The equivalent resistance in parallel is given by 1/R_total = 1/R1 + 1/R2 = 1/10 + 1/10 = 1/5. Therefore, R_total = 5Ω.

In series, the equivalent resistance is the sum of the individual resistances: R_eq = R1 + R2 + R3 = 2 + 3 + 6 = 11 ohms.

1/Req = 1/R1 + 1/R2 + 1/R3 = 1/2 + 1/3 + 1/5 = 0.8333, thus Req = 1.2Ω.

In series, R_eq = R1 + R2 + R3 = 2 + 3 + 6 = 11Ω.

1/R_eq = 1/R1 + 1/R2 + 1/R3 = 1/2 + 1/3 + 1/6 = 1. Therefore, R_eq = 1Ω.

1/R_eq = 1/R1 + 1/R2 + 1/R3 = 1/2 + 1/3 + 1/5 = 0.8333, thus R_eq = 1.2Ω.

1/Req = 1/R1 + 1/R2 + 1/R3 = 1/2 + 1/3 + 1/6 = 1. Therefore, Req = 1Ω.

In series, the equivalent resistance is the sum of the individual resistances: R_eq = R1 + R2 + R3 = 2Ω + 3Ω + 6Ω = 11Ω.

In a series connection, the total or equivalent resistance is the sum of the individual resistances.

In series, the equivalent resistance R_eq = R1 + R2 = 10 ohms + 20 ohms = 30 ohms.

Using the formula for parallel resistors, 1/R_eq = 1/R1 + 1/R2 = 1/4 + 1/12 = 1/3. Therefore, R_eq = 3Ω.

Using the formula for resistors in parallel, 1/R_eq = 1/R1 + 1/R2, we find R_eq = 1 / (1/5 + 1/10) = 3.33 ohms.

1/Req = 1/R1 + 1/R2 = 1/5 + 1/10 = 2/10 + 1/10 = 3/10. Therefore, Req = 10/3 = 3.33Ω.

In series, the equivalent resistance is the sum: R_eq = R1 + R2 = 6Ω + 3Ω = 9Ω.

In series, the equivalent resistance (R_eq) is the sum of the resistances: R_eq = 6Ω + 3Ω = 9Ω.

The escape velocity from the Earth's surface is approximately 11.2 km/s.

The escape velocity from the Earth's surface is approximately 11.2 km/s.

The escape velocity from the Earth's surface is approximately 11.2 km/s.

Escape velocity v = √(2GM/R); here, v = √(2 * 4GM / 3R) = √(8GM/3R).

Escape velocity v = √(2GM/R) = √(2 * 2M / 4R) = √(8GM/4R) = √(8GM/R)

Escape velocity is given by v = √(2GM/R).

The escape velocity from the surface of the Earth is approximately 11.2 km/s.

Escape velocity (v) = sqrt(2gR) = sqrt(2 * 9.8 * 6.4 x 10^6) ≈ 11.2 km/s.

The magnetic field at the center of a circular loop is given by B = μ₀I/(2R).

The magnetic field at the center of a circular loop of radius R carrying a current I is given by B = μ₀I/(2πR).

The magnetic field B at a distance r from a long straight wire carrying current I is given by B = (μ₀I)/(2πr).

The magnetic field B at a distance r from a long straight conductor carrying current I is given by B = (μ₀I)/(2πr).

Using the formula m1*T1 + m2*T2 = (m1 + m2)*Tf, we find Tf = (200*90 + 300*30) / (200 + 300) = 70°C.

The first law of thermodynamics states that energy cannot be created or destroyed, only transformed from one form to another.

For a concave lens, the focal length (f) is negative. The virtual image distance (v) is -20 cm. Using the lens formula 1/f = 1/v + 1/u, we can find f. Since v = -20 cm, we can assume u is at infinity, thus 1/f = 1/(-20) + 0, giving f = -20 cm.