Q. For the reaction 2SO2(g) + O2(g) ⇌ 2SO3(g), what happens to the equilibrium if the volume of the container is decreased? (2022)
A.Equilibrium shifts to the left
B.Equilibrium shifts to the right
C.No effect on equilibrium
D.Equilibrium constant changes
Solution
Decreasing the volume increases the pressure, and according to Le Chatelier's principle, the equilibrium will shift towards the side with fewer moles of gas, which is the right side (2 moles of SO3).
Correct Answer: B — Equilibrium shifts to the right
Q. For the reaction 2SO2(g) + O2(g) ⇌ 2SO3(g), what happens to the equilibrium position if SO3 is removed from the system? (2023)
A.The equilibrium shifts to the left
B.The equilibrium shifts to the right
C.The equilibrium remains unchanged
D.The reaction stops
Solution
Removing SO3 will decrease its concentration, causing the system to shift to the right to produce more SO3 in order to re-establish equilibrium, according to Le Chatelier's principle.
Correct Answer: B — The equilibrium shifts to the right
Q. For the reaction 2SO2(g) + O2(g) ⇌ 2SO3(g), what will happen if the volume of the container is increased? (2020) 2020
A.Equilibrium shifts to the right
B.Equilibrium shifts to the left
C.No change in equilibrium
D.Reaction stops
Solution
Increasing the volume decreases the pressure, and according to Le Chatelier's principle, the equilibrium will shift to the side with more moles of gas, which is the left side in this case.
Correct Answer: B — Equilibrium shifts to the left
Q. For the reaction N2(g) + 3H2(g) ⇌ 2NH3(g), what happens to the equilibrium if the volume of the container is decreased? (2020)
A.Equilibrium shifts to the right
B.Equilibrium shifts to the left
C.No change in equilibrium
D.Equilibrium shifts to the side with more moles
Solution
Decreasing the volume increases the pressure, and according to Le Chatelier's principle, the equilibrium will shift to the side with fewer moles of gas, which is the right side in this case.
Correct Answer: A — Equilibrium shifts to the right
Q. For the reaction: 2SO2(g) + O2(g) ⇌ 2SO3(g), what happens to the equilibrium position if the volume of the container is decreased? (2020)
A.Shifts to the left
B.Shifts to the right
C.No change
D.Depends on temperature
Solution
Decreasing the volume increases the pressure, and according to Le Chatelier's principle, the equilibrium will shift towards the side with fewer moles of gas, which is the right side in this case.
Q. For the reaction: 2SO2(g) + O2(g) ⇌ 2SO3(g), what will happen if the volume of the container is increased? (2020)
A.Equilibrium shifts to the right
B.Equilibrium shifts to the left
C.No change in equilibrium
D.Equilibrium shifts to the center
Solution
Increasing the volume decreases the pressure, and according to Le Chatelier's principle, the equilibrium will shift to the side with more moles of gas, which is the left side in this case.
Correct Answer: B — Equilibrium shifts to the left
Q. For the reaction: A(g) + B(g) ⇌ C(g) + D(g), if the volume of the container is decreased, what will be the effect on the equilibrium? (2023)
A.Shift to the left
B.Shift to the right
C.No effect
D.Increase the concentration of A
Solution
Decreasing the volume increases the pressure. According to Le Chatelier's principle, the equilibrium will shift towards the side with fewer moles of gas. If there are more moles of gas on the left side, the equilibrium will shift to the left.
Q. How many different 4-digit PINs can be formed using the digits 0-9 if digits cannot be repeated?
A.5040
B.10000
C.9000
D.7200
Solution
The first digit can be any of 10 digits, the second can be any of 9, the third can be any of 8, and the fourth can be any of 7. Total = 10 * 9 * 8 * 7 = 5040.
