Atomic Structure
Q. For an electron in a 3d orbital, what are the possible values of l?
Solution
For d orbitals, the azimuthal quantum number l = 2.
Correct Answer: C — 2
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Q. For an electron in a 3d orbital, what are the possible values of m_l?
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A.
-2, -1, 0, 1, 2
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B.
-1, 0, 1
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C.
0, 1
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D.
0, 1, 2
Solution
For l=2 (d orbital), m_l can take values from -l to +l, which are -2, -1, 0, 1, 2.
Correct Answer: A — -2, -1, 0, 1, 2
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Q. For an electron in a 3p orbital, what are the possible values of m_l?
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A.
-1, 0, +1
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B.
0, +1, +2
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C.
-2, -1, 0
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D.
0, -1, -2
Solution
For a p orbital, l=1, so m_l can take values -1, 0, +1.
Correct Answer: A — -1, 0, +1
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Q. For an electron in a 3p orbital, what are the possible values of the magnetic quantum number (m_l)?
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A.
-1, 0, +1
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B.
0, +1, +2
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C.
-2, -1, 0
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D.
1, 2, 3
Solution
For a p orbital (l=1), m_l can take values -1, 0, +1.
Correct Answer: A — -1, 0, +1
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Q. For an electron in a 5d orbital, what are the possible values of m_l?
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A.
-2, -1, 0, 1, 2
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B.
-3, -2, -1, 0, 1, 2, 3
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C.
0, 1, 2
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D.
-1, 0, 1
Solution
For l=2 (d orbital), m_l can take values from -2 to +2, which are -2, -1, 0, 1, 2.
Correct Answer: A — -2, -1, 0, 1, 2
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Q. For the quantum state with n=3, l=1, how many possible values can m_l take?
Solution
For l=1, m_l can take values -1, 0, 1, which gives 3 possible values.
Correct Answer: C — 3
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Q. If an electron has quantum numbers n=2, l=0, and m_l=0, which orbital does it occupy?
Solution
The quantum numbers correspond to the 2s orbital, where l=0 indicates an s orbital.
Correct Answer: A — 2s
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Q. If an electron has quantum numbers n=3, l=1, and m_l=-1, what is the possible value of the spin quantum number?
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A.
+1/2
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B.
-1/2
-
C.
0
-
D.
1
Solution
The spin quantum number can be either +1/2 or -1/2, so both values are possible.
Correct Answer: A — +1/2
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Q. If an electron has the quantum numbers n=3, l=1, m_l=0, what type of orbital does it occupy?
Solution
For l=1, the electron occupies a p orbital.
Correct Answer: B — p
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Q. If an electron has the quantum numbers n=3, l=1, m_l=0, what type of orbital is it in?
Solution
For l=1, the orbital is a p orbital.
Correct Answer: B — p
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Q. If an electron is in the state characterized by the quantum numbers n=4, l=0, what is the value of m_l?
Solution
For l=0, m_l can only be 0.
Correct Answer: A — 0
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Q. If an electron is in the state characterized by the quantum numbers n=4, l=2, what is the value of m_l?
-
A.
-2
-
B.
0
-
C.
2
-
D.
All of the above
Solution
For l=2, m_l can take values -2, -1, 0, 1, 2. Therefore, all of the options are valid.
Correct Answer: D — All of the above
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Q. If n=4 and l=2, what is the type of orbital?
Solution
For l=2, the orbital type is d.
Correct Answer: C — d
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Q. If the azimuthal quantum number l = 1, what is the shape of the orbital?
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A.
Spherical
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B.
Dumbbell
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C.
Double dumbbell
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D.
None of the above
Solution
The azimuthal quantum number l = 1 corresponds to p orbitals, which have a dumbbell shape.
Correct Answer: B — Dumbbell
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Q. If the principal quantum number n = 4 and the azimuthal quantum number l = 2, what is the maximum number of electrons in this subshell?
Solution
The maximum number of electrons in a subshell is given by 2(2l + 1). For l = 2, it is 2(2*2 + 1) = 10.
Correct Answer: C — 14
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Q. If the principal quantum number n = 4, what are the possible values of l?
-
A.
0, 1, 2, 3
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B.
1, 2, 3, 4
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C.
0, 1, 2, 3, 4
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D.
0, 1, 2
Solution
For n=4, l can take values 0, 1, 2, or 3.
Correct Answer: A — 0, 1, 2, 3
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Q. If the principal quantum number n = 4, what are the possible values of the azimuthal quantum number l?
-
A.
0, 1, 2, 3
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B.
1, 2, 3, 4
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C.
0, 1, 2, 3, 4
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D.
0, 1, 2
Solution
For n=4, l can take values from 0 to n-1, which are 0, 1, 2, and 3.
Correct Answer: A — 0, 1, 2, 3
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Q. In which of the following orbitals would an electron have the highest energy?
Solution
The 3s orbital has the highest principal quantum number (n=3), indicating it has the highest energy.
Correct Answer: D — 3s
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Q. What is the electron configuration of oxygen (O)?
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A.
1s2 2s2 2p4
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B.
1s2 2s2 2p6
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C.
1s2 2s1 2p5
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D.
1s2 2s2 2p3
Solution
The electron configuration of oxygen (atomic number 8) is 1s2 2s2 2p4.
Correct Answer: A — 1s2 2s2 2p4
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Q. What is the electronic configuration of a chlorine ion (Cl-)?
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A.
1s2 2s2 2p6 3s2 3p5
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B.
1s2 2s2 2p6
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C.
1s2 2s2 2p6 3s2 3p6
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D.
1s2 2s2 2p6 3s2 3p4
Solution
Chlorine ion (Cl-) has gained an electron, resulting in the configuration 1s2 2s2 2p6.
Correct Answer: B — 1s2 2s2 2p6
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Q. What is the electronic configuration of a neutral oxygen atom?
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A.
1s2 2s2 2p4
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B.
1s2 2s2 2p6
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C.
1s2 2s2 2p2
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D.
1s2 2s2 2p5
Solution
Oxygen has 8 electrons. The electronic configuration is 1s2 2s2 2p4.
Correct Answer: A — 1s2 2s2 2p4
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Q. What is the electronic configuration of a neutral sodium atom?
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A.
1s2 2s2 2p6 3s1
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B.
1s2 2s2 2p6
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C.
1s2 2s2 2p5
-
D.
1s2 2s2 2p6 3s2
Solution
Sodium has 11 electrons, and its configuration is 1s2 2s2 2p6 3s1.
Correct Answer: A — 1s2 2s2 2p6 3s1
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Q. What is the electronic configuration of a sodium ion (Na+)?
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A.
1s2 2s2 2p6
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B.
1s2 2s2 2p6 3s1
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C.
1s2 2s2 2p5
-
D.
1s2 2s2 2p6 3s2
Solution
Sodium ion (Na+) has lost one electron, resulting in the configuration 1s2 2s2 2p6.
Correct Answer: A — 1s2 2s2 2p6
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Q. What is the electronic configuration of Iron?
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A.
[Ar] 4s2 3d6
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B.
[Ar] 4s2 3d8
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C.
[Ar] 4s2 3d5
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D.
[Ar] 4s2 3d7
Solution
Iron (Fe) has the configuration [Ar] 4s2 3d6.
Correct Answer: A — [Ar] 4s2 3d6
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Q. What is the electronic configuration of oxygen?
-
A.
1s2 2s2 2p4
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B.
1s2 2s2 2p6
-
C.
1s2 2s2 2p2
-
D.
1s2 2s2 2p5
Solution
Oxygen has 8 electrons, and its electronic configuration is 1s2 2s2 2p4.
Correct Answer: A — 1s2 2s2 2p4
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Q. What is the electronic configuration of the chloride ion (Cl-)?
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A.
1s2 2s2 2p6 3s2 3p5
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B.
1s2 2s2 2p6 3s2 3p6
-
C.
1s2 2s2 2p6 3s2 3p4
-
D.
1s2 2s2 2p6 3s2 3p3
Solution
Chloride ion has gained one electron, making its configuration 1s2 2s2 2p6 3s2 3p6.
Correct Answer: B — 1s2 2s2 2p6 3s2 3p6
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Q. What is the electronic configuration of the element with atomic number 12?
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A.
[Ne] 3s2
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B.
[He] 2s2 2p6
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C.
[Ne] 3s1
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D.
[Ar] 4s2
Solution
The element with atomic number 12 is magnesium (Mg), and its electronic configuration is [Ne] 3s2.
Correct Answer: A — [Ne] 3s2
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Q. What is the electronic configuration of the element with atomic number 15?
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A.
[Ne] 3s2 3p3
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B.
[Ne] 3s2 3p4
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C.
[Ne] 3s2 3p5
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D.
[Ne] 3s2 3p2
Solution
The element with atomic number 15 is phosphorus (P), and its electronic configuration is [Ne] 3s2 3p3.
Correct Answer: A — [Ne] 3s2 3p3
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Q. What is the electronic configuration of the element with atomic number 17?
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A.
1s2 2s2 2p6 3s2 3p5
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B.
1s2 2s2 2p6 3s2 3p4
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C.
1s2 2s2 2p6 3s2 3p6
-
D.
1s2 2s2 2p6 3s2 3p3
Solution
Chlorine (Cl) has the configuration 1s2 2s2 2p6 3s2 3p5.
Correct Answer: A — 1s2 2s2 2p6 3s2 3p5
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Q. What is the electronic configuration of the element with atomic number 20?
-
A.
[Ne] 3s2 3p6
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B.
[Ar] 4s2
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C.
[He] 2s2 2p6 3s2 3p6
-
D.
[Ne] 3s2 3p4
Solution
The element with atomic number 20 is Calcium, which has the configuration [Ar] 4s2.
Correct Answer: B — [Ar] 4s2
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