Q. What is the magnetic field inside a hollow conductor carrying current?
A.
Zero
B.
Uniform
C.
Varies with distance
D.
Depends on the current
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Solution
According to Ampere's law, the magnetic field inside a hollow conductor carrying current is zero.
Correct Answer: A — Zero
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Q. What is the magnetic field inside a hollow cylindrical shell carrying current I?
A.
0
B.
μ₀I/2πR
C.
μ₀I/4πR
D.
μ₀I/πR
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Solution
Inside a hollow cylindrical shell, the magnetic field is zero.
Correct Answer: A — 0
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Q. What is the magnetic field inside a long solenoid carrying current I?
A.
Zero
B.
μ₀nI
C.
μ₀I/n
D.
μ₀I/2
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Solution
The magnetic field inside a long solenoid is given by B = μ₀nI, where n is the number of turns per unit length.
Correct Answer: B — μ₀nI
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Q. What is the magnetic field inside a long solenoid carrying current?
A.
Zero
B.
Uniform and parallel to the axis
C.
Varies with distance
D.
Depends on the current only
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Solution
The magnetic field inside a long solenoid is uniform and parallel to the axis of the solenoid.
Correct Answer: B — Uniform and parallel to the axis
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Q. What is the magnetic field inside a long solenoid with n turns per unit length carrying a current I?
A.
μ₀nI
B.
μ₀I/n
C.
μ₀I/2n
D.
μ₀I/4n
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Solution
The magnetic field inside a long solenoid is given by B = μ₀nI.
Correct Answer: A — μ₀nI
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Q. What is the magnetic field inside a long straight conductor carrying a current I?
A.
0
B.
μ₀I/2πr
C.
μ₀I/4πr
D.
μ₀I/πr
Show solution
Solution
Using Ampere's Law, B = μ₀I/2πr for a long straight conductor.
Correct Answer: B — μ₀I/2πr
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Q. What is the magnetic field inside a long straight conductor carrying current I?
A.
0
B.
μ₀I/2πr
C.
μ₀I/4πr
D.
μ₀I/πr
Show solution
Solution
Using Ampere's Law, B = μ₀I/2πr for a long straight conductor.
Correct Answer: B — μ₀I/2πr
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Q. What is the magnetic field inside a long, ideal solenoid carrying current I?
A.
Zero
B.
μ₀I
C.
μ₀I/n
D.
μ₀nI
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Solution
The magnetic field inside a long, ideal solenoid is given by B = μ₀nI, where n is the number of turns per unit length.
Correct Answer: D — μ₀nI
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Q. What is the magnetic field inside a long, ideal solenoid carrying current?
A.
Zero
B.
Uniform and parallel
C.
Concentric circles
D.
Decreasing
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Solution
The magnetic field inside a long, ideal solenoid is uniform and parallel to the axis of the solenoid.
Correct Answer: B — Uniform and parallel
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Q. What is the magnetic field inside a long, ideal solenoid with n turns per unit length carrying a current I?
A.
B = μ₀nI
B.
B = μ₀I/n
C.
B = nI/μ₀
D.
B = μ₀I
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Solution
The magnetic field inside an ideal solenoid is given by B = μ₀nI, where n is the number of turns per unit length.
Correct Answer: A — B = μ₀nI
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Q. What is the magnetic field inside a long, ideal solenoid?
A.
Zero
B.
Uniform and parallel
C.
Concentric circles
D.
Diverging lines
Show solution
Solution
The magnetic field inside a long, ideal solenoid is uniform and parallel.
Correct Answer: B — Uniform and parallel
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Q. What is the magnetic field inside a long, straight solenoid carrying current I?
A.
0
B.
μ₀I
C.
μ₀nI
D.
μ₀nI/2
Show solution
Solution
The magnetic field inside a long, straight solenoid is given by B = μ₀nI, where n is the number of turns per unit length and μ₀ is the permeability of free space.
Correct Answer: C — μ₀nI
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Q. What is the magnetic field inside a long, straight solenoid carrying current?
A.
Zero
B.
Uniform and parallel to the axis
C.
Varies with distance
D.
Concentric circles
Show solution
Solution
The magnetic field inside a long, straight solenoid is uniform and parallel to the axis of the solenoid, given by B = μ₀nI, where n is the number of turns per unit length.
Correct Answer: B — Uniform and parallel to the axis
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Q. What is the magnetic field inside a solenoid carrying current I with n turns per unit length?
A.
μ₀nI
B.
μ₀I/n
C.
μ₀I
D.
μ₀nI/2
Show solution
Solution
The magnetic field inside a long solenoid is given by B = μ₀nI.
Correct Answer: A — μ₀nI
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Q. What is the magnetic field strength at the center of a square loop of side a carrying a current I?
A.
(μ₀I)/(2a)
B.
(μ₀I)/(4a)
C.
(μ₀I)/(√2a)
D.
(μ₀I)/(8a)
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Solution
The magnetic field at the center of a square loop is given by B = (μ₀I)/(√2a).
Correct Answer: C — (μ₀I)/(√2a)
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Q. What is the magnetic quantum number for a 3d orbital?
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Solution
The magnetic quantum number (m_l) for a 3d orbital can be -2, -1, 0, 1, or 2.
Correct Answer: A — -2
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Q. What is the magnification produced by a concave lens if the object distance is 20 cm and the image distance is -10 cm?
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Solution
Magnification m = -v/u = -(-10)/20 = 0.5.
Correct Answer: A — 0.5
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Q. What is the magnification produced by a concave mirror if the object is placed at a distance of 15 cm and the image is formed at 5 cm?
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Solution
Magnification (m) = -v/u = -(-5)/(-15) = 1/3. Therefore, the magnification is 3.
Correct Answer: C — 3
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Q. What is the magnification produced by a convex lens if the object is placed at twice the focal length?
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Solution
Magnification (m) = v/u. For an object at 2f, the image distance v = 2f, so m = 2f/(2f) = 1.
Correct Answer: A — 1
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Q. What is the magnification produced by a lens if the object distance is 15 cm and the image distance is 45 cm?
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Solution
Magnification (m) = image distance/object distance = 45/15 = 3.
Correct Answer: C — 3
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Q. What is the magnification produced by a lens if the object distance is 15 cm and the image distance is 30 cm?
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Solution
Magnification (m) = image distance/object distance = 30/15 = 2.
Correct Answer: C — 2
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Q. What is the magnification produced by a lens if the object distance is 20 cm and the image distance is 10 cm?
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Solution
Magnification (m) = -v/u = -10/20 = 0.5, but since we consider absolute value, m = 2.
Correct Answer: C — 2
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Q. What is the magnification produced by a lens if the object distance is 25 cm and the image distance is 50 cm?
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Solution
Magnification (m) = -v/u = -50/25 = -2. The absolute value indicates the image is twice the size of the object.
Correct Answer: C — 2
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Q. What is the magnitude of the vector (2, -3, 6)?
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Solution
Magnitude = √(2^2 + (-3)^2 + 6^2) = √(4 + 9 + 36) = √49 = 7.
Correct Answer: B — 9
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Q. What is the magnitude of the vector (3, 4)?
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Solution
Magnitude = √(3^2 + 4^2) = √(9 + 16) = √25 = 5
Correct Answer: A — 5
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Q. What is the magnitude of the vector C = (6, 8, 10)?
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Solution
Magnitude |C| = √(6^2 + 8^2 + 10^2) = √(36 + 64 + 100) = √200 = 10√2.
Correct Answer: C — 14
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Q. What is the magnitude of the vector v = (3, -4)?
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Solution
Magnitude of v = √(3^2 + (-4)^2) = √(9 + 16) = √25 = 5.
Correct Answer: A — 5
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Q. What is the main active ingredient in most antacids?
A.
Calcium carbonate
B.
Magnesium hydroxide
C.
Aluminum hydroxide
D.
All of the above
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Solution
Most antacids contain a combination of calcium carbonate, magnesium hydroxide, and aluminum hydroxide to neutralize stomach acid.
Correct Answer: D — All of the above
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Q. What is the main advantage of using a potentiometer over a voltmeter?
A.
It is cheaper.
B.
It provides more accurate measurements.
C.
It is easier to use.
D.
It can measure AC voltages.
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Solution
A potentiometer provides more accurate measurements because it measures voltage by balancing rather than drawing current from the circuit.
Correct Answer: B — It provides more accurate measurements.
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Q. What is the main advantage of using a Wheatstone bridge in measurements?
A.
It is very fast
B.
It provides high accuracy
C.
It is very simple
D.
It requires no power supply
Show solution
Solution
The Wheatstone bridge is known for providing high accuracy in measuring unknown resistances.
Correct Answer: B — It provides high accuracy
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