Q. A train is moving at 72 km/h and passes a platform in 30 seconds. What is the length of the platform if the train is 200 meters long?
A.
200 m
B.
300 m
C.
400 m
D.
500 m
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Solution
Speed in m/s = 72 * (1000/3600) = 20 m/s. Distance = Speed × Time = 20 m/s × 30 s = 600 m. Length of platform = 600 m - 200 m = 400 m.
Correct Answer: B — 300 m
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Q. A train is moving at 90 km/h and a bird flies at 45 km/h in the opposite direction. What is the speed of the bird relative to the train?
A.
135 km/h
B.
45 km/h
C.
90 km/h
D.
135 km/h
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Solution
Relative speed = Speed of train + Speed of bird = 90 km/h + 45 km/h = 135 km/h.
Correct Answer: A — 135 km/h
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Q. A train leaves a station and travels at 90 km/h. Another train leaves the same station 30 minutes later and travels at 120 km/h. How far from the station will they meet?
A.
90 km
B.
120 km
C.
150 km
D.
180 km
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Solution
Let the distance be d. Time taken by first train = d/90. Time taken by second train = d/120. Setting up the equation gives d = 150 km.
Correct Answer: C — 150 km
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Q. A train leaves a station and travels at a speed of 80 km/h. How far will it travel in 3 hours? (2022)
A.
200 km
B.
240 km
C.
260 km
D.
300 km
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Solution
Distance = Speed × Time = 80 km/h × 3 h = 240 km.
Correct Answer: B — 240 km
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Q. A train leaves a station and travels at a speed of 90 km/h. How far will it travel in 2.5 hours?
A.
200 km
B.
225 km
C.
250 km
D.
300 km
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Solution
Distance = speed × time = 90 km/h × 2.5 h = 225 km.
Correct Answer: B — 225 km
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Q. A train leaves a station and travels at a speed of 90 km/h. How long will it take to travel 270 km?
A.
2 hours
B.
3 hours
C.
4 hours
D.
5 hours
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Solution
Time = Distance / Speed. Here, time = 270 km / 90 km/h = 3 hours.
Correct Answer: B — 3 hours
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Q. A train leaves a station at 2 PM traveling at 80 km/h. If it travels for 3 hours, at what time will it arrive at the next station? (2022)
A.
4 PM
B.
5 PM
C.
6 PM
D.
7 PM
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Solution
Departure time = 2 PM, travel time = 3 hours. Arrival time = 2 PM + 3 hours = 5 PM.
Correct Answer: C — 6 PM
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Q. A train leaves a station at 70 km/h. Another train leaves the same station 30 minutes later at 90 km/h. How far from the station will they meet?
A.
70 km
B.
90 km
C.
100 km
D.
110 km
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Solution
Let the distance be d. Time taken by first train = d/70, second train = d/90. They meet when d/70 = d/90 + 0.5. Solving gives d = 100 km.
Correct Answer: C — 100 km
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Q. A train leaves a station at 80 km/h and another train leaves the same station 30 minutes later at 100 km/h. How far from the station will they meet?
A.
100 km
B.
120 km
C.
150 km
D.
180 km
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Solution
Let the time taken by the first train be t hours. Distance = speed * time. 80t = 100(t - 0.5). Solving gives t = 2 hours, so distance = 80 * 2 = 160 km.
Correct Answer: B — 120 km
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Q. A train moving at 72 km/h applies brakes and comes to a stop in 10 seconds. What is the acceleration of the train?
A.
-2 m/s²
B.
-3 m/s²
C.
-4 m/s²
D.
-5 m/s²
Show solution
Solution
First convert speed to m/s: 72 km/h = 20 m/s. Using the formula: a = (v - u) / t = (0 - 20) / 10 = -2 m/s².
Correct Answer: C — -4 m/s²
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Q. A train moving at 72 km/h applies brakes and comes to a stop in 5 seconds. What is the deceleration? (2023)
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
5 m/s²
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Solution
First convert speed to m/s: 72 km/h = 20 m/s. Deceleration = (final velocity - initial velocity) / time = (0 - 20) / 5 = -4 m/s².
Correct Answer: C — 4 m/s²
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Q. A train moving at 72 km/h applies brakes and comes to a stop in 5 seconds. What is the acceleration of the train?
A.
-4 m/s²
B.
-5 m/s²
C.
-6 m/s²
D.
-7 m/s²
Show solution
Solution
First convert speed to m/s: 72 km/h = 20 m/s. Using the formula: acceleration = (final velocity - initial velocity) / time = (0 - 20) / 5 = -4 m/s².
Correct Answer: B — -5 m/s²
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Q. A train moving at 72 km/h overtakes a man walking at 6 km/h in the same direction. How fast does the train appear to be moving to the man?
A.
66 km/h
B.
72 km/h
C.
78 km/h
D.
84 km/h
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Solution
Relative speed = Speed of train - Speed of man = 72 km/h - 6 km/h = 66 km/h.
Correct Answer: A — 66 km/h
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Q. A train moving at 72 km/h passes a man walking at 6 km/h in the same direction. How fast does the train appear to be moving to the man?
A.
66 km/h
B.
72 km/h
C.
78 km/h
D.
84 km/h
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Solution
Relative speed = Speed of train - Speed of man = 72 km/h - 6 km/h = 66 km/h.
Correct Answer: A — 66 km/h
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Q. A train moving at 72 km/h passes a platform 300 m long. How long does it take to cross the platform completely?
A.
10 seconds
B.
15 seconds
C.
20 seconds
D.
25 seconds
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Solution
Total distance = Length of train + Length of platform. If length of train is L, time = (L + 300)/20 m/s. Assuming L = 300 m, time = (300 + 300)/20 = 30 seconds.
Correct Answer: B — 15 seconds
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Q. A train moving at a speed of 72 km/h applies brakes and comes to a stop in 5 seconds. What is the acceleration of the train?
A.
-4 m/s²
B.
-2 m/s²
C.
-3 m/s²
D.
-1 m/s²
Show solution
Solution
First, convert speed to m/s: 72 km/h = 20 m/s. Using a = (v - u)/t = (0 - 20)/5 = -4 m/s².
Correct Answer: A — -4 m/s²
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Q. A train moving with a speed of 60 km/h applies brakes and comes to a stop in 5 seconds. What is the magnitude of its acceleration?
A.
-3 m/s²
B.
-2 m/s²
C.
-1 m/s²
D.
-4 m/s²
Show solution
Solution
First, convert speed to m/s: 60 km/h = 60/3.6 = 16.67 m/s. Using the formula: acceleration = (final velocity - initial velocity) / time = (0 - 16.67) / 5 = -3.33 m/s², approximately -3 m/s².
Correct Answer: A — -3 m/s²
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Q. A train moving with a speed of 72 km/h applies brakes and comes to a stop in 10 seconds. What is the magnitude of its acceleration?
A.
-2 m/s²
B.
-3 m/s²
C.
-4 m/s²
D.
-5 m/s²
Show solution
Solution
First convert speed to m/s: 72 km/h = 20 m/s. Using the formula: acceleration = (final velocity - initial velocity) / time = (0 - 20) / 10 = -2 m/s².
Correct Answer: C — -4 m/s²
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Q. A train moving with a speed of 72 km/h applies brakes and comes to a stop in 10 seconds. What is the acceleration of the train?
A.
-2 m/s²
B.
-3 m/s²
C.
-4 m/s²
D.
-5 m/s²
Show solution
Solution
First convert speed to m/s: 72 km/h = 20 m/s. Using the formula: acceleration = (final velocity - initial velocity) / time = (0 - 20) / 10 = -2 m/s².
Correct Answer: B — -3 m/s²
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Q. A train of mass 1000 kg is moving with a velocity of 36 km/h. What is its kinetic energy?
A.
500 J
B.
1000 J
C.
1800 J
D.
2000 J
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Solution
First convert velocity to m/s: 36 km/h = 10 m/s. K.E. = (1/2)mv² = (1/2)(1000 kg)(10 m/s)² = 50000 J.
Correct Answer: C — 1800 J
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Q. A train starts from rest and accelerates uniformly at 2 m/s². What is its speed after 10 seconds? (2021)
A.
10 m/s
B.
20 m/s
C.
30 m/s
D.
40 m/s
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Solution
Using the formula: final velocity = initial velocity + acceleration * time. Final velocity = 0 + 2 * 10 = 20 m/s.
Correct Answer: B — 20 m/s
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Q. A train travels 120 km at a speed of 60 km/h and then 180 km at 90 km/h. What is the average speed for the entire journey? (2019)
A.
72 km/h
B.
75 km/h
C.
80 km/h
D.
85 km/h
Show solution
Solution
Total time = (120/60) + (180/90) = 2 + 2 = 4 hours. Total distance = 120 + 180 = 300 km. Average speed = Total distance / Total time = 300/4 = 75 km/h.
Correct Answer: C — 80 km/h
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Q. A train travels 120 km at a speed of 60 km/h. How long does it take to complete the journey?
A.
1 hour
B.
1.5 hours
C.
2 hours
D.
2.5 hours
Show solution
Solution
Time = Distance / Speed = 120 km / 60 km/h = 2 hours.
Correct Answer: C — 2 hours
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Q. A train travels 120 km at a uniform speed. If it takes 2 hours to complete the journey, what is the speed of the train?
A.
50 km/h
B.
60 km/h
C.
70 km/h
D.
80 km/h
Show solution
Solution
Speed = distance / time = 120 km / 2 h = 60 km/h.
Correct Answer: B — 60 km/h
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Q. A train travels 60 km at a speed of 30 km/h and then 90 km at a speed of 60 km/h. What is the average speed of the train for the entire journey? (2021)
A.
40 km/h
B.
45 km/h
C.
50 km/h
D.
55 km/h
Show solution
Solution
Total distance = 60 + 90 = 150 km. Time for first part = 60/30 = 2 hours. Time for second part = 90/60 = 1.5 hours. Total time = 2 + 1.5 = 3.5 hours. Average speed = Total distance / Total time = 150 / 3.5 = 42.86 km/h, which rounds to 45 km/h.
Correct Answer: B — 45 km/h
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Q. A train travels 60 km at a speed of 30 km/h and then travels another 60 km at a speed of 60 km/h. What is the average speed of the train for the entire journey? (2020)
A.
40 km/h
B.
45 km/h
C.
50 km/h
D.
55 km/h
Show solution
Solution
Total distance = 120 km. Time for first part = 60/30 = 2 hours. Time for second part = 60/60 = 1 hour. Total time = 3 hours. Average speed = Total distance / Total time = 120/3 = 40 km/h.
Correct Answer: B — 45 km/h
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Q. A train travels 60 km in 1 hour. How far will it travel in 2.5 hours at the same speed? (2019)
A.
120 km
B.
150 km
C.
180 km
D.
200 km
Show solution
Solution
Distance = Speed × Time. Therefore, distance = 60 km/h × 2.5 h = 150 km.
Correct Answer: B — 150 km
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Q. A train travels 60 km in 1 hour. How far will it travel in 2.5 hours? (2019)
A.
120 km
B.
150 km
C.
180 km
D.
200 km
Show solution
Solution
Distance = Speed × Time. Therefore, distance = 60 km/h × 2.5 h = 150 km.
Correct Answer: B — 150 km
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Q. A train travels at a speed of 60 km/h. How far will it travel in 2.5 hours? (2022)
A.
120 km
B.
150 km
C.
180 km
D.
200 km
Show solution
Solution
Distance = Speed × Time = 60 km/h × 2.5 h = 150 km.
Correct Answer: B — 150 km
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Q. A train travels at a speed of 72 km/h. How far will it travel in 30 minutes?
A.
12 km
B.
18 km
C.
24 km
D.
36 km
Show solution
Solution
Distance = speed × time = 72 km/h × 0.5 h = 36 km.
Correct Answer: B — 18 km
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