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If the principal quantum number n = 4 and the azimuthal quantum number l = 2, wh
If the principal quantum number n = 4 and the azimuthal quantum number l = 2, what is the maximum number of electrons in this subshell?
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Q1
If the principal quantum number n = 4 and the azimuthal quantum number l = 2, what is the maximum number of electrons in this subshell?
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The maximum number of electrons in a subshell is given by 2(2l + 1). For l = 2, it is 2(2*2 + 1) = 10.
Questions & Step-by-step Solutions
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Q
Q: If the principal quantum number n = 4 and the azimuthal quantum number l = 2, what is the maximum number of electrons in this subshell?
Solution:
The maximum number of electrons in a subshell is given by 2(2l + 1). For l = 2, it is 2(2*2 + 1) = 10.
Steps: 6
Show Steps
Step 1: Identify the azimuthal quantum number l, which is given as l = 2.
Step 2: Use the formula for the maximum number of electrons in a subshell, which is 2(2l + 1).
Step 3: Substitute the value of l into the formula: 2(2*2 + 1).
Step 4: Calculate the value inside the parentheses: 2*2 = 4, then 4 + 1 = 5.
Step 5: Multiply by 2: 2 * 5 = 10.
Step 6: Conclude that the maximum number of electrons in this subshell is 10.
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