Q. What is the force experienced by a current-carrying conductor of length L in a magnetic field B at an angle θ? (2023)
A.
F = BIL
B.
F = BIL sin(θ)
C.
F = BIL cos(θ)
D.
F = BIL²
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Solution
The force on a current-carrying conductor in a magnetic field is given by F = BIL sin(θ), where θ is the angle between the conductor and the magnetic field.
Correct Answer: B — F = BIL sin(θ)
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Q. What is the force on a charge moving in a magnetic field given by F = qvB sin(θ)? (2022)
A.
It is always zero
B.
It depends on the angle θ
C.
It is constant
D.
It is maximum when θ = 90°
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Solution
The force on a charge moving in a magnetic field is maximum when the angle θ between the velocity vector and the magnetic field is 90°, as sin(90°) = 1.
Correct Answer: D — It is maximum when θ = 90°
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Q. What is the force on a charge moving in a magnetic field given by the equation F = qvB sin(θ)? (2020)
A.
Charge times velocity
B.
Charge times magnetic field
C.
Charge times velocity times magnetic field times sine of angle
D.
Charge times sine of angle
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Solution
The force on a charge moving in a magnetic field is given by F = qvB sin(θ), where q is the charge, v is the velocity, B is the magnetic field strength, and θ is the angle between the velocity and the magnetic field.
Correct Answer: C — Charge times velocity times magnetic field times sine of angle
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Q. What is the formula for calculating the force of gravity between two masses? (2021)
A.
F = ma
B.
F = G(m1m2)/r²
C.
F = mv
D.
F = mgh
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Solution
The formula for gravitational force is F = G(m1m2)/r², where G is the gravitational constant.
Correct Answer: B — F = G(m1m2)/r²
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Q. What is the formula for calculating the total current in a parallel RLC circuit? (2023)
A.
I = V/R
B.
I = V/(1/R + 1/X)
C.
I = V/(R + X)
D.
I = V/R + V/X
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Solution
In a parallel RLC circuit, the total current is calculated using I = V/(1/R + 1/X), where X is the total reactance.
Correct Answer: B — I = V/(1/R + 1/X)
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Q. What is the formula for the average power consumed in an AC circuit with a phase angle φ? (2020)
A.
P = VI
B.
P = VI cos(φ)
C.
P = VI sin(φ)
D.
P = V²/R
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Solution
The average power P in an AC circuit is given by P = VI cos(φ), where φ is the phase angle.
Correct Answer: B — P = VI cos(φ)
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Q. What is the formula for the average power consumed in an AC circuit with a resistor? (2019)
A.
P = VI
B.
P = V²/R
C.
P = I²R
D.
All of the above
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Solution
The average power consumed in an AC circuit can be expressed as P = VI, P = V²/R, and P = I²R.
Correct Answer: D — All of the above
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Q. What is the formula for the resonant frequency of an RLC circuit? (2021)
A.
f = 1/(2π√(LC))
B.
f = R/(2πL)
C.
f = 1/(2πRC)
D.
f = 2π√(LC)
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Solution
The resonant frequency f of an RLC circuit is given by f = 1/(2π√(LC)).
Correct Answer: A — f = 1/(2π√(LC))
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Q. What is the formula for the total impedance in a parallel RLC circuit? (2023)
A.
1/Z = 1/Z1 + 1/Z2 + 1/Z3
B.
Z = R + jX
C.
Z = R
D.
.
X
.
Z = R + jωL - j/(ωC)
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Solution
The total impedance in a parallel circuit is given by 1/Z = 1/Z1 + 1/Z2 + 1/Z3.
Correct Answer: A — 1/Z = 1/Z1 + 1/Z2 + 1/Z3
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Q. What is the frequency of a pendulum that completes 30 oscillations in 60 seconds? (2017)
A.
0.5 Hz
B.
1 Hz
C.
2 Hz
D.
3 Hz
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Solution
Frequency f = number of oscillations / time = 30 / 60 = 0.5 Hz.
Correct Answer: B — 1 Hz
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Q. What is the frequency of a sound wave with a period of 0.01 seconds? (2014)
A.
100 Hz
B.
200 Hz
C.
50 Hz
D.
10 Hz
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Solution
Frequency = 1/Period = 1/0.01 s = 100 Hz.
Correct Answer: A — 100 Hz
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Q. What is the frequency of a tuning fork that vibrates 256 times in 2 seconds? (2019)
A.
128 Hz
B.
256 Hz
C.
512 Hz
D.
64 Hz
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Solution
Frequency (f) = Number of vibrations / Time = 256 / 2 = 128 Hz.
Correct Answer: A — 128 Hz
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Q. What is the frequency of a wave with a period of 0.01 s? (2020)
A.
100 Hz
B.
50 Hz
C.
200 Hz
D.
10 Hz
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Solution
Frequency f = 1/T = 1/0.01 s = 100 Hz.
Correct Answer: A — 100 Hz
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Q. What is the frequency of a wave with a period of 0.1 s? (2020)
A.
10 Hz
B.
5 Hz
C.
20 Hz
D.
15 Hz
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Solution
Frequency f = 1/T = 1/0.1 s = 10 Hz.
Correct Answer: A — 10 Hz
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Q. What is the frequency of a wave with a period of 0.2 seconds?
A.
5 Hz
B.
10 Hz
C.
20 Hz
D.
50 Hz
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Solution
Frequency (f) is the reciprocal of the period (T). Therefore, f = 1/T = 1/0.2 s = 5 Hz.
Correct Answer: B — 10 Hz
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Q. What is the frequency of a wave with a period of 0.5 seconds? (2019)
A.
2 Hz
B.
1 Hz
C.
0.5 Hz
D.
4 Hz
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Solution
Frequency (f) = 1/Period (T) = 1/0.5 s = 2 Hz.
Correct Answer: A — 2 Hz
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Q. What is the frequency of a wave with a speed of 300 m/s and a wavelength of 3 m? (2023)
A.
100 Hz
B.
150 Hz
C.
200 Hz
D.
250 Hz
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Solution
Frequency (f) = speed (v) / wavelength (λ) = 300 m/s / 3 m = 100 Hz.
Correct Answer: B — 150 Hz
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Q. What is the frequency of a wave with a wavelength of 2 m and a speed of 340 m/s?
A.
170 Hz
B.
340 Hz
C.
85 Hz
D.
420 Hz
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Solution
Frequency (f) is given by the formula f = speed / wavelength. Here, f = 340 m/s / 2 m = 170 Hz.
Correct Answer: A — 170 Hz
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Q. What is the gravitational field strength at a distance of 10 m from a mass of 100 kg? (G = 6.67 × 10^-11 N m²/kg²)
A.
6.67 × 10^-10 N/kg
B.
6.67 × 10^-9 N/kg
C.
6.67 × 10^-8 N/kg
D.
6.67 × 10^-7 N/kg
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Solution
g = G * M / r² = (6.67 × 10^-11) * (100) / (10²) = 6.67 × 10^-10 N/kg
Correct Answer: A — 6.67 × 10^-10 N/kg
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Q. What is the gravitational force acting on a 50 kg object at the surface of the Earth?
A.
490 N
B.
500 N
C.
510 N
D.
520 N
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Solution
Weight = mass * g = 50 kg * 9.8 m/s² = 490 N
Correct Answer: A — 490 N
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Q. What is the gravitational force acting on a 50 kg object on the surface of the Earth?
A.
490 N
B.
50 N
C.
5 N
D.
500 N
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Solution
Weight W = m * g = 50 kg * 9.8 m/s² = 490 N.
Correct Answer: A — 490 N
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Q. What is the gravitational force between two 1 kg masses placed 1 meter apart? (G = 6.67 × 10^-11 N m²/kg²)
A.
6.67 × 10^-11 N
B.
1.67 × 10^-10 N
C.
6.67 × 10^-10 N
D.
0 N
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Solution
F = G * (m1 * m2) / r² = (6.67 × 10^-11) * (1 * 1) / (1²) = 6.67 × 10^-11 N
Correct Answer: A — 6.67 × 10^-11 N
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Q. What is the gravitational force between two objects of mass 5 kg and 10 kg separated by a distance of 2 m? (G = 6.67 × 10^-11 N m²/kg²)
A.
1.67 × 10^-10 N
B.
1.25 × 10^-10 N
C.
1.00 × 10^-10 N
D.
2.00 × 10^-10 N
Show solution
Solution
Using the formula F = G * (m1 * m2) / r², we have F = (6.67 × 10^-11) * (5 * 10) / (2²) = 1.67 × 10^-10 N.
Correct Answer: A — 1.67 × 10^-10 N
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Q. What is the gravitational force between two objects of mass m1 and m2 separated by a distance r? (2021)
A.
G * (m1 * m2) / r^2
B.
G * (m1 + m2) / r^2
C.
G * (m1 - m2) / r^2
D.
G * (m1 * m2) * r^2
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Solution
The gravitational force is given by Newton's law of gravitation: F = G * (m1 * m2) / r^2.
Correct Answer: A — G * (m1 * m2) / r^2
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Q. What is the gravitational potential energy of a 10 kg mass at a height of 10 m?
A.
100 J
B.
200 J
C.
500 J
D.
1000 J
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Solution
Gravitational potential energy (PE) is given by PE = mgh. Here, PE = 10 kg * 9.81 m/s² * 10 m = 981 J.
Correct Answer: D — 1000 J
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Q. What is the gravitational potential energy of a 10 kg mass at a height of 5 m? (2019)
A.
50 J
B.
100 J
C.
150 J
D.
200 J
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Solution
Gravitational potential energy (PE) = m * g * h = 10 kg * 9.81 m/s² * 5 m = 490.5 J.
Correct Answer: B — 100 J
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Q. What is the gravitational potential energy of a 10 kg object at a height of 10 m?
A.
100 J
B.
200 J
C.
500 J
D.
1000 J
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Solution
Gravitational potential energy (PE) is given by the formula PE = mgh. Here, PE = 10 kg * 9.8 m/s² * 10 m = 980 J, which rounds to approximately 1000 J.
Correct Answer: B — 200 J
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Q. What is the gravitational potential energy of a 10 kg object at a height of 5 m? (g = 9.8 m/s²)
A.
49 J
B.
98 J
C.
245 J
D.
490 J
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Solution
Gravitational potential energy (PE) is given by PE = mgh. Here, m = 10 kg, g = 9.8 m/s², and h = 5 m. PE = 10 * 9.8 * 5 = 490 J.
Correct Answer: B — 98 J
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Q. What is the gravitational potential energy of a 2 kg object at a height of 10 m? (2023)
A.
20 J
B.
15 J
C.
10 J
D.
25 J
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Solution
Gravitational potential energy (PE) = mgh = 2 kg × 9.8 m/s² × 10 m = 196 J.
Correct Answer: A — 20 J
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Q. What is the gravitational potential energy of a 5 kg object at a height of 10 m?
A.
50 J
B.
100 J
C.
150 J
D.
200 J
Show solution
Solution
Gravitational potential energy (PE) = m * g * h = 5 kg * 9.8 m/s² * 10 m = 490 J.
Correct Answer: B — 100 J
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