NaHCO3 is a weak base; its pH is around 8.4.

Using the Henderson-Hasselbalch equation, pH = pKa + log([A-]/[HA]). Here, pKa ≈ 4.74, so pH = 4.74 + log(1) = 4.74.

Using the Henderson-Hasselbalch equation: pH = pKa + log([A-]/[HA]) = 4.76 + log(0.1/0.2) = 5.74

Using the Henderson-Hasselbalch equation, pH = pKa + log([A-]/[HA]) = 4.76.

At 25°C, the pH of a neutral solution is 7.

A neutral solution has a pH of 7.

HCl and NaOH neutralize each other completely, resulting in a neutral solution with a pH of 7.

pH is calculated as pH = -log[H+]. For [H+] = 1 x 10^-5 M, pH = -log(1 x 10^-5) = 5.

pH is calculated as pH = -log[H3O+]. For [H3O+] = 1 x 10^-5 M, pH = -log(1 x 10^-5) = 5.

pOH = -log[OH-] = -log(1.0 x 10^-3) = 3. Therefore, pH = 14 - pOH = 14 - 3 = 11.

pH = -log[H+] = -log(1 x 10^-7) = 7.

Using Henderson-Hasselbalch equation: pH = pKa + log([A-]/[HA]); pKa of acetic acid = 4.76, so pH = 4.76 + log(1) = 4.76

pOH = -log[OH-] = -log(0.001) = 3; pH = 14 - pOH = 14 - 3 = 11

To find the pH, first calculate pOH = -log[OH-] = 4, then use pH + pOH = 14, so pH = 14 - 4 = 10.

Using the formula pH = -log[H+], we find pH = -log(1 x 10^-6) = 6.

In simple harmonic motion, acceleration is always opposite to displacement, hence the phase difference is 180 degrees.

In simple harmonic motion, the acceleration is always directed towards the mean position and is 180 degrees out of phase with the displacement.

In simple harmonic motion, acceleration is 180 degrees out of phase with displacement.

At resonance, the phase difference is 90°.

At resonance, the phase difference between the driving force and the displacement is 180 degrees.

At resonance, the phase difference between the driving force and the displacement is 0 degrees.

If two particles are in the same position at the same time in simple harmonic motion, they have a phase difference of 0.

When two particles are in phase, they reach their maximum and minimum displacements at the same time, resulting in a phase difference of 0 radians.

A phase difference of 90 degrees corresponds to π/2 radians.

The phase difference between two points in the same wave separated by a distance of λ/2 is π radians.

The phase difference Δφ between two points separated by a distance of λ/4 is given by Δφ = (2π/λ)(λ/4) = π/2 radians.

The phase difference between two points that are half a wavelength apart is π radians.

The phase difference between two points on a wave that are one wavelength apart is 2π radians.

A phase difference of 180° corresponds to the waves being out of phase, leading to destructive interference.

When two waves are in phase, their phase difference is 0 radians.