Q. What is the mass of 0.5 moles of NaCl?
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A.
29 g
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B.
58 g
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C.
14 g
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D.
0.5 g
Solution
Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol. Mass = moles x molar mass = 0.5 moles x 58.5 g/mol = 29.25 g.
Correct Answer: A — 29 g
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Q. What is the mass of 0.5 moles of sodium chloride (NaCl)?
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A.
29 g
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B.
35 g
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C.
58 g
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D.
70 g
Solution
The molar mass of NaCl is 58 g/mol. Therefore, 0.5 moles of NaCl = 0.5 x 58 g = 29 g.
Correct Answer: C — 58 g
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Q. What is the mass of 0.75 moles of sulfuric acid (H2SO4)?
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A.
75 g
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B.
98 g
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C.
147 g
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D.
50 g
Solution
Molar mass of H2SO4 = 2*1 + 32 + 4*16 = 98 g/mol. Mass = moles x molar mass = 0.75 moles x 98 g/mol = 73.5 g.
Correct Answer: B — 98 g
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Q. What is the mass of 1 mole of water (H2O)?
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A.
18 g
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B.
16 g
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C.
20 g
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D.
22 g
Solution
The molar mass of water (H2O) is 18 g/mol (2*1 for H + 16 for O).
Correct Answer: A — 18 g
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Q. What is the mass of 2 moles of carbon dioxide (CO2)?
-
A.
44 g
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B.
22 g
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C.
88 g
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D.
66 g
Solution
The molar mass of CO2 is 12 g/mol (C) + 16 g/mol x 2 (O) = 44 g/mol. Therefore, 2 moles of CO2 weigh 2 x 44 g = 88 g.
Correct Answer: A — 44 g
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Q. What is the mass of 2 moles of sulfuric acid (H2SO4)?
-
A.
98 g
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B.
196 g
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C.
294 g
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D.
392 g
Solution
Molar mass of H2SO4 = 2*1 + 32 + 4*16 = 98 g/mol. Mass = 2 moles x 98 g/mol = 196 g.
Correct Answer: B — 196 g
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Q. What is the mass of 3 moles of carbon dioxide (CO2)?
-
A.
44 g
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B.
66 g
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C.
132 g
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D.
22 g
Solution
The molar mass of CO2 is 12 g/mol (C) + 16 g/mol x 2 (O) = 44 g/mol. Therefore, 3 moles of CO2 weigh 3 x 44 g = 132 g.
Correct Answer: A — 44 g
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Q. What is the mass of 3 moles of NaCl?
-
A.
87 g
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B.
58.5 g
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C.
174 g
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D.
3 g
Solution
Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol. Mass = moles x molar mass = 3 moles x 58.5 g/mol = 174 g.
Correct Answer: C — 174 g
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Q. What is the mass of 3 moles of sulfuric acid (H2SO4)?
-
A.
98 g
-
B.
196 g
-
C.
294 g
-
D.
392 g
Solution
Molar mass of H2SO4 = 2*1 + 32 + 4*16 = 98 g/mol. Mass = 3 moles x 98 g/mol = 294 g.
Correct Answer: B — 196 g
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Q. What is the mass of KCl produced when 10 g of K reacts with excess Cl2?
-
A.
74.5 g
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B.
10 g
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C.
20 g
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D.
30 g
Solution
10 g of K = 0.25 moles. K + Cl2 → KCl, so 0.25 moles of KCl = 0.25 * 74.5 g = 18.625 g.
Correct Answer: A — 74.5 g
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Q. What is the mass of water produced when 2 moles of hydrogen react with 1 mole of oxygen?
-
A.
18 g
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B.
36 g
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C.
54 g
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D.
9 g
Solution
2 moles of H2 produce 2 moles of H2O. Mass of H2O = 2 moles * 18 g/mole = 36 g.
Correct Answer: A — 18 g
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Q. What is the mass percent of a solution containing 20 g of NaCl in 180 g of water?
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A.
10%
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B.
20%
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C.
25%
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D.
15%
Solution
Mass percent = (mass of solute / total mass) x 100 = (20 g / (20 g + 180 g)) x 100 = 10%.
Correct Answer: A — 10%
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Q. What is the mass percent of a solution containing 20 g of solute in 180 g of solution?
-
A.
10%
-
B.
20%
-
C.
25%
-
D.
15%
Solution
Mass percent = (mass of solute / mass of solution) x 100 = (20 g / 200 g) x 100 = 10%.
Correct Answer: B — 20%
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Q. What is the mass percent of a solution containing 20 g of solute in 200 g of solution?
-
A.
10%
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B.
20%
-
C.
5%
-
D.
15%
Solution
Mass percent = (mass of solute / mass of solution) × 100 = (20 g / 200 g) × 100 = 10%.
Correct Answer: B — 20%
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Q. What is the maximum number of electrons in the n=2 shell?
Solution
The maximum number of electrons in the n=2 shell is 2(2^2) = 8.
Correct Answer: B — 4
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Q. What is the maximum number of electrons that can be accommodated in a shell with principal quantum number n=5?
Solution
The maximum number of electrons in a shell is given by 2n^2. For n=5, it is 2(5^2) = 50.
Correct Answer: C — 32
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Q. What is the maximum number of electrons that can be accommodated in a shell with quantum number n=4?
Solution
The maximum number of electrons in a shell is given by 2n^2. For n=4, it is 2(4^2) = 32.
Correct Answer: C — 32
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Q. What is the maximum number of electrons that can be accommodated in a shell with n=3?
Solution
The maximum number of electrons in a shell is given by 2n^2. For n=3, it is 2(3^2) = 18.
Correct Answer: B — 18
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Q. What is the maximum number of electrons that can be accommodated in a subshell with the quantum number l = 2?
Solution
The maximum number of electrons in a subshell is given by the formula 2(2l + 1). For l = 2, it is 2(2*2 + 1) = 10.
Correct Answer: C — 10
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Q. What is the maximum number of electrons that can be accommodated in the n=2 shell?
Solution
The maximum number of electrons in a shell is given by 2n^2. For n=2, this is 2(2^2) = 8.
Correct Answer: B — 4
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Q. What is the maximum number of electrons that can be accommodated in the n=5 shell?
Solution
The maximum number of electrons in a shell is given by 2n^2. For n=5, it is 2(5^2) = 50.
Correct Answer: C — 32
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Q. What is the maximum number of electrons that can occupy a p subshell?
Solution
A p subshell can hold a maximum of 6 electrons.
Correct Answer: B — 6
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Q. What is the maximum number of electrons that can occupy a single orbital?
Solution
A single orbital can hold a maximum of 2 electrons, with opposite spins.
Correct Answer: B — 2
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Q. What is the maximum number of electrons that can occupy a single p-orbital?
Solution
A single p-orbital can hold a maximum of 2 electrons.
Correct Answer: A — 2
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Q. What is the maximum number of electrons that can occupy a subshell with the quantum numbers n=3 and l=2?
Solution
The maximum number of electrons in a subshell is given by the formula 2(2l + 1). For l=2, this gives 2(2*2 + 1) = 10.
Correct Answer: C — 10
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Q. What is the maximum number of electrons that can occupy a subshell with the quantum number l = 2?
Solution
The maximum number of electrons in a subshell is given by the formula 2(2l + 1). For l = 2, this gives 2(2*2 + 1) = 10.
Correct Answer: C — 10
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Q. What is the maximum number of electrons that can occupy the 3rd energy level?
Solution
The maximum number of electrons in an energy level is given by the formula 2n^2. For n=3, it is 2(3^2) = 18.
Correct Answer: C — 18
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Q. What is the maximum number of electrons that can occupy the n=3 shell?
Solution
The maximum number of electrons in a shell is given by the formula 2n^2. For n=3, it is 2(3^2) = 18.
Correct Answer: C — 18
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Q. What is the maximum number of orbitals in a subshell where l = 1?
Solution
For l=1, the number of orbitals is given by 2l + 1 = 3.
Correct Answer: B — 3
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Q. What is the maximum number of orbitals in a subshell with l = 3?
Solution
The number of orbitals in a subshell is given by 2l + 1. For l = 3, it is 2*3 + 1 = 7.
Correct Answer: C — 7
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