 3 moles x 58.5 g/mol = 174 g.

The molar mass of NaCl is 58.5 g/mol. Therefore, 3 moles of NaCl weigh 3 x 58.5 g = 175.5 g.

Molar mass of NaOH = 40 g/mol; grams = moles × molar mass = (1 mole/L × 0.5 L) × 40 g/mol = 20 g

Molar mass of NaCl = 58.44 g/mol; mass = moles × molar mass = 3 moles × 58.44 g/mol = 175.32 g

Mass = moles × molar mass = (0.1 moles/L × 1 L) × 58.5 g/mol = 5.85 g.

Molar mass of NaOH = 40 g/mol. Mass = moles × molar mass = 0.5 moles × 40 g/mol = 20 g.

Mass percent = (mass of solute / total mass of solution) x 100 = (10 g / (10 g + 90 g)) x 100 = 10%

Area = 1/2 * base * height = 1/2 * 10 * x. Max area occurs when x = 10, giving Area = 50.

Area = 1/2 * base * height. Max area occurs when height is maximized, thus Area = 1/2 * 10 * 10 = 50.

Area = 1/2 * base * height = 5h. Max area occurs when h = 10, giving area = 50.

The maximum displacement from the mean position in simple harmonic motion is called the amplitude.

The maximum displacement in a mass-spring system is defined as the amplitude, which is given as 0.3 m.

The maximum displacement from the mean position in simple harmonic motion is called amplitude.

The maximum height occurs at t = -b/(2a) = 1. h(1) = 64.

The maximum height occurs at t = -b/(2a) = -64/(2*-16) = 2. h(2) = -16(2^2) + 64(2) + 48 = 80.

The maximum number of bright fringes is given by the formula n = d/λ. Here, n = 0.1 mm / 500 nm = 200, which means 20 bright fringes can be observed on either side of the central maximum.

The maximum number of bright fringes depends on the wavelength and the slit separation, as it determines how many integer multiples of the wavelength fit within the observable range.

The d subshell can hold a maximum of 10 electrons.

The f-subshell can hold a maximum of 14 electrons.

The d subshell can hold a maximum of 10 electrons.

The p subshell can hold a maximum of 6 electrons.

The maximum number of electrons in an energy level is given by the formula 2n². For n=3, it is 2(3)² = 18.

The maximum number of electrons in a shell is given by the formula 2n². For n=3, it is 2(3)² = 18.

The maximum number of electrons in a shell is given by the formula 2n². For n=3, it is 2(3)² = 18.

The maximum number of electrons in an energy level is given by 2n^2. For n=4, it is 2(4^2) = 32.

Phosphorus can exhibit a maximum oxidation state of +5 in compounds like PCl5.

The maximum profit occurs at x = -b/(2a) = 10/2 = 5. P(5) = -5^2 + 10*5 - 16 = 9.

The vertex occurs at x = 2. f(2) = -2^2 + 4(2) + 1 = 5.

The vertex occurs at x = 3. f(3) = -9 + 18 - 8 = 1.

Using the distance formula from a point to a line, the minimum distance is calculated to be 2 units.