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For the quadratic equation x² + 6x + k = 0 to have no real roots, what must be the value of k? (2021)

Practice Questions

1 question
Q1
For the quadratic equation x² + 6x + k = 0 to have no real roots, what must be the value of k? (2021)
  1. k < 9
  2. k > 9
  3. k = 9
  4. k ≤ 9

Questions & Step-by-step Solutions

1 item
Q
Q: For the quadratic equation x² + 6x + k = 0 to have no real roots, what must be the value of k? (2021)
Solution: The discriminant must be less than zero: 6² - 4*1*k < 0, which simplifies to k > 9.
Steps: 0

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