Physics Syllabus (JEE Main)
Q. In a two-slit interference pattern, if the angle of the first order maximum is θ, what is the path difference?
A.
λ
B.
2λ
C.
λ sin θ
D.
2λ sin θ
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Solution
The path difference for the first order maximum is given by d sin θ = λ, hence the path difference is λ sin θ.
Correct Answer: C — λ sin θ
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Q. In a two-slit interference pattern, if the distance between the slits is increased, what happens to the number of visible fringes on the screen?
A.
Increases
B.
Decreases
C.
Remains the same
D.
Becomes zero
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Solution
Increasing the distance between the slits (d) decreases the fringe width, which in turn reduces the number of visible fringes on the screen.
Correct Answer: B — Decreases
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Q. In a two-slit interference pattern, if the distance between the slits is increased, what happens to the fringe separation?
A.
Increases
B.
Decreases
C.
Remains the same
D.
Becomes zero
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Solution
Increasing the distance between the slits (d) decreases the fringe separation, as fringe separation is inversely proportional to d.
Correct Answer: B — Decreases
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Q. In a two-slit interference pattern, if the distance to the screen is doubled, what happens to the fringe spacing?
A.
It doubles
B.
It halves
C.
It remains the same
D.
It quadruples
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Solution
Fringe spacing (β) is directly proportional to the distance to the screen (D). If D is doubled, the fringe spacing also doubles.
Correct Answer: A — It doubles
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Q. In a two-slit interference pattern, if the intensity at the center is I0, what is the intensity at the first minimum?
A.
0
B.
I0
C.
I0/2
D.
I0/4
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Solution
At the first minimum, the intensity is 0 due to destructive interference.
Correct Answer: A — 0
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Q. In a two-slit interference pattern, if the intensity at the center is I_0, what is the intensity at the first minimum?
A.
0
B.
I_0
C.
I_0/2
D.
I_0/4
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Solution
At the first minimum, the intensity is 0 due to destructive interference.
Correct Answer: A — 0
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Q. In a two-slit interference pattern, if the intensity of light from one slit is increased, what happens to the overall intensity of the pattern?
A.
It decreases
B.
It remains the same
C.
It increases
D.
It becomes zero
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Solution
Increasing the intensity from one slit increases the overall intensity of the interference pattern.
Correct Answer: C — It increases
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Q. In a uniform circular motion, which of the following quantities remains constant?
A.
Velocity
B.
Acceleration
C.
Speed
D.
Centripetal force
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Solution
In uniform circular motion, speed remains constant while velocity and acceleration change direction.
Correct Answer: C — Speed
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Q. In a uniform electric field, how does the electric potential change with distance?
A.
Linearly
B.
Quadratically
C.
Exponentially
D.
Remains constant
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Solution
In a uniform electric field, the electric potential changes linearly with distance.
Correct Answer: A — Linearly
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Q. In a uniform electric field, the equipotential surfaces are always:
A.
Perpendicular to the field lines
B.
Parallel to the field lines
C.
Curved
D.
None of the above
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Solution
Equipotential surfaces are always perpendicular to electric field lines.
Correct Answer: A — Perpendicular to the field lines
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Q. In a uniform electric field, the equipotential surfaces are:
A.
Curved
B.
Straight lines
C.
Concentric circles
D.
Parallel planes
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Solution
In a uniform electric field, the equipotential surfaces are parallel planes.
Correct Answer: D — Parallel planes
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Q. In a uniform electric field, the potential difference between two points is directly proportional to what?
A.
Distance between the points
B.
Magnitude of the electric field
C.
Both A and B
D.
None of the above
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Solution
The potential difference is directly proportional to both the distance between the points and the magnitude of the electric field.
Correct Answer: C — Both A and B
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Q. In a uniform electric field, the potential difference between two points is given by which formula?
A.
V = Ed
B.
V = E/d
C.
V = d/E
D.
V = E × d
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Solution
In a uniform electric field, the potential difference (V) between two points is given by V = Ed, where d is the distance between the points.
Correct Answer: A — V = Ed
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Q. In a uniform electric field, the potential difference between two points is given by which of the following?
A.
E × d
B.
E/d
C.
d/E
D.
E + d
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Solution
In a uniform electric field, the potential difference (V) between two points separated by a distance (d) is given by V = E × d, where E is the electric field strength.
Correct Answer: A — E × d
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Q. In a uniform magnetic field, the magnetic force on a charged particle is maximum when the angle between the velocity and the magnetic field is:
A.
0 degrees
B.
90 degrees
C.
180 degrees
D.
45 degrees
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Solution
The magnetic force is maximum when the angle between the velocity and the magnetic field is 90 degrees, as sin(90°) = 1.
Correct Answer: B — 90 degrees
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Q. In a vacuum, which mode of heat transfer is not possible?
A.
Conduction
B.
Convection
C.
Radiation
D.
All of the above
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Solution
Convection is not possible in a vacuum as it requires a medium (fluid) for heat transfer.
Correct Answer: B — Convection
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Q. In a vacuum, which of the following travels fastest?
A.
Sound
B.
Light
C.
Radio waves
D.
All travel at the same speed
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Solution
In a vacuum, light travels fastest at approximately 3 x 10^8 m/s.
Correct Answer: B — Light
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Q. In a viscometer, what does the time taken for a fluid to flow through a capillary tube indicate?
A.
Density of the fluid
B.
Viscosity of the fluid
C.
Temperature of the fluid
D.
Pressure of the fluid
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Solution
The time taken for a fluid to flow through a capillary tube is directly related to its viscosity.
Correct Answer: B — Viscosity of the fluid
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Q. In a wave equation y(x, t) = A sin(kx - ωt), what does 'A' represent?
A.
Wavelength
B.
Frequency
C.
Amplitude
D.
Wave number
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Solution
'A' represents the amplitude of the wave, which is the maximum displacement from the equilibrium position.
Correct Answer: C — Amplitude
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Q. In a wave, if the amplitude is increased, what effect does it have on the energy of the wave?
A.
Energy decreases
B.
Energy remains the same
C.
Energy increases linearly
D.
Energy increases with the square of the amplitude
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Solution
The energy of a wave is proportional to the square of its amplitude, so if the amplitude increases, the energy increases with the square of the amplitude.
Correct Answer: D — Energy increases with the square of the amplitude
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Q. In a wave, if the amplitude is increased, what happens to the energy carried by the wave?
A.
Energy decreases
B.
Energy remains the same
C.
Energy increases linearly
D.
Energy increases with the square of the amplitude
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Solution
The energy carried by a wave is proportional to the square of its amplitude, so if the amplitude increases, the energy increases with the square of that increase.
Correct Answer: D — Energy increases with the square of the amplitude
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Q. In a wave, if the amplitude is increased, what happens to the energy of the wave?
A.
Energy decreases
B.
Energy remains the same
C.
Energy increases
D.
Energy becomes zero
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Solution
The energy of a wave is proportional to the square of its amplitude. Therefore, if the amplitude increases, the energy increases.
Correct Answer: C — Energy increases
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Q. In a wave, the distance between two consecutive crests is known as what?
A.
Amplitude
B.
Wavelength
C.
Frequency
D.
Period
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Solution
The distance between two consecutive crests in a wave is called the wavelength.
Correct Answer: B — Wavelength
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Q. In a Wheatstone bridge, if all resistances are equal, what is the condition for balance?
A.
Any configuration.
B.
R1 = R2 = R3 = R4.
C.
R1 + R2 = R3 + R4.
D.
R1/R2 = R3/R4.
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Solution
When all resistances are equal, the bridge is balanced regardless of the configuration.
Correct Answer: B — R1 = R2 = R3 = R4.
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Q. In a Wheatstone bridge, if one of the resistors is changed, how does it affect the balance condition?
A.
It does not affect the balance
B.
It always unbalances the bridge
C.
It can either balance or unbalance the bridge
D.
It only balances if the new resistor is equal
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Solution
Changing one resistor can either balance or unbalance the bridge depending on the new value relative to the others.
Correct Answer: C — It can either balance or unbalance the bridge
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Q. In a Wheatstone bridge, if P = 20Ω, Q = 30Ω, and R = 10Ω, what is the value of S for the bridge to be balanced?
A.
15Ω
B.
20Ω
C.
25Ω
D.
30Ω
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Solution
Using the balance condition P/Q = R/S, we find S = 15Ω.
Correct Answer: B — 20Ω
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Q. In a Wheatstone bridge, if R1 = 10Ω, R2 = 15Ω, and R3 = 30Ω, what is the value of R4 for the bridge to be balanced?
A.
20Ω
B.
25Ω
C.
30Ω
D.
35Ω
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Solution
Using the balance condition R1/R2 = R3/R4, we find R4 = (R2 * R3) / R1 = (15 * 30) / 10 = 45Ω.
Correct Answer: B — 25Ω
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Q. In a Wheatstone bridge, if R1 = 10Ω, R2 = 20Ω, and R3 = 30Ω, what is the value of R4 for the bridge to be balanced?
A.
15Ω
B.
20Ω
C.
25Ω
D.
30Ω
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Solution
Using the balance condition R1/R2 = R3/R4, we have 10/20 = 30/R4, which gives R4 = 20Ω.
Correct Answer: B — 20Ω
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Q. In a Wheatstone bridge, if R1 = 10Ω, R2 = 20Ω, R3 = 15Ω, what should R4 be for the bridge to be balanced?
A.
30Ω
B.
20Ω
C.
15Ω
D.
10Ω
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Solution
For balance, R1/R2 = R3/R4. Thus, 10/20 = 15/R4, giving R4 = 30Ω.
Correct Answer: B — 20Ω
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Q. In a Wheatstone bridge, if R1 = 1Ω, R2 = 2Ω, and R3 = 3Ω, what is the value of R4 for the bridge to be balanced?
A.
1.5Ω
B.
2Ω
C.
3Ω
D.
4Ω
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Solution
Using the balance condition R1/R2 = R3/R4, we have 1/2 = 3/R4. Solving gives R4 = 6Ω.
Correct Answer: D — 4Ω
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