Kinematics
Q. A ball is thrown upwards with a speed of 20 m/s. How long will it take to reach the maximum height? (Take g = 10 m/s²) (2023)
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A.
1 s
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B.
2 s
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C.
3 s
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D.
4 s
Solution
Time to reach maximum height = initial velocity / g = 20 / 10 = 2 s.
Correct Answer: B — 2 s
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Q. A ball is thrown vertically upwards with a speed of 15 m/s. How high will it rise before coming to a stop? (2023)
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A.
11.25 m
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B.
15 m
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C.
22.5 m
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D.
30 m
Solution
Using the formula: height = (initial velocity^2) / (2 * g), where g = 9.8 m/s². Height = (15^2) / (2 * 9.8) = 11.25 m.
Correct Answer: A — 11.25 m
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Q. A car moving at 30 m/s applies brakes and comes to a stop in 6 seconds. What is the distance covered during braking? (2023)
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A.
90 m
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B.
120 m
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C.
150 m
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D.
180 m
Solution
Using the formula: distance = initial velocity * time + 0.5 * acceleration * time^2. Here, acceleration = (0 - 30) / 6 = -5 m/s². Distance = 30 * 6 + 0.5 * (-5) * 6^2 = 180 - 90 = 90 m.
Correct Answer: B — 120 m
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Q. A cyclist travels at a speed of 10 m/s for 5 seconds. What distance does he cover? (2023)
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A.
25 m
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B.
50 m
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C.
75 m
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D.
100 m
Solution
Distance = speed * time = 10 m/s * 5 s = 50 m.
Correct Answer: B — 50 m
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Q. A stone is thrown horizontally from a height of 45 m. How long will it take to hit the ground? (Take g = 10 m/s²) (2023)
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A.
3 s
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B.
4.5 s
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C.
5 s
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D.
6 s
Solution
Using h = 0.5 * g * t^2, we have 45 = 0.5 * 10 * t^2. Solving gives t^2 = 9, so t = 3 s.
Correct Answer: A — 3 s
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Q. A train moving at 72 km/h applies brakes and comes to a stop in 5 seconds. What is the deceleration? (2023)
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A.
2 m/s²
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B.
3 m/s²
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C.
4 m/s²
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D.
5 m/s²
Solution
First convert speed to m/s: 72 km/h = 20 m/s. Deceleration = (final velocity - initial velocity) / time = (0 - 20) / 5 = -4 m/s².
Correct Answer: C — 4 m/s²
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Q. A vehicle travels with a uniform speed of 60 km/h. How far will it travel in 2 hours? (2023)
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A.
80 km
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B.
100 km
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C.
120 km
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D.
140 km
Solution
Distance = speed * time = 60 km/h * 2 h = 120 km.
Correct Answer: C — 120 km
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Q. An object is dropped from a height of 80 m. How long will it take to reach the ground? (Take g = 10 m/s²) (2023)
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A.
4 s
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B.
8 s
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C.
10 s
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D.
12 s
Solution
Using the formula: h = 0.5 * g * t^2. Rearranging gives t = sqrt(2h/g) = sqrt(2*80/10) = sqrt(16) = 4 s.
Correct Answer: B — 8 s
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