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If the true value of a measurement is 50.0 cm and a student records a value of 4
If the true value of a measurement is 50.0 cm and a student records a value of 49.5 cm, what is the absolute error?
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Practice Questions
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Q1
If the true value of a measurement is 50.0 cm and a student records a value of 49.5 cm, what is the absolute error?
0.5 cm
0.0 cm
0.5 m
1.0 cm
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Absolute error = |True value - Measured value| = |50.0 - 49.5| = 0.5 cm.
Questions & Step-by-step Solutions
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Q
Q: If the true value of a measurement is 50.0 cm and a student records a value of 49.5 cm, what is the absolute error?
Solution:
Absolute error = |True value - Measured value| = |50.0 - 49.5| = 0.5 cm.
Steps: 5
Show Steps
Step 1: Identify the true value of the measurement, which is 50.0 cm.
Step 2: Identify the measured value recorded by the student, which is 49.5 cm.
Step 3: Subtract the measured value from the true value: 50.0 cm - 49.5 cm.
Step 4: Calculate the absolute value of the result from Step 3: |50.0 - 49.5|.
Step 5: The result is 0.5 cm, which is the absolute error.
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