In H3PO4, phosphorus has an oxidation state of +5.

In phosphoric acid, phosphorus has an oxidation state of +5.

In H2SO4, the oxidation state of sulfur is +6.

In UF6, Uranium is in the +6 oxidation state as it forms six bonds with fluorine.

Integrating gives y = 2x^2 + C. Using the initial condition, C = 1.

The general solution is y = Ce^(2x). Using the initial condition y(0) = 1, we find C = 1.

The general solution is y = Ce^(2x). Using y(0) = 5 gives C = 5.

Path difference = d sin θ = d sin(45°) = d(√2/2). For d = λ, path difference = √2λ.

Path difference = d sin θ = 1 m * sin(45°) = 1 m * √2/2 = 0.707 m.

The path difference for the first minimum is λ/2, which leads to destructive interference.

Percentage by mass = (mass of solute / mass of solution) * 100 = (20 g / (20 g + 180 g)) * 100 = 20%.

Percentage by mass = (mass of solute / total mass) × 100 = (5 g / (5 g + 95 g)) × 100 = 5%.

Molar mass of glucose = 6(12) + 12(1) + 6(16) = 180 g. Percentage of carbon = (72/180) x 100 = 40%.

The element with atomic number 20 is Calcium, which is in period 4.

The period T of a simple pendulum is given by T = 2π√(L/g). For L = 1 m and g ≈ 9.8 m/s², T = 2π√(1/9.8) ≈ 2 s.

The period of a satellite in a circular orbit at a height of 300 km is approximately 90 minutes.

Satellites in low Earth orbit have a much shorter orbital period compared to geostationary satellites due to their proximity to Earth.

Electronegativity increases across a period from left to right.

The pH of a 0.01 M HCl solution is 2, as HCl is a strong acid and fully dissociates.

For NaOH, which is a strong base, pOH = -log[OH-]. [OH-] = 0.01 M, so pOH = 2. Therefore, pH = 14 - pOH = 14 - 2 = 12.

Sodium acetate is a salt of a weak acid (acetic acid) and a strong base (sodium hydroxide). The pH can be calculated using the formula pH = 7 + 0.5(pKa - log[C]), where pKa of acetic acid is 4.76.

pH = 14 - pOH; pOH = -log[OH-] = -log(0.01) = 2; pH = 14 - 2 = 12.

H2SO4 is a strong acid and dissociates completely, so pH = -log(0.01) = 2.

H2SO4 is a strong acid and dissociates completely; [H+] = 0.05 M, so pH = -log(0.05) ≈ 1.3

pOH = -log[OH-] = -log(0.1) = 1; pH = 14 - pOH = 14 - 1 = 13

Using the formula for weak acids, pH = 0.5(pKa - log[C]) = 0.5(4.74 - log(0.1)) = 4.76.

NH4Cl is a salt of a weak base and a strong acid; it hydrolyzes to give H+, resulting in a pH < 7.

The pH of a strong acid like HCl is calculated using the formula pH = -log[H+]. For 0.1 M HCl, [H+] = 0.1 M, so pH = -log(0.1) = 1.

KHP is a weak acid; its pKa is approximately 5.0, so the pH of a 0.1 M solution is around 5.0.

pH = 7 + 0.5(pKa + log[C]) = 7 + 0.5(4.76 + log(0.1)) = 9.24