The major product of hydrogenation of 2-butyne is butane.

The major product of the reaction of propene with HBr is 2-bromopropane due to Markovnikov's rule.

The reaction is an example of an SN2 reaction, leading to the formation of 1-ethoxybutane.

The major product of the reaction of propene with bromine is 2-bromopropane due to anti-addition.

The major product of the reaction of propene with HBr is 2-Bromopropane due to Markovnikov's rule.

Mass = moles × molar mass = 0.25 moles × 180 g/mol = 45 g.

Molar mass of CaCO3 = 40 + 12 + 16*3 = 100 g/mol. Mass = moles x molar mass = 0.5 moles x 100 g/mol = 50 g.

Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol. Mass = moles x molar mass = 0.5 moles x 58.5 g/mol = 29.25 g.

The molar mass of NaCl is 58 g/mol. Therefore, 0.5 moles of NaCl = 0.5 x 58 g = 29 g.

Molar mass of H2SO4 = 2*1 + 32 + 4*16 = 98 g/mol. Mass = moles x molar mass = 0.75 moles x 98 g/mol = 73.5 g.

The molar mass of water (H2O) is 18 g/mol (2*1 for H + 16 for O).

The molar mass of CO2 is 12 g/mol (C) + 16 g/mol x 2 (O) = 44 g/mol. Therefore, 2 moles of CO2 weigh 2 x 44 g = 88 g.

Molar mass of H2SO4 = 2*1 + 32 + 4*16 = 98 g/mol. Mass = 2 moles x 98 g/mol = 196 g.

The molar mass of CO2 is 12 g/mol (C) + 16 g/mol x 2 (O) = 44 g/mol. Therefore, 3 moles of CO2 weigh 3 x 44 g = 132 g.

Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol. Mass = moles x molar mass = 3 moles x 58.5 g/mol = 174 g.

Molar mass of H2SO4 = 2*1 + 32 + 4*16 = 98 g/mol. Mass = 3 moles x 98 g/mol = 294 g.

10 g of K = 0.25 moles. K + Cl2 → KCl, so 0.25 moles of KCl = 0.25 * 74.5 g = 18.625 g.

2 moles of H2 produce 2 moles of H2O. Mass of H2O = 2 moles * 18 g/mole = 36 g.

Mass percent = (mass of solute / total mass) x 100 = (20 g / (20 g + 180 g)) x 100 = 10%.

Mass percent = (mass of solute / mass of solution) x 100 = (20 g / 200 g) x 100 = 10%.

Mass percent = (mass of solute / mass of solution) × 100 = (20 g / 200 g) × 100 = 10%.

The maximum number of electrons in the n=2 shell is 2(2^2) = 8.

The maximum number of electrons in a shell is given by 2n^2. For n=4, it is 2(4^2) = 32.

The maximum number of electrons in a shell is given by 2n^2. For n=3, it is 2(3^2) = 18.

The maximum number of electrons in a shell is given by 2n^2. For n=5, it is 2(5^2) = 50.

The maximum number of electrons in a subshell is given by the formula 2(2l + 1). For l = 2, it is 2(2*2 + 1) = 10.

The maximum number of electrons in a shell is given by 2n^2. For n=2, this is 2(2^2) = 8.

The maximum number of electrons in a shell is given by 2n^2. For n=5, it is 2(5^2) = 50.

A p subshell can hold a maximum of 6 electrons.

A single orbital can hold a maximum of 2 electrons, with opposite spins.