Q. What is the moment of inertia of a thin wire bent in the shape of a semicircle of radius R and mass M about the diameter?
A.
1/2 MR^2
B.
1/4 MR^2
C.
MR^2
D.
3/8 MR^2
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Solution
The moment of inertia of a thin wire bent in the shape of a semicircle about the diameter is I = 3/8 MR^2.
Correct Answer: D — 3/8 MR^2
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Q. What is the moment of inertia of a uniform rectangular plate of mass M and dimensions a x b about an axis through its center and parallel to side a?
A.
1/12 Ma^2
B.
1/12 Mb^2
C.
1/3 Ma^2
D.
1/3 Mb^2
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Solution
The moment of inertia of a rectangular plate about an axis through its center and parallel to side a is I = 1/3 Mb^2.
Correct Answer: D — 1/3 Mb^2
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Q. What is the moment of inertia of a uniform thin circular plate of mass M and radius R about an axis through its center and perpendicular to its plane?
A.
1/2 MR^2
B.
MR^2
C.
1/4 MR^2
D.
2/5 MR^2
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Solution
The moment of inertia of a uniform thin circular plate about an axis through its center and perpendicular to its plane is I = 1/2 MR^2.
Correct Answer: A — 1/2 MR^2
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Q. What is the moment of inertia of a uniform thin square plate of mass M and side length a about an axis through its center and parallel to one of its sides?
A.
1/6 Ma²
B.
1/12 Ma²
C.
1/4 Ma²
D.
1/3 Ma²
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Solution
The moment of inertia of a square plate about an axis through its center and parallel to one side is I = 1/12 Ma².
Correct Answer: B — 1/12 Ma²
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Q. What is the moment of inertia of a uniform triangular lamina of mass M and base b about an axis perpendicular to the base and passing through its centroid?
A.
1/18 Mb^2
B.
1/12 Mb^2
C.
1/6 Mb^2
D.
1/24 Mb^2
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Solution
The moment of inertia of a triangular lamina about an axis through its centroid is I = 1/12 Mb^2.
Correct Answer: B — 1/12 Mb^2
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Q. What is the name of the reaction where benzene is converted to phenol?
A.
Hydrogenation
B.
Nitration
C.
Sulfonation
D.
Hydroxylation
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Solution
The conversion of benzene to phenol is known as hydroxylation, typically involving the addition of a hydroxyl group (-OH) to the aromatic ring.
Correct Answer: D — Hydroxylation
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Q. What is the nature of the image formed by a concave lens when the object is placed at infinity?
A.
Real and inverted
B.
Virtual and upright
C.
Real and upright
D.
Virtual and inverted
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Solution
A concave lens always produces a virtual and upright image regardless of the object's position.
Correct Answer: B — Virtual and upright
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Q. What is the nature of the image formed by a concave lens?
A.
Real and inverted
B.
Real and upright
C.
Virtual and upright
D.
Virtual and inverted
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Solution
A concave lens always forms a virtual and upright image.
Correct Answer: C — Virtual and upright
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Q. What is the nature of the image formed by a concave mirror when the object is placed beyond the center of curvature?
A.
Real and inverted
B.
Virtual and upright
C.
Real and upright
D.
Virtual and inverted
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Solution
When the object is beyond the center of curvature, the image formed is real and inverted.
Correct Answer: A — Real and inverted
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Q. What is the nature of the image formed by a convex lens when the object is placed beyond the focal length?
A.
Virtual and erect
B.
Real and inverted
C.
Real and erect
D.
Virtual and inverted
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Solution
When an object is placed beyond the focal length of a convex lens, the image formed is real and inverted.
Correct Answer: B — Real and inverted
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Q. What is the nature of the image formed by a convex lens when the object is placed at twice the focal length?
A.
Real and inverted
B.
Virtual and erect
C.
Real and erect
D.
Virtual and inverted
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Solution
When the object is at 2f, the image is formed at 2f on the opposite side, making it real and inverted.
Correct Answer: A — Real and inverted
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Q. What is the nature of the image formed by a convex lens when the object is placed beyond the focal point?
A.
Virtual and upright
B.
Real and inverted
C.
Real and upright
D.
Virtual and inverted
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Solution
When the object is beyond the focal point, the image formed by a convex lens is real and inverted.
Correct Answer: B — Real and inverted
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Q. What is the nature of the image formed by a convex lens when the object is placed at infinity?
A.
Real and inverted
B.
Virtual and upright
C.
Real and upright
D.
Virtual and inverted
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Solution
When the object is at infinity, the rays converge at the focal point, forming a real and inverted image.
Correct Answer: A — Real and inverted
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Q. What is the nature of the image formed by a convex lens when the object is placed at a distance greater than twice the focal length?
A.
Real and inverted
B.
Virtual and upright
C.
Real and upright
D.
Virtual and inverted
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Solution
When the object is placed beyond 2f, the image formed by a convex lens is real and inverted.
Correct Answer: A — Real and inverted
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Q. What is the nature of the image formed by a convex mirror?
A.
Real and inverted
B.
Virtual and upright
C.
Real and upright
D.
Virtual and inverted
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Solution
A convex mirror always forms a virtual image that is upright and smaller than the object.
Correct Answer: B — Virtual and upright
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Q. What is the nature of the image formed by a plane mirror?
A.
Real and inverted
B.
Virtual and erect
C.
Real and erect
D.
Virtual and inverted
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Solution
A plane mirror always forms a virtual and erect image, as the image appears behind the mirror at the same distance as the object.
Correct Answer: B — Virtual and erect
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Q. What is the Nernst equation used for?
A.
Calculating pH
B.
Determining cell potential
C.
Finding molarity
D.
Measuring temperature
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Solution
The Nernst equation is used to determine the cell potential under non-standard conditions.
Correct Answer: B — Determining cell potential
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Q. What is the net force acting on an object at rest?
A.
Zero
B.
Equal to its weight
C.
Equal to its mass
D.
Equal to the applied force
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Solution
An object at rest has no net force acting on it, according to Newton's first law.
Correct Answer: A — Zero
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Q. What is the normality of a solution containing 1 mole of H2SO4 in 1 liter of solution?
A.
1 N
B.
2 N
C.
0.5 N
D.
4 N
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Solution
Normality (N) = equivalents of solute / liters of solution. H2SO4 provides 2 equivalents, so N = 2 moles / 1 L = 2 N.
Correct Answer: B — 2 N
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Q. What is the normality of a solution containing 2 moles of H2SO4 in 1 liter of solution?
A.
2 N
B.
4 N
C.
1 N
D.
0.5 N
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Solution
Normality (N) = equivalents of solute / liters of solution. H2SO4 provides 2 equivalents, so 2 moles × 2 = 4 N.
Correct Answer: B — 4 N
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Q. What is the normality of a solution containing 3 moles of H2SO4 in 2 liters of solution? (H2SO4 is a diprotic acid)
A.
3 N
B.
6 N
C.
1.5 N
D.
1 N
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Solution
Normality (N) = equivalents of solute / liters of solution. H2SO4 has 2 equivalents per mole, so 3 moles = 6 equivalents. Normality = 6 equivalents / 2 L = 3 N.
Correct Answer: B — 6 N
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Q. What is the normality of a solution containing 4 moles of H2SO4 in 2 liters of solution?
A.
4 N
B.
8 N
C.
2 N
D.
1 N
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Solution
Normality (N) = equivalents of solute / liters of solution. H2SO4 has 2 equivalents, so 4 moles = 8 equivalents. N = 8 eq / 2 L = 4 N.
Correct Answer: B — 8 N
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Q. What is the normality of a solution containing 4 moles of H2SO4 in 2 liters of solution? (H2SO4 is a diprotic acid)
A.
4 N
B.
2 N
C.
8 N
D.
1 N
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Solution
Normality (N) = number of equivalents / liters of solution. H2SO4 has 2 equivalents per mole, so 4 moles = 8 equivalents. Normality = 8 equivalents / 2 L = 4 N.
Correct Answer: C — 8 N
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Q. What is the normality of a solution that is 1 M in H2SO4?
A.
1 N
B.
2 N
C.
0.5 N
D.
4 N
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Solution
Normality (N) = Molarity (M) x number of equivalents. H2SO4 has 2 acidic protons, so 1 M x 2 = 2 N.
Correct Answer: B — 2 N
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Q. What is the number of atoms in 2 moles of aluminum (Al)? (2044)
A.
6.022 x 10^23
B.
1.2044 x 10^24
C.
3.011 x 10^23
D.
12.044 x 10^24
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Solution
Number of atoms = moles x Avogadro's number = 2 moles x 6.022 x 10^23 atoms/mole = 1.2044 x 10^24 atoms.
Correct Answer: B — 1.2044 x 10^24
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Q. What is the number of atoms in 2 moles of CaCO3?
A.
6.022 x 10^23
B.
1.2044 x 10^24
C.
3.011 x 10^23
D.
1.8066 x 10^24
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Solution
Each CaCO3 has 5 atoms (1 Ca, 1 C, 3 O). Number of atoms = moles x atoms per molecule x Avogadro's number = 2 moles x 5 x 6.022 x 10^23 = 1.206 x 10^24 atoms.
Correct Answer: D — 1.8066 x 10^24
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Q. What is the number of atoms in 2 moles of Na2SO4?
A.
6.022 x 10^23
B.
1.2044 x 10^24
C.
1.2044 x 10^25
D.
3.011 x 10^23
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Solution
Na2SO4 has 2 Na + 1 S + 4 O = 7 atoms. Number of atoms = moles x atoms per mole = 2 moles x 7 atoms = 14 atoms = 1.2044 x 10^24 atoms.
Correct Answer: B — 1.2044 x 10^24
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Q. What is the number of atoms in 2 moles of NaCl? (2044)
A.
6.022 x 10^23
B.
1.2044 x 10^24
C.
1.2044 x 10^25
D.
3.011 x 10^23
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Solution
Each NaCl unit has 2 atoms (Na and Cl). Therefore, 2 moles of NaCl contain 2 x 6.022 x 10^23 x 2 = 1.2044 x 10^24 atoms.
Correct Answer: B — 1.2044 x 10^24
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Q. What is the number of moles in 10 grams of Na?
A.
0.43
B.
0.22
C.
0.5
D.
0.1
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Solution
Molar mass of Na = 23 g/mol. Number of moles = mass / molar mass = 10 g / 23 g/mol = 0.43 moles.
Correct Answer: A — 0.43
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Q. What is the number of moles in 10 grams of NaOH?
A.
0.25
B.
0.5
C.
0.75
D.
1
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Solution
Molar mass of NaOH = 23 + 16 + 1 = 40 g/mol. Number of moles = mass/molar mass = 10 g / 40 g/mol = 0.25 moles.
Correct Answer: B — 0.5
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