First, find the equivalent resistance: 1/R_eq = 1/4 + 1/8 = 3/8, so R_eq = 8/3Ω. Then, I = V/R_eq = 24V / (8/3)Ω = 9A.

First, find the equivalent resistance: 1/R_eq = 1/5 + 1/10 = 3/10, R_eq = 10/3Ω. Then, I = V/R_eq = 20V / (10/3)Ω = 6A.

Using Ohm's law, I = V/R = 9V / 3Ω = 3A.

Power is given by P = V²/R = (9V)² / 3Ω = 81V² / 3Ω = 27W.

Power P = V²/R = (9V)² / 3Ω = 81 / 3 = 27W.

Power is given by P = I²R. If I is doubled, P becomes (2I)²R = 4I²R, which means power quadruples.

Power is given by P = I²R. If I is doubled, P becomes (2I)²R = 4I²R, which is quadrupled.

According to Ohm's law, I = V/R. If R is halved, I will double.

According to Ohm's law, I = V/R. If V is doubled, I also doubles.

In a damped harmonic oscillator, the amplitude decreases over time due to energy loss.

Decreasing the distance between the slits increases the diffraction effect, causing the central maximum to become wider.

The central maximum has the maximum intensity because all light waves arrive in phase at this point, leading to constructive interference.

Fringe separation (β) = λD/d = (500 x 10^-9 m)(1 m)/(0.1 x 10^-3 m) = 0.5 mm.

Fringe width (β) is given by β = λD/d. If λ is halved, β will also be halved.

In a generator, mechanical energy is converted into electrical energy through the process of electromagnetic induction.

In a generator, mechanical energy is converted into electrical energy through the process of electromagnetic induction.

Frequency (f) = (1/2π)√(k/m). If mass (m) is doubled, frequency decreases.

An alpha particle consists of 2 protons and 2 neutrons, so the atomic number decreases by 2.

First, find the equivalent resistance: 1/R_eq = 1/6 + 1/3 = 1/2, so R_eq = 2Ω. Then, I = V/R_eq = 12V / 2Ω = 6A.

Using the formula 1/R_eq = 1/R1 + 1/R2, we get 1/R_eq = 1/6 + 1/3 = 1/6 + 2/6 = 3/6, thus R_eq = 2Ω.

1/R_eq = 1/4 + 1/8 = 2/8 + 1/8 = 3/8, so R_eq = 8/3Ω ≈ 2.67Ω.

Y = 1/R + j(ωC - 1/ωL); calculate Y for given values.

Quality factor Q = (1/R) * √(L/C) = (1/50) * √(0.2/50e-6) = 2.

At resonance, total current I = V/R. Calculate using V = 10V.

Total admittance Y = 1/R + j(ωC - 1/ωL). Calculate Y using given values.

In a purely capacitive circuit, the current leads the voltage by 90°.

In a purely capacitive circuit, the current leads the voltage by 90 degrees.

f0 = 1 / (2π√(LC)) = 1 / (2π√(0.1 × 100 × 10^-6)) = 159.15 Hz.

Resonant frequency f₀ = 1 / (2π√(LC)) = 1 / (2π√(0.1 * 100e-6)) = 159.15 Hz.

If inductive reactance (XL) is greater than capacitive reactance (XC), the circuit is inductive.