Physics Syllabus (JEE Main)
Q. If the temperature of a material increases, what happens to its Young's modulus?
A.
Increases
B.
Decreases
C.
Remains constant
D.
Depends on the material
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Solution
Generally, the Young's modulus of materials decreases with an increase in temperature.
Correct Answer: B — Decreases
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Q. If the temperature of a metallic conductor increases, what happens to its resistivity?
A.
Increases
B.
Decreases
C.
Remains constant
D.
Becomes zero
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Solution
For metals, resistivity increases with temperature due to increased lattice vibrations.
Correct Answer: A — Increases
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Q. If the temperature of an ideal gas is doubled at constant volume, what happens to the average kinetic energy of the gas molecules?
A.
It remains the same.
B.
It doubles.
C.
It triples.
D.
It halves.
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Solution
The average kinetic energy of gas molecules is directly proportional to the absolute temperature. Therefore, if the temperature is doubled, the average kinetic energy also doubles.
Correct Answer: B — It doubles.
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Q. If the temperature of an ideal gas is doubled at constant volume, what happens to the pressure?
A.
It remains the same
B.
It doubles
C.
It triples
D.
It quadruples
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Solution
According to Gay-Lussac's law, at constant volume, the pressure of an ideal gas is directly proportional to its absolute temperature. Therefore, if the temperature is doubled, the pressure also doubles.
Correct Answer: B — It doubles
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Q. If the temperature of an ideal gas is doubled at constant volume, what happens to its pressure?
A.
It halves
B.
It remains the same
C.
It doubles
D.
It quadruples
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Solution
According to Gay-Lussac's law, pressure is directly proportional to temperature at constant volume, so it doubles.
Correct Answer: C — It doubles
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Q. If the temperature of an ideal gas is doubled while keeping the pressure constant, what happens to its volume?
A.
It halves
B.
It doubles
C.
It remains the same
D.
It quadruples
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Solution
According to Charles's Law, at constant pressure, the volume of an ideal gas is directly proportional to its temperature. Therefore, if the temperature doubles, the volume also doubles.
Correct Answer: B — It doubles
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Q. If the temperature of an ideal gas is doubled while keeping the volume constant, what happens to the pressure?
A.
It remains the same.
B.
It doubles.
C.
It triples.
D.
It halves.
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Solution
According to Gay-Lussac's law, if the volume is constant, the pressure of an ideal gas is directly proportional to its absolute temperature. Therefore, doubling the temperature doubles the pressure.
Correct Answer: B — It doubles.
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Q. If the temperature of an object increases, what happens to the rate of heat radiation from that object?
A.
Decreases
B.
Increases
C.
Remains constant
D.
Becomes zero
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Solution
According to Stefan-Boltzmann law, the rate of heat radiation increases with the fourth power of the temperature, so as the temperature increases, the rate of radiation also increases.
Correct Answer: B — Increases
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Q. If the temperature of an object increases, what happens to the rate of heat transfer by radiation?
A.
Decreases
B.
Increases
C.
Remains constant
D.
Becomes zero
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Solution
The rate of heat transfer by radiation increases with the fourth power of the absolute temperature, according to Stefan-Boltzmann law.
Correct Answer: B — Increases
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Q. If the temperature of an object is doubled, how does its thermal radiation change according to the Stefan-Boltzmann law?
A.
It doubles
B.
It quadruples
C.
It remains the same
D.
It increases eightfold
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Solution
According to the Stefan-Boltzmann law, if the temperature is doubled, the thermal radiation increases by a factor of 2^4 = 16, not quadruples.
Correct Answer: B — It quadruples
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Q. If the temperature of an object is doubled, how does the rate of heat radiation change?
A.
It doubles
B.
It quadruples
C.
It remains the same
D.
It halves
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Solution
According to the Stefan-Boltzmann law, if the temperature is doubled, the rate of heat radiation increases by a factor of 2^4 = 16.
Correct Answer: B — It quadruples
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Q. If the torque is doubled while keeping the distance constant, what happens to the force applied?
A.
It doubles
B.
It halves
C.
It remains the same
D.
It quadruples
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Solution
Torque = Force × Distance; if Torque is doubled and Distance is constant, Force must also double.
Correct Answer: A — It doubles
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Q. If the torque on a rotating object is doubled while the radius remains constant, what happens to the force applied?
A.
It doubles
B.
It halves
C.
It remains the same
D.
It quadruples
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Solution
If torque is doubled and radius remains constant, the force must also double to maintain the relationship τ = F × r.
Correct Answer: A — It doubles
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Q. If the torque on an object is zero, what can be said about the forces acting on it?
A.
The object is at rest.
B.
The net force is zero.
C.
The forces are balanced.
D.
The forces are acting along the same line.
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Solution
If the torque is zero, it means that the forces are acting along the same line, resulting in no rotational effect.
Correct Answer: D — The forces are acting along the same line.
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Q. If the torque on an object is zero, which of the following must be true?
A.
The net force is zero.
B.
The object is at rest.
C.
The forces are balanced.
D.
The line of action of the forces passes through the pivot.
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Solution
If the torque is zero, it means that the line of action of the forces passes through the pivot point.
Correct Answer: D — The line of action of the forces passes through the pivot.
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Q. If the total charge enclosed by a Gaussian surface is zero, what can be said about the electric field on that surface?
A.
It is zero everywhere
B.
It can be non-zero
C.
It is constant
D.
It is infinite
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Solution
If the total charge enclosed is zero, the electric field can still be non-zero at points on the surface due to external charges.
Correct Answer: B — It can be non-zero
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Q. If the total energy of a simple harmonic oscillator is 50 J and the mass is 2 kg, what is the maximum speed of the mass?
A.
5 m/s
B.
10 m/s
C.
15 m/s
D.
20 m/s
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Solution
Total energy (E) = (1/2)m(v_max)^2. Solving for v_max gives v_max = sqrt(2E/m) = sqrt(2*50/2) = 10 m/s.
Correct Answer: B — 10 m/s
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Q. If the total resistance in a Wheatstone bridge is 30Ω and the bridge is balanced, what is the current through the galvanometer?
A.
0A
B.
1A
C.
2A
D.
Depends on the voltage
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Solution
In a balanced Wheatstone bridge, the current through the galvanometer is zero.
Correct Answer: A — 0A
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Q. If the total resistance in a Wheatstone bridge is increased, what happens to the current in the circuit?
A.
It increases
B.
It decreases
C.
It remains the same
D.
It becomes zero
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Solution
According to Ohm's law, if the total resistance increases, the current in the circuit decreases.
Correct Answer: B — It decreases
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Q. If the true value of a measurement is 50 and the measured value is 48, what is the absolute error?
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Solution
Absolute error = |True value - Measured value| = |50 - 48| = 2.
Correct Answer: A — 2
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Q. If the true value of a measurement is 50.0 cm and a student records a value of 49.5 cm, what is the absolute error?
A.
0.5 cm
B.
0.0 cm
C.
0.5 m
D.
1.0 cm
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Solution
Absolute error = |True value - Measured value| = |50.0 - 49.5| = 0.5 cm.
Correct Answer: A — 0.5 cm
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Q. If the true value of a measurement is 50.0 cm and the measured value is 49.5 cm, what is the absolute error?
A.
0.5 cm
B.
1.0 cm
C.
0.1 cm
D.
0.2 cm
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Solution
Absolute error = |True value - Measured value| = |50.0 - 49.5| = 0.5 cm.
Correct Answer: A — 0.5 cm
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Q. If the true value of a measurement is 50.0 units and the measured value is 48.0 units, what is the percentage error?
A.
4.0%
B.
2.0%
C.
5.0%
D.
3.0%
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Solution
Percentage error = |(True value - Measured value) / True value| * 100 = |(50.0 - 48.0) / 50.0| * 100 = 4.0%.
Correct Answer: A — 4.0%
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Q. If the true value of a quantity is 100 and the measured value is 98, what is the percentage error?
A.
2%
B.
1%
C.
3%
D.
0.5%
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Solution
Percentage error = (|True value - Measured value| / True value) * 100 = (|100 - 98| / 100) * 100 = 2%.
Correct Answer: A — 2%
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Q. If the true value of a quantity is 200 and the measured value is 198, what is the percentage error?
A.
1%
B.
0.5%
C.
2%
D.
0.25%
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Solution
Percentage error = (|True value - Measured value| / True value) * 100 = (|200 - 198| / 200) * 100 = 1%.
Correct Answer: A — 1%
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Q. If the value of one of the resistances in a Wheatstone bridge is doubled, what effect does it have on the balance condition?
A.
It remains balanced
B.
It becomes unbalanced
C.
It depends on other resistances
D.
It cannot be determined
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Solution
Doubling one resistance will change the ratio, thus making the bridge unbalanced.
Correct Answer: B — It becomes unbalanced
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Q. If the value of one of the resistances in a Wheatstone bridge is increased, what effect does it have on the balance of the bridge?
A.
It remains balanced
B.
It becomes unbalanced
C.
It depends on the other resistances
D.
It becomes short-circuited
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Solution
Increasing one resistance will generally cause the bridge to become unbalanced.
Correct Answer: B — It becomes unbalanced
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Q. If the viscosity of a fluid is doubled, what happens to the flow rate through a constant diameter pipe?
A.
Doubles
B.
Halves
C.
Remains the same
D.
Increases fourfold
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Solution
If viscosity is doubled, the flow rate through a constant diameter pipe is halved.
Correct Answer: B — Halves
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Q. If the viscosity of a fluid is doubled, what happens to the flow rate through a pipe, assuming all other factors remain constant?
A.
Doubles
B.
Halves
C.
Remains the same
D.
Increases fourfold
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Solution
If viscosity is doubled, the flow rate through a pipe will halve, as flow rate is inversely proportional to viscosity.
Correct Answer: B — Halves
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Q. If the viscosity of a fluid is high, what does it imply about the fluid's flow?
A.
It flows easily
B.
It flows slowly
C.
It is incompressible
D.
It is a gas
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Solution
A high viscosity indicates that the fluid flows slowly.
Correct Answer: B — It flows slowly
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