Optics
Q. If two waves of equal amplitude interfere destructively, what is the phase difference between them?
A.
0 rad
B.
π/2 rad
C.
π rad
D.
3π/2 rad
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Solution
Destructive interference occurs when the phase difference is π rad.
Correct Answer: C — π rad
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Q. If two waves of equal amplitude interfere destructively, what is the resultant amplitude?
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Solution
For destructive interference, the resultant amplitude is zero when two equal amplitudes cancel each other out.
Correct Answer: A — 0
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Q. If two waves of equal amplitude interfere, what is the maximum intensity observed?
A.
A^2
B.
2A^2
C.
4A^2
D.
A
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Solution
Maximum intensity (I_max) = 4A^2 for two waves of equal amplitude A.
Correct Answer: B — 2A^2
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Q. If unpolarized light passes through a polarizer, what fraction of the light intensity is transmitted?
A.
0%
B.
25%
C.
50%
D.
100%
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Solution
When unpolarized light passes through a polarizer, 50% of the light intensity is transmitted.
Correct Answer: C — 50%
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Q. If unpolarized light passes through a polarizer, what is the intensity of the transmitted light?
A.
Zero
B.
Half of the original intensity
C.
Equal to the original intensity
D.
Twice the original intensity
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Solution
According to Malus's law, the intensity of transmitted light is half of the original intensity when unpolarized light passes through a polarizer.
Correct Answer: B — Half of the original intensity
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Q. If unpolarized light passes through a polarizer, what percentage of the light intensity will emerge?
A.
0%
B.
25%
C.
50%
D.
100%
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Solution
When unpolarized light passes through a polarizer, 50% of the light intensity will emerge, according to Malus's law.
Correct Answer: C — 50%
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Q. If unpolarized light passes through two polarizers at 90 degrees to each other, what is the intensity of the transmitted light?
A.
Same as incident light
B.
Half of the incident light
C.
Zero
D.
One quarter of the incident light
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Solution
When unpolarized light passes through two polarizers at 90 degrees, no light is transmitted, resulting in zero intensity.
Correct Answer: C — Zero
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Q. If unpolarized light passes through two polarizers, what is the maximum intensity of light transmitted?
A.
Zero
B.
Half of the original intensity
C.
Equal to the original intensity
D.
Dependent on the angle between the polarizers
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Solution
The maximum intensity transmitted through two polarizers is given by Malus's law, which states that I = I0 * cos²(θ), where θ is the angle between the polarizers.
Correct Answer: D — Dependent on the angle between the polarizers
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Q. In a compound microscope, which lens is the eyepiece?
A.
Convex lens
B.
Concave lens
C.
Bifocal lens
D.
Plano-convex lens
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Solution
The eyepiece of a compound microscope is a convex lens.
Correct Answer: A — Convex lens
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Q. In a compound microscope, which lens is the objective lens?
A.
The lens closest to the eye
B.
The lens closest to the object
C.
The lens with the longer focal length
D.
The lens with the shorter focal length
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Solution
The objective lens is the one closest to the object being viewed.
Correct Answer: B — The lens closest to the object
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Q. In a diffraction grating, if the number of slits is increased, what happens to the angular width of the principal maxima?
A.
Increases
B.
Decreases
C.
Remains the same
D.
Becomes zero
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Solution
Increasing the number of slits increases the sharpness of the maxima, thus decreasing the angular width.
Correct Answer: B — Decreases
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Q. In a diffraction grating, if the number of slits is increased, what happens to the sharpness of the maxima?
A.
Sharpness increases
B.
Sharpness decreases
C.
No effect
D.
Maxima disappear
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Solution
Increasing the number of slits in a diffraction grating increases the sharpness of the maxima due to constructive interference.
Correct Answer: A — Sharpness increases
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Q. In a diffraction grating, if the number of slits is increased, what happens to the intensity of the maxima?
A.
Increases
B.
Decreases
C.
Remains the same
D.
Becomes zero
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Solution
Increasing the number of slits increases the intensity of the maxima due to constructive interference.
Correct Answer: A — Increases
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Q. In a diffraction grating, what is the relationship between the angle of diffraction and the order of the maximum?
A.
Directly proportional
B.
Inversely proportional
C.
Independent
D.
Exponential
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Solution
The angle of diffraction is directly proportional to the order of the maximum in a diffraction grating.
Correct Answer: A — Directly proportional
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Q. In a diffraction pattern, how does the intensity of the maxima compare to the minima?
A.
Maxima are always brighter than minima
B.
Minima have the same intensity as maxima
C.
Minima are always darker than maxima
D.
Intensity is uniform throughout
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Solution
In a diffraction pattern, the minima are always darker than the maxima, which have higher intensity.
Correct Answer: C — Minima are always darker than maxima
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Q. In a diffraction pattern, if the first minimum occurs at an angle of 30°, what is the ratio of the slit width to the wavelength?
A.
1:2
B.
1:√3
C.
√3:1
D.
2:1
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Solution
Using the condition for the first minimum a sin(30°) = λ, we find the ratio a/λ = 1/√3.
Correct Answer: B — 1:√3
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Q. In a diffraction pattern, the intensity of the central maximum is how many times that of the first minimum?
A.
Zero
B.
One
C.
Infinity
D.
Two
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Solution
The intensity of the central maximum is theoretically infinite compared to the first minimum, which has zero intensity.
Correct Answer: C — Infinity
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Q. In a diffraction pattern, the intensity of the central maximum is typically:
A.
Zero
B.
Minimum
C.
Maximum
D.
Constant
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Solution
The intensity of the central maximum in a diffraction pattern is at its maximum compared to other maxima.
Correct Answer: C — Maximum
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Q. In a diffraction pattern, what does the intensity of the central maximum depend on?
A.
Wavelength only
B.
Slit width only
C.
Both wavelength and slit width
D.
Distance from the slit
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Solution
The intensity of the central maximum in a diffraction pattern depends on both the wavelength of light and the slit width.
Correct Answer: C — Both wavelength and slit width
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Q. In a diffraction pattern, what does the term 'fringe separation' refer to?
A.
Distance between two minima
B.
Distance between two maxima
C.
Distance between a maximum and a minimum
D.
None of the above
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Solution
Fringe separation refers to the distance between two consecutive maxima in a diffraction pattern.
Correct Answer: B — Distance between two maxima
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Q. In a diffraction pattern, what does the term 'order of diffraction' refer to?
A.
The number of slits used
B.
The number of maxima observed
C.
The wavelength of light used
D.
The distance to the screen
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Solution
The order of diffraction refers to the number of maxima observed in the diffraction pattern, with the central maximum being the zeroth order.
Correct Answer: B — The number of maxima observed
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Q. In a diffraction pattern, what is the effect of increasing the slit width?
A.
Wider central maximum
B.
Narrower central maximum
C.
No effect
D.
Increased number of fringes
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Solution
Increasing the slit width results in a wider central maximum due to the decrease in diffraction effects.
Correct Answer: A — Wider central maximum
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Q. In a diffraction pattern, what is the ratio of the intensity of the central maximum to that of the first minimum?
A.
1:0
B.
1:1
C.
1:2
D.
1:4
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Solution
The intensity of the central maximum is typically much greater than that of the first minimum, often approximated as 1:4.
Correct Answer: D — 1:4
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Q. In a double convex lens, if the radii of curvature are 10 cm and 15 cm, what is the focal length using the lens maker's formula?
A.
6 cm
B.
10 cm
C.
12 cm
D.
8 cm
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Solution
Using the lens maker's formula, f = (R1 * R2) / (n - 1) * (1/R1 - 1/R2), we find f = 12 cm.
Correct Answer: C — 12 cm
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Q. In a double-slit experiment, if the distance between the screen and the slits is increased, what happens to the fringe separation?
A.
It increases
B.
It decreases
C.
It remains the same
D.
It becomes zero
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Solution
Fringe separation is directly proportional to the distance from the slits to the screen; increasing this distance increases fringe separation.
Correct Answer: A — It increases
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Q. In a double-slit experiment, if the distance between the slits is 0.2 mm and the distance to the screen is 1 m, what is the fringe width for light of wavelength 600 nm?
A.
0.3 mm
B.
0.6 mm
C.
0.9 mm
D.
1.2 mm
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Solution
Fringe width β = λD/d = (600 x 10^-9 m)(1 m)/(0.2 x 10^-3 m) = 0.003 m = 0.6 mm.
Correct Answer: B — 0.6 mm
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Q. In a double-slit experiment, if the distance between the slits is 0.5 mm and the distance to the screen is 2 m, what is the distance between the first and second bright fringes if the wavelength of light used is 500 nm?
A.
0.5 cm
B.
1 cm
C.
1.5 cm
D.
2 cm
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Solution
Using the formula for fringe separation, y = (λD)/d, we find y = (500 x 10^-9 m * 2 m) / (0.5 x 10^-3 m) = 2 cm.
Correct Answer: B — 1 cm
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Q. In a double-slit experiment, if the distance between the slits is 0.5 mm and the wavelength of light is 400 nm, what is the distance between the first and second bright fringes?
A.
0.4 m
B.
0.8 m
C.
1.2 m
D.
1.6 m
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Solution
Distance between fringes = β = λD/d. For first and second bright fringes, the distance is 2β.
Correct Answer: B — 0.8 m
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Q. In a double-slit experiment, if the distance between the slits is doubled while keeping the wavelength constant, what happens to the fringe width?
A.
Doubles
B.
Halves
C.
Remains the same
D.
Quadruples
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Solution
Fringe width (β) is given by β = λD/d, where d is the distance between the slits. If d is doubled, β is halved.
Correct Answer: B — Halves
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Q. In a double-slit experiment, if the distance between the slits is doubled, how does the fringe width change?
A.
Doubles
B.
Halves
C.
Remains the same
D.
Quadruples
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Solution
Fringe width (β) is inversely proportional to the distance between the slits (d). If d is doubled, β is halved.
Correct Answer: B — Halves
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