A sharp increase in December could be attributed to multiple factors, including holiday shopping.

The sharp increase in December likely correlates with holiday shopping trends.

Consistently higher sales for Product B suggest it is more popular among consumers.

Slope of 2x + 3y = 6 is -2/3, so m = 3/2 (negative reciprocal).

To find the x-intercept, set y = 0. Solving gives x = 2, so the intersection point is (2, 0).

Setting y to 0 in the equation gives x = 2, so the intersection with the x-axis is (2, 0).

The lines intersect if the discriminant D = b^2 - 4ac > 0.

The sum of the slopes of the lines can be found using the relation -b/a, which gives -3.

Using the formula for the angle between two lines, we can derive the coefficient of xy that satisfies the angle condition.

The product of the slopes of the lines can be found from the equation. Here, the product of the slopes is given by -c/a, where c is the coefficient of xy and a is the coefficient of x^2.

For the lines to be perpendicular, the condition 4 - 4(3)(2) = 0 must hold, leading to k = 0.

The product of the slopes of the lines represented by ax^2 + bxy + cy^2 = 0 is given by c/a. Here, c = 2 and a = 3, so the product is 2/3.

The lines are coincident when the determinant of the coefficients is zero, leading to k = 0.

The nature of the intersection can be determined by the slopes, which indicate that the angle is obtuse.

The angle can be found using the formula tan(θ) = |(m1 - m2) / (1 + m1*m2)|, where m1 and m2 are the slopes derived from the equation.

The sum of the slopes of the lines is given by -b/a, which is 0 in this case.

The nature of the roots can be determined by the discriminant of the quadratic equation.

The lines are not perpendicular as the condition for perpendicularity is not satisfied.

The condition for the lines to be real and distinct is that the discriminant D must be greater than 0.

For the lines to be perpendicular, the condition a + b = 0 must hold.

For the lines to be coincident, the constant term must be zero.

If the magnetic field around a closed loop is constant, the current through the loop must also be constant according to Ampere's Law.

In a uniform magnetic field, the magnetic field lines are straight and parallel.

The force experienced by a current-carrying conductor in a magnetic field is directly proportional to the magnetic field strength. Therefore, if the magnetic field strength is doubled, the force also doubles.

The force on a charged particle is directly proportional to the magnetic field strength, so if the magnetic field strength is doubled, the force also doubles.

The force on a current-carrying conductor is directly proportional to the magnetic field strength, so if the magnetic field strength is doubled, the force also doubles.

The force on a current-carrying conductor is directly proportional to the magnetic field strength, so if the field strength is doubled, the force also doubles.

According to Faraday's law, the induced EMF is directly proportional to the rate of change of magnetic flux, which depends on the magnetic field strength.

The magnetic force on a charged particle is given by F = qvB sin(θ). If the magnetic field strength B is doubled, the force F also doubles, assuming charge q and velocity v remain constant.

Magnetic flux is given by the product of magnetic field strength and area. If the magnetic field is doubled, the magnetic flux also doubles.