Q. A potentiometer wire is made of constantan. What is the advantage of using this material?
A.
High conductivity
B.
Low temperature coefficient
C.
High resistance
D.
Low cost
Show solution
Solution
Constantan has a low temperature coefficient, making it stable for accurate measurements.
Correct Answer: B — Low temperature coefficient
Learn More →
Q. A prize of $1500 is to be divided among three students in the ratio 2:3:5. How much does the student with the largest share receive?
A.
$500
B.
$600
C.
$750
D.
$900
Show solution
Solution
Total parts = 2 + 3 + 5 = 10. Largest share = (5/10) * 1500 = $750.
Correct Answer: C — $750
Learn More →
Q. A prize of $1500 is to be divided among three students in the ratio 2:3:5. How much will the student with the largest share receive?
A.
$500
B.
$600
C.
$750
D.
$900
Show solution
Solution
Total parts = 2 + 3 + 5 = 10. Largest share = (5/10) * 1500 = $750.
Correct Answer: B — $600
Learn More →
Q. A prize of $3000 is to be divided among 3 winners in the ratio 2:3:5. How much does the second winner receive? (2019)
A.
$600
B.
$900
C.
$1200
D.
$1500
Show solution
Solution
Total parts = 2 + 3 + 5 = 10. Second winner's share = (3/10) * 3000 = $900.
Correct Answer: B — $900
Learn More →
Q. A prize of $3000 is to be divided among 3 winners in the ratio 2:3:5. How much does the winner with the largest share receive? (2019)
A.
$600
B.
$900
C.
$1200
D.
$1500
Show solution
Solution
Total parts = 2 + 3 + 5 = 10. The largest share = (5/10) * 3000 = $1500.
Correct Answer: C — $1200
Learn More →
Q. A product is bought for $120 and sold for $144. What is the profit percentage?
A.
15%
B.
20%
C.
25%
D.
30%
Show solution
Solution
Profit = Selling Price - Cost Price = 144 - 120 = 24. Profit Percentage = (Profit/Cost Price) * 100 = (24/120) * 100 = 20%.
Correct Answer: B — 20%
Learn More →
Q. A product is bought for $200 and sold for $240. What is the profit percentage?
A.
15%
B.
20%
C.
25%
D.
30%
Show solution
Solution
Profit = Selling Price - Cost Price = 240 - 200 = 40. Profit Percentage = (Profit/Cost Price) * 100 = (40/200) * 100 = 20%.
Correct Answer: B — 20%
Learn More →
Q. A product is bought for $500 and sold for $450. What is the loss percentage? (2023)
A.
10%
B.
15%
C.
20%
D.
25%
Show solution
Solution
Loss = Cost Price - Selling Price = 500 - 450 = 50. Loss Percentage = (Loss/Cost Price) * 100 = (50/500) * 100 = 10%.
Correct Answer: C — 20%
Learn More →
Q. A product is marked at $250 and sold for $200. What is the discount percentage?
A.
15%
B.
20%
C.
25%
D.
30%
Show solution
Solution
Discount = Marked Price - Selling Price = 250 - 200 = 50. Discount Percentage = (50/250) * 100 = 20%.
Correct Answer: B — 20%
Learn More →
Q. A product is marked at $600 and sold at a loss of 10%. What is the selling price?
A.
$540
B.
$550
C.
$560
D.
$570
Show solution
Solution
Selling Price = Marked Price - Loss = 600 - (10% of 600) = 600 - 60 = $540.
Correct Answer: A — $540
Learn More →
Q. A product is sold at a loss of 25%. If the selling price is $75, what was the cost price?
A.
$100
B.
$90
C.
$80
D.
$70
Show solution
Solution
Let the cost price be x. Selling Price = x - (25% of x) = 0.75x. Therefore, 0.75x = $75, x = $75 / 0.75 = $100.
Correct Answer: A — $100
Learn More →
Q. A product is sold at a profit of 25%. If the selling price is $250, what was the cost price?
A.
$200
B.
$180
C.
$220
D.
$240
Show solution
Solution
Let the cost price be x. Selling Price = Cost Price + Profit = x + 0.25x = 1.25x. Setting this equal to $250 gives 1.25x = $250, so x = $250 / 1.25 = $200.
Correct Answer: A — $200
Learn More →
Q. A product is sold at a profit of 30%. If the selling price is $130, what was the cost price?
A.
$100
B.
$90
C.
$110
D.
$120
Show solution
Solution
Let the cost price be x. Selling Price = x + 30% of x = 1.3x. Thus, 1.3x = 130, so x = 100.
Correct Answer: A — $100
Learn More →
Q. A product is sold for $240 after a discount of 20%. What was the original price?
A.
$300
B.
$280
C.
$250
D.
$260
Show solution
Solution
Let the original price be x. Selling Price = x - (20% of x) = 0.80x. Thus, 0.80x = $240, so x = $240 / 0.80 = $300.
Correct Answer: A — $300
Learn More →
Q. A product is sold for $300 after a discount of 25%. What was the original price of the product? (2023)
A.
$350
B.
$375
C.
$400
D.
$450
Show solution
Solution
Let the original price be x. Then, Selling Price = x - (25% of x) = 300 => 0.75x = 300 => x = 400.
Correct Answer: C — $400
Learn More →
Q. A product is sold for $300 after a discount of 30%. What was the original price?
A.
$400
B.
$350
C.
$450
D.
$500
Show solution
Solution
Let the original price be x. After a 30% discount, the selling price is 0.70x. Setting this equal to $300 gives 0.70x = $300, so x = $300 / 0.70 = $428.57, which rounds to $400.
Correct Answer: A — $400
Learn More →
Q. A product's price is increased by 15% and then decreased by 15%. What is the net effect on the price?
A.
0%
B.
2.25%
C.
3.25%
D.
4.5%
Show solution
Solution
Let the original price be $100. After a 15% increase, the price is $115. After a 15% decrease, the price is $115 - (15% of $115) = $115 - $17.25 = $97.75. The net change is ($97.75 - $100) / $100 * 100% = -2.25%.
Correct Answer: B — 2.25%
Learn More →
Q. A projectile is launched at an angle of 30 degrees with an initial speed of 20 m/s. What is the maximum height reached by the projectile?
A.
5 m
B.
10 m
C.
15 m
D.
20 m
Show solution
Solution
Using the formula: h = (u² * sin²θ) / (2g), where u = 20 m/s, θ = 30°, g = 9.8 m/s². h = (20² * (1/4)) / (2 * 9.8) = 5.1 m, approximately 5 m.
Correct Answer: B — 10 m
Learn More →
Q. A projectile is launched at an angle of 30 degrees with an initial speed of 20 m/s. What is the maximum height it reaches? (2022)
A.
5 m
B.
10 m
C.
15 m
D.
20 m
Show solution
Solution
Using the formula: H = (u² * sin²θ) / (2g). H = (20² * (1/2)) / (2 * 9.8) = 10.2 m, approximately 10 m.
Correct Answer: B — 10 m
Learn More →
Q. A projectile is launched at an angle of 30 degrees with an initial speed of 20 m/s. What is the maximum height reached? (g = 10 m/s²)
A.
5 m
B.
10 m
C.
15 m
D.
20 m
Show solution
Solution
Maximum height h = (u^2 * sin²θ) / (2g) = (20² * (1/2)²) / (2 * 10) = 5 m.
Correct Answer: B — 10 m
Learn More →
Q. A projectile is launched at an angle of 30 degrees with an initial speed of 40 m/s. What is the maximum height reached? (g = 10 m/s²)
A.
80 m
B.
60 m
C.
40 m
D.
20 m
Show solution
Solution
Maximum height = (u^2 * sin²θ) / (2g) = (40^2 * (1/2)) / (2 * 10) = 80 m.
Correct Answer: B — 60 m
Learn More →
Q. A projectile is launched at an angle of 30 degrees with an initial velocity of 20 m/s. What is the maximum height reached by the projectile?
A.
5 m
B.
10 m
C.
15 m
D.
20 m
Show solution
Solution
Maximum height (H) = (u^2 * sin^2(θ)) / (2g) = (20^2 * (1/2)^2) / (2 * 9.8) = 10.2 m.
Correct Answer: B — 10 m
Learn More →
Q. A projectile is launched at an angle of 30° with an initial speed of 40 m/s. What is the maximum height reached by the projectile?
A.
80 m
B.
60 m
C.
40 m
D.
20 m
Show solution
Solution
Using the formula H = (u² * sin²θ) / (2g), where u = 40 m/s, θ = 30°, and g = 9.8 m/s², we find H = (40² * (1/4)) / (2*9.8) = 40.82 m, approximately 60 m.
Correct Answer: B — 60 m
Learn More →
Q. A projectile is launched at an angle of 30° with the horizontal with an initial velocity of 40 m/s. What is the horizontal range of the projectile? (Take g = 10 m/s²)
A.
160 m
B.
200 m
C.
80 m
D.
120 m
Show solution
Solution
Range R = (u² * sin(2θ))/g = (40² * sin(60°))/10 = (1600 * √3/2)/10 = 80√3 m ≈ 138.56 m.
Correct Answer: B — 200 m
Learn More →
Q. A projectile is launched with a speed of 30 m/s at an angle of 60 degrees. What is the horizontal component of its velocity?
A.
15 m/s
B.
20 m/s
C.
25 m/s
D.
30 m/s
Show solution
Solution
Horizontal component (v_x) = u * cos(θ) = 30 * 0.5 = 15 m/s.
Correct Answer: B — 20 m/s
Learn More →
Q. A projectile is launched with a speed of 50 m/s at an angle of 30 degrees. What is the time of flight?
A.
5 s
B.
10 s
C.
15 s
D.
20 s
Show solution
Solution
Time of flight (T) = (2 * u * sin(θ)) / g = (2 * 50 * (√3/2)) / 9.8 ≈ 10.2 s.
Correct Answer: B — 10 s
Learn More →
Q. A projectile is launched with a speed of 50 m/s at an angle of 30 degrees. What is the horizontal component of the velocity?
A.
25 m/s
B.
35 m/s
C.
43.3 m/s
D.
50 m/s
Show solution
Solution
Horizontal component (u_x) = u * cos(θ) = 50 * (√3/2) = 43.3 m/s.
Correct Answer: C — 43.3 m/s
Learn More →
Q. A projectile is launched with a speed of 50 m/s at an angle of 60 degrees. What is the horizontal component of its velocity?
A.
25 m/s
B.
50 m/s
C.
43.3 m/s
D.
30 m/s
Show solution
Solution
Horizontal component (v_x) = v * cos(θ) = 50 * 0.5 = 43.3 m/s.
Correct Answer: C — 43.3 m/s
Learn More →
Q. A projectile is launched with an initial speed of 30 m/s at an angle of 60 degrees. What is the horizontal component of the velocity?
A.
15 m/s
B.
20 m/s
C.
25 m/s
D.
30 m/s
Show solution
Solution
Horizontal component (vx) = u * cos(θ) = 30 * 0.5 = 15 m/s.
Correct Answer: C — 25 m/s
Learn More →
Q. A projectile is launched with an initial speed of 30 m/s at an angle of 60 degrees. What is the horizontal component of its velocity?
A.
15 m/s
B.
20 m/s
C.
25 m/s
D.
30 m/s
Show solution
Solution
Horizontal component (vx) = u * cos(θ) = 30 * 0.5 = 15 m/s.
Correct Answer: B — 20 m/s
Learn More →
Showing 1891 to 1920 of 25216 (841 Pages)
