Physics
Q. A 0.5 kg ball is thrown vertically upwards with a speed of 20 m/s. What is the maximum height it reaches?
A.
10 m
B.
20 m
C.
30 m
D.
40 m
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Solution
Using the formula h = v²/(2g), where v = 20 m/s and g = 9.8 m/s², h = (20)²/(2 * 9.8) ≈ 20.4 m, which rounds to 20 m.
Correct Answer: B — 20 m
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Q. A 1 kg ball is thrown vertically upwards with a velocity of 20 m/s. What is the maximum height it reaches? (g = 10 m/s²) (2021)
A.
20 m
B.
30 m
C.
40 m
D.
10 m
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Solution
Using the formula h = v² / (2g) = (20 m/s)² / (2 × 10 m/s²) = 20 m.
Correct Answer: A — 20 m
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Q. A 1 kg block of ice at 0°C is placed in 2 kg of water at 80°C. What will be the final temperature of the mixture? (Assume no heat loss to the surroundings) (2019)
A.
0°C
B.
40°C
C.
60°C
D.
80°C
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Solution
Using the principle of conservation of energy, the heat lost by water equals the heat gained by ice. The final temperature will be 0°C as the ice will melt.
Correct Answer: B — 40°C
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Q. A 1 kg block of metal at 100°C is placed in 2 kg of water at 20°C. Assuming no heat loss to the surroundings, what is the final temperature of the system? (Specific heat of water = 4.18 kJ/kg°C, specific heat of metal = 0.9 kJ/kg°C) (2020)
A.
25°C
B.
30°C
C.
35°C
D.
40°C
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Solution
Using the principle of conservation of energy, set heat lost by metal equal to heat gained by water to find the final temperature.
Correct Answer: C — 35°C
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Q. A 1 kg block of metal at 100°C is placed in 2 kg of water at 20°C. What is the final temperature of the system? (Specific heat of water = 4.18 J/g°C, specific heat of metal = 0.9 J/g°C) (2021)
A.
25°C
B.
30°C
C.
35°C
D.
40°C
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Solution
Using conservation of energy: m1*c1*(T_initial - T_final) = m2*c2*(T_final - T_initial). Solving gives T_final = 35°C.
Correct Answer: C — 35°C
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Q. A 10 kg block is pushed with a force of 50 N. What is its acceleration? (2023)
A.
2 m/s²
B.
5 m/s²
C.
10 m/s²
D.
15 m/s²
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Solution
Using Newton's second law, F = ma, we have a = F/m = 50 N / 10 kg = 5 m/s².
Correct Answer: B — 5 m/s²
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Q. A 10 kg object is dropped from a height of 20 m. What is its potential energy at the top? (g = 9.8 m/s²) (1960)
A.
196 J
B.
98 J
C.
294 J
D.
490 J
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Solution
Potential Energy (PE) = mgh = 10 kg × 9.8 m/s² × 20 m = 1960 J.
Correct Answer: C — 294 J
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Q. A 10 kg object is lifted to a height of 2 m. What is the work done against gravity? (g = 9.8 m/s²)
A.
196 J
B.
98 J
C.
20 J
D.
39.2 J
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Solution
Work done (W) = m × g × h = 10 kg × 9.8 m/s² × 2 m = 196 J.
Correct Answer: A — 196 J
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Q. A 10 kg object is subjected to a net force of 30 N. What is its acceleration? (2022)
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
5 m/s²
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Solution
Using F = ma, acceleration a = F/m = 30 N / 10 kg = 3 m/s².
Correct Answer: B — 3 m/s²
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Q. A 10 N force is applied to move an object 3 m. What is the work done if the force is applied at an angle of 60 degrees to the direction of motion?
A.
15 J
B.
30 J
C.
25 J
D.
20 J
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Solution
Work done = Force × Distance × cos(θ) = 10 N × 3 m × cos(60°) = 10 N × 3 m × 0.5 = 15 J
Correct Answer: A — 15 J
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Q. A 100 g piece of metal at 100°C is placed in 200 g of water at 20°C. What will be the final temperature of the system? (Specific heat of water = 4.2 J/g°C, specific heat of metal = 0.5 J/g°C) (2023)
A.
30°C
B.
40°C
C.
50°C
D.
60°C
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Solution
Using the heat transfer equation, we can find the final temperature to be 50°C.
Correct Answer: C — 50°C
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Q. A 100 W bulb is connected to a 220 V supply. What is the current flowing through the bulb?
A.
0.45 A
B.
1.0 A
C.
2.2 A
D.
2.5 A
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Solution
Using the formula P = VI, where P = 100 W and V = 220 V, the current I = P/V = 100/220 ≈ 0.45 A.
Correct Answer: A — 0.45 A
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Q. A 100 W bulb is used for 5 hours. How much energy does it consume? (2016)
A.
500 Wh
B.
1000 Wh
C.
200 Wh
D.
250 Wh
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Solution
Energy consumed = Power × Time = 100 W × 5 h = 500 Wh.
Correct Answer: A — 500 Wh
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Q. A 1000 kg car is moving at a speed of 15 m/s. What is its kinetic energy?
A.
112,500 J
B.
75,000 J
C.
50,000 J
D.
25,000 J
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Solution
Kinetic Energy = 0.5 * m * v² = 0.5 * 1000 kg * (15 m/s)² = 112,500 J.
Correct Answer: A — 112,500 J
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Q. A 1000 kg car is moving at a speed of 36 km/h. What is its kinetic energy? (1 km/h = 1/3.6 m/s) (2000)
A.
500 J
B.
1000 J
C.
2000 J
D.
5000 J
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Solution
First convert speed: 36 km/h = 10 m/s. KE = 0.5 × m × v² = 0.5 × 1000 kg × (10 m/s)² = 0.5 × 1000 × 100 = 50000 J.
Correct Answer: C — 2000 J
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Q. A 100W bulb operates at 220V. What is the resistance of the bulb? (2021)
A.
484Ω
B.
220Ω
C.
110Ω
D.
100Ω
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Solution
Using P = V^2/R, we rearrange to find R = V^2/P = (220V)^2 / 100W = 484Ω.
Correct Answer: A — 484Ω
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Q. A 12 kg object is pushed with a force of 36 N. What is its acceleration? (2023)
A.
1 m/s²
B.
2 m/s²
C.
3 m/s²
D.
4 m/s²
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Solution
Using F = ma, we find a = F/m = 36 N / 12 kg = 3 m/s².
Correct Answer: C — 3 m/s²
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Q. A 12V battery is connected across a 4Ω resistor. What is the current flowing through the resistor? (2020)
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Solution
Using Ohm's law, I = V/R = 12V / 4Ω = 3A.
Correct Answer: A — 2A
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Q. A 12V battery is connected to a resistor of 4Ω. What is the current flowing through the circuit? (2022)
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Solution
Using Ohm's law, I = V/R = 12V / 4Ω = 3A.
Correct Answer: A — 2A
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Q. A 15 kg object is dropped from a height. What is the force acting on it due to gravity? (2023)
A.
15 N
B.
30 N
C.
45 N
D.
150 N
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Solution
Using F = mg, where g = 9.8 m/s², we have F = 15 kg * 9.8 m/s² = 147 N, which rounds to 150 N.
Correct Answer: B — 30 N
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Q. A 15 kg object is lifted to a height of 4 m. What is the work done against gravity? (g = 9.8 m/s²) (2021)
A.
588 J
B.
5880 J
C.
392 J
D.
294 J
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Solution
Work = mgh = 15 kg * 9.8 m/s² * 4 m = 588 J.
Correct Answer: A — 588 J
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Q. A 15 kg object is moving with a velocity of 4 m/s. What is its momentum? (2019)
A.
60 kg m/s
B.
30 kg m/s
C.
45 kg m/s
D.
75 kg m/s
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Solution
Momentum = mass × velocity = 15 kg × 4 m/s = 60 kg m/s.
Correct Answer: A — 60 kg m/s
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Q. A 2 kg block of ice at 0°C is converted to water at 0°C. How much heat is absorbed if the latent heat of fusion of ice is 334,000 J/kg?
A.
668,000 J
B.
334,000 J
C.
167,000 J
D.
500,000 J
Show solution
Solution
Heat absorbed = mass * latent heat = 2 kg * 334,000 J/kg = 668,000 J.
Correct Answer: A — 668,000 J
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Q. A 2 kg block of metal at 100°C is placed in 1 kg of water at 20°C. What is the final temperature of the system? (Specific heat of water = 4.2 J/g°C, specific heat of metal = 0.9 J/g°C) (2021)
A.
30°C
B.
40°C
C.
50°C
D.
60°C
Show solution
Solution
Using the heat transfer equation, the final temperature can be calculated to be 50°C.
Correct Answer: C — 50°C
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Q. A 2 kg object is lifted to a height of 5 m. What is the potential energy gained by the object? (2022)
A.
10 J
B.
20 J
C.
30 J
D.
40 J
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Solution
Potential Energy = mass × g × height = 2 kg × 10 m/s² × 5 m = 100 J
Correct Answer: B — 20 J
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Q. A 2 kg object is lifted to a height of 5 m. What is the potential energy gained by the object? (g = 9.8 m/s²)
A.
98 J
B.
19.6 J
C.
39.2 J
D.
49 J
Show solution
Solution
Potential Energy = mass × g × height = 2 kg × 9.8 m/s² × 5 m = 98 J
Correct Answer: A — 98 J
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Q. A 2 kg object is subjected to a net force of 8 N. What is its acceleration? (2020)
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
5 m/s²
Show solution
Solution
Using F = ma, a = F/m = 8 N / 2 kg = 4 m/s².
Correct Answer: C — 4 m/s²
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Q. A 20 kg cart is pulled with a force of 80 N. What is the acceleration of the cart? (2023)
A.
2 m/s²
B.
4 m/s²
C.
6 m/s²
D.
8 m/s²
Show solution
Solution
Using F = ma, we find a = F/m = 80 N / 20 kg = 4 m/s².
Correct Answer: B — 4 m/s²
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Q. A 25 kg object is acted upon by a force of 100 N. What is its acceleration? (2023)
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
5 m/s²
Show solution
Solution
Using F = ma, we find a = F/m = 100 N / 25 kg = 4 m/s².
Correct Answer: D — 5 m/s²
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Q. A 3 kg object is dropped from a height of 10 m. What is the potential energy at the top? (2022)
A.
30 J
B.
60 J
C.
90 J
D.
120 J
Show solution
Solution
Potential Energy = mass × g × height = 3 kg × 10 m/s² × 10 m = 300 J
Correct Answer: C — 90 J
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