Q. What is the relationship between the average speed and RMS speed of gas molecules?
A.
RMS speed is always greater than average speed
B.
RMS speed is always less than average speed
C.
RMS speed equals average speed
D.
RMS speed is independent of average speed
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Solution
For an ideal gas, the RMS speed is always greater than the average speed due to the nature of the distribution of molecular speeds.
Correct Answer: A — RMS speed is always greater than average speed
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Q. What is the relationship between the Celsius and Kelvin scales?
A.
K = C + 273.15
B.
C = K + 273.15
C.
K = C - 273.15
D.
C = K - 273.15
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Solution
The relationship is K = C + 273.15, where K is the temperature in Kelvin and C is the temperature in Celsius.
Correct Answer: A — K = C + 273.15
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Q. What is the relationship between the damping coefficient and the type of damping?
A.
Higher coefficient indicates under-damping
B.
Lower coefficient indicates over-damping
C.
Critical damping occurs at a specific coefficient
D.
Damping coefficient has no effect
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Solution
Critical damping occurs at a specific value of the damping coefficient, which separates under-damping from over-damping.
Correct Answer: C — Critical damping occurs at a specific coefficient
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Q. What is the relationship between the damping ratio and the type of damping in a system?
A.
Damping ratio < 1 indicates overdamping
B.
Damping ratio = 1 indicates critical damping
C.
Damping ratio > 1 indicates underdamping
D.
Damping ratio = 0 indicates critical damping
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Solution
A damping ratio of 1 indicates critical damping, while less than 1 indicates underdamping and greater than 1 indicates overdamping.
Correct Answer: B — Damping ratio = 1 indicates critical damping
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Q. What is the relationship between the damping ratio and the type of damping?
A.
Damping ratio < 1: Underdamping
B.
Damping ratio = 1: Overdamping
C.
Damping ratio > 1: Critical damping
D.
Damping ratio = 0: Overdamping
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Solution
A damping ratio less than 1 indicates underdamping, equal to 1 indicates critical damping, and greater than 1 indicates overdamping.
Correct Answer: A — Damping ratio < 1: Underdamping
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Q. What is the relationship between the density of a gas and its molar mass at constant temperature and pressure?
A.
Density is directly proportional to molar mass
B.
Density is inversely proportional to molar mass
C.
Density is independent of molar mass
D.
Density is equal to molar mass
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Solution
At constant temperature and pressure, density is directly proportional to molar mass according to the ideal gas law.
Correct Answer: A — Density is directly proportional to molar mass
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Q. What is the relationship between the electric field and magnetic field in polarized light?
A.
They are always perpendicular to each other
B.
They oscillate in the same direction
C.
They are in phase with each other
D.
They have varying amplitudes
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Solution
In polarized light, the electric field and magnetic field are always perpendicular to each other.
Correct Answer: A — They are always perpendicular to each other
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Q. What is the relationship between the electric field vector and the direction of propagation in linearly polarized light?
A.
They are perpendicular
B.
They are parallel
C.
They are at 45 degrees
D.
They are randomly oriented
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Solution
In linearly polarized light, the electric field vector is perpendicular to the direction of propagation.
Correct Answer: A — They are perpendicular
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Q. What is the relationship between the equilibrium constant (K) and the Gibbs free energy change (ΔG) for a reaction?
A.
ΔG = -RT ln(K)
B.
ΔG = RT ln(K)
C.
ΔG = KRT
D.
ΔG = K/R
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Solution
The relationship is given by the equation ΔG = -RT ln(K), where R is the gas constant and T is the temperature in Kelvin.
Correct Answer: A — ΔG = -RT ln(K)
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Q. What is the relationship between the equilibrium constant (K) and the reaction quotient (Q)?
A.
K = Q at equilibrium
B.
K > Q at equilibrium
C.
K < Q at equilibrium
D.
K is independent of Q
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Solution
At equilibrium, the reaction quotient Q is equal to the equilibrium constant K.
Correct Answer: A — K = Q at equilibrium
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Q. What is the relationship between the equilibrium constants Kp and Kc for a gaseous reaction?
A.
Kp = Kc
B.
Kp = Kc(RT)^(Δn)
C.
Kp = Kc/RT
D.
Kp = Kc(RT)^(Δn) where Δn is the change in moles of gas
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Solution
The relationship between Kp and Kc is given by Kp = Kc(RT)^(Δn), where Δn is the change in the number of moles of gas.
Correct Answer: B — Kp = Kc(RT)^(Δn)
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Q. What is the relationship between the frequency and period of a wave?
A.
Frequency = Period × Speed
B.
Frequency = 1/Period
C.
Frequency = Speed × Wavelength
D.
Frequency = Wavelength/Speed
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Solution
The relationship is given by Frequency = 1/Period.
Correct Answer: B — Frequency = 1/Period
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Q. What is the relationship between the frequency and the period of a simple harmonic oscillator?
A.
f = T
B.
f = 1/T
C.
f = T^2
D.
f = 2T
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Solution
The frequency (f) is the reciprocal of the period (T), so f = 1/T.
Correct Answer: B — f = 1/T
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Q. What is the relationship between the frequency and wavelength of a wave?
A.
Frequency = Wavelength × Speed
B.
Wavelength = Speed / Frequency
C.
Speed = Frequency × Wavelength
D.
All of the above
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Solution
The relationship is given by the equation Speed = Frequency × Wavelength, which can be rearranged to show the other relationships.
Correct Answer: D — All of the above
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Q. What is the relationship between the frequency of incident light and the number of emitted electrons in the photoelectric effect?
A.
Directly proportional
B.
Inversely proportional
C.
No relationship
D.
Exponential relationship
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Solution
The number of emitted electrons is related to the intensity of light, not the frequency, as long as the frequency is above the threshold.
Correct Answer: C — No relationship
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Q. What is the relationship between the Gibbs free energy change (ΔG) and the equilibrium constant (K)?
A.
ΔG = -RT ln(K)
B.
ΔG = RT ln(K)
C.
ΔG = K - RT
D.
ΔG = 0 at equilibrium
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Solution
The relationship is given by the equation ΔG = -RT ln(K), where R is the gas constant and T is the temperature in Kelvin.
Correct Answer: A — ΔG = -RT ln(K)
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Q. What is the relationship between the Gibbs free energy change (ΔG) and the equilibrium constant (K) at standard conditions?
A.
ΔG = RT ln K
B.
ΔG = -RT ln K
C.
ΔG = KRT
D.
ΔG = K/R
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Solution
ΔG = -RT ln K relates Gibbs free energy change to the equilibrium constant.
Correct Answer: B — ΔG = -RT ln K
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Q. What is the relationship between the height of a satellite and its orbital period?
A.
Directly proportional
B.
Inversely proportional
C.
No relationship
D.
Exponential relationship
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Solution
The orbital period T of a satellite is related to its height h by T ∝ h^(3/2), which indicates that the period is inversely proportional to the square root of the gravitational force acting on it.
Correct Answer: B — Inversely proportional
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Q. What is the relationship between the intensity of light and the energy of individual photons in the photoelectric effect?
A.
Directly proportional
B.
Inversely proportional
C.
Independent
D.
Depends on frequency
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Solution
The energy of individual photons is dependent on frequency (E = hν) and not on intensity.
Correct Answer: C — Independent
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Q. What is the relationship between the magnetic field and the distance from a long straight wire carrying current?
A.
Directly proportional
B.
Inversely proportional
C.
Independent
D.
Exponential
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Solution
The magnetic field around a long straight wire is inversely proportional to the distance from the wire, as given by B = μ₀I/2πr.
Correct Answer: B — Inversely proportional
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Q. What is the relationship between the magnetic field and the enclosed current according to Ampere's Law?
A.
B is proportional to the square of the current
B.
B is inversely proportional to the current
C.
B is directly proportional to the current
D.
B is independent of the current
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Solution
According to Ampere's Law, the magnetic field B is directly proportional to the enclosed current.
Correct Answer: C — B is directly proportional to the current
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Q. What is the relationship between the mean free path (λ) and the diameter (d) of gas molecules?
A.
λ ∝ d^2
B.
λ ∝ 1/d
C.
λ ∝ d
D.
λ ∝ d^3
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Solution
The mean free path (λ) is inversely proportional to the diameter (d) of the gas molecules, meaning λ ∝ 1/d.
Correct Answer: B — λ ∝ 1/d
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Q. What is the relationship between the mean free path and the density of gas molecules?
A.
Mean free path increases with density
B.
Mean free path decreases with density
C.
Mean free path is independent of density
D.
Mean free path is proportional to the square of density
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Solution
The mean free path is inversely proportional to the density of gas molecules. As density increases, the mean free path decreases due to more frequent collisions.
Correct Answer: B — Mean free path decreases with density
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Q. What is the relationship between the mean free path and the diameter of gas molecules?
A.
Mean free path is independent of diameter
B.
Mean free path is directly proportional to diameter
C.
Mean free path is inversely proportional to diameter
D.
Mean free path is equal to diameter
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Solution
The mean free path is inversely proportional to the diameter of gas molecules; as the diameter increases, the mean free path decreases.
Correct Answer: C — Mean free path is inversely proportional to diameter
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Q. What is the relationship between the molality of a solution and its boiling point elevation?
A.
Directly proportional
B.
Inversely proportional
C.
No relationship
D.
Exponential relationship
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Solution
Boiling point elevation is directly proportional to the molality of the solution.
Correct Answer: A — Directly proportional
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Q. What is the relationship between the number of emitted electrons and the intensity of light in the photoelectric effect?
A.
Directly proportional
B.
Inversely proportional
C.
No relationship
D.
Exponential relationship
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Solution
The number of emitted electrons is directly proportional to the intensity of light, provided the frequency is above the threshold frequency.
Correct Answer: A — Directly proportional
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Q. What is the relationship between the number of slits in a diffraction grating and the sharpness of the maxima?
A.
More slits, sharper maxima
B.
More slits, broader maxima
C.
No relationship
D.
Fewer slits, sharper maxima
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Solution
Increasing the number of slits in a diffraction grating results in sharper maxima due to increased constructive interference.
Correct Answer: A — More slits, sharper maxima
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Q. What is the relationship between the orbital radius and the period of a satellite in a circular orbit?
A.
T is directly proportional to r
B.
T is inversely proportional to r
C.
T is proportional to r^2
D.
T is proportional to √r
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Solution
The period T of a satellite is proportional to the square root of the orbital radius r (T ∝ √r).
Correct Answer: D — T is proportional to √r
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Q. What is the relationship between the orbital radius and the time period of a satellite?
A.
T ∝ r^2
B.
T ∝ r^3/2
C.
T ∝ r
D.
T ∝ r^1/2
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Solution
The time period T of a satellite is related to the orbital radius r by T ∝ r^(3/2), according to Kepler's third law.
Correct Answer: B — T ∝ r^3/2
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Q. What is the relationship between the period and frequency of a simple harmonic oscillator?
A.
T = f
B.
T = 1/f
C.
T = f^2
D.
T = 2f
Show solution
Solution
The period (T) is the reciprocal of frequency (f), so T = 1/f.
Correct Answer: B — T = 1/f
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