Q. A capacitor of capacitance 10 microfarads is charged to a voltage of 5 volts. What is the charge stored in the capacitor?
A.
50 microcoulombs
B.
5 microcoulombs
C.
0.5 microcoulombs
D.
100 microcoulombs
Show solution
Solution
Charge (Q) is given by Q = C * V. Thus, Q = 10 µF * 5 V = 50 µC.
Correct Answer: A — 50 microcoulombs
Learn More →
Q. A capacitor stores 5 microfarads of charge at a voltage of 10 volts. What is the energy stored in the capacitor?
A.
0.25 mJ
B.
0.5 mJ
C.
0.75 mJ
D.
1 mJ
Show solution
Solution
The energy stored in a capacitor is given by the formula E = 0.5 * C * V^2. Here, E = 0.5 * 5 * 10^-6 F * (10 V)^2 = 0.5 * 5 * 10^-6 * 100 = 0.25 mJ.
Correct Answer: B — 0.5 mJ
Learn More →
Q. If a circuit has a resistance of 5 ohms and a current of 2 amperes, what is the voltage across the circuit?
A.
10 V
B.
5 V
C.
2 V
D.
1 V
Show solution
Solution
Using Ohm's Law (V = I * R), V = 2 A * 5 Ω = 10 V.
Correct Answer: A — 10 V
Learn More →
Q. If a wire carries a current of 3 A and has a resistance of 2 ohms, what is the power dissipated in the wire?
A.
6 W
B.
9 W
C.
12 W
D.
15 W
Show solution
Solution
Power is given by P = I^2 * R. Here, P = (3 A)^2 * 2 Ω = 9 * 2 = 18 W.
Correct Answer: C — 12 W
Learn More →
Q. In a parallel circuit with two resistors of 6 ohms and 3 ohms, what is the total resistance?
A.
2 ohms
B.
4 ohms
C.
1.5 ohms
D.
9 ohms
Show solution
Solution
The total resistance in parallel is given by 1/R_total = 1/R1 + 1/R2. Thus, 1/R_total = 1/6 + 1/3 = 1/2, so R_total = 2 ohms.
Correct Answer: A — 2 ohms
Learn More →
Q. In a series circuit with a 12 V battery and two resistors of 4 Ω and 8 Ω, what is the current flowing through the circuit?
A.
0.5 A
B.
1 A
C.
1.5 A
D.
2 A
Show solution
Solution
Total resistance R_total = R1 + R2 = 4 Ω + 8 Ω = 12 Ω. Using Ohm's Law, I = V/R = 12 V / 12 Ω = 1 A.
Correct Answer: B — 1 A
Learn More →
Q. What is the equivalent resistance of two resistors of 4 ohms and 6 ohms connected in series?
A.
10 ohms
B.
24 ohms
C.
2.4 ohms
D.
0.67 ohms
Show solution
Solution
In series, the equivalent resistance is the sum: R_eq = R1 + R2 = 4 Ω + 6 Ω = 10 Ω.
Correct Answer: A — 10 ohms
Learn More →
Q. What is the equivalent resistance of two resistors of 4 ohms and 6 ohms in series?
A.
10 ohms
B.
24 ohms
C.
2.4 ohms
D.
0.67 ohms
Show solution
Solution
In series, the equivalent resistance is the sum: R_eq = R1 + R2 = 4 Ω + 6 Ω = 10 Ω.
Correct Answer: A — 10 ohms
Learn More →
Q. What is the formula for calculating the capacitance of a parallel plate capacitor?
A.
C = εA/d
B.
C = A/εd
C.
C = d/εA
D.
C = εd/A
Show solution
Solution
The capacitance (C) of a parallel plate capacitor is given by C = εA/d, where ε is the permittivity, A is the area of the plates, and d is the distance between them.
Correct Answer: A — C = εA/d
Learn More →
Q. What is the magnetic field strength at the center of a circular loop of radius 0.1 m carrying a current of 5 A?
A.
0.1 T
B.
0.2 T
C.
0.5 T
D.
1 T
Show solution
Solution
The magnetic field at the center of a circular loop is given by B = (μ₀ * I) / (2 * R). Using μ₀ = 4π x 10^-7 Tm/A, B = (4π x 10^-7 * 5) / (2 * 0.1) = 0.1 T.
Correct Answer: B — 0.2 T
Learn More →
Q. What is the magnetic field strength at the center of a circular loop of radius r carrying a current I?
A.
μ0I/2r
B.
μ0I/r
C.
μ0I/4r
D.
μ0I/πr
Show solution
Solution
The magnetic field at the center of a circular loop is given by B = (μ0I)/(2r).
Correct Answer: B — μ0I/r
Learn More →
Q. What is the power consumed by a device that operates at a voltage of 120 volts and draws a current of 3 amperes?
A.
360 watts
B.
40 watts
C.
120 watts
D.
240 watts
Show solution
Solution
Power (P) is calculated as P = V * I. Thus, P = 120 V * 3 A = 360 W.
Correct Answer: A — 360 watts
Learn More →
Q. What is the resistance of a wire of length 2 m and cross-sectional area 1 mm² if the resistivity of the material is 1.7 x 10^-8 Ωm?
A.
0.034 Ω
B.
0.017 Ω
C.
0.068 Ω
D.
0.085 Ω
Show solution
Solution
Resistance R = ρ * (L/A). Here, R = (1.7 x 10^-8 Ωm) * (2 m / (1 x 10^-6 m²)) = 0.034 Ω.
Correct Answer: A — 0.034 Ω
Learn More →
Q. What is the total capacitance of two capacitors of 3 µF and 6 µF connected in parallel?
A.
2 µF
B.
3 µF
C.
9 µF
D.
18 µF
Show solution
Solution
In parallel, the total capacitance is the sum: C_total = C1 + C2 = 3 µF + 6 µF = 9 µF.
Correct Answer: C — 9 µF
Learn More →
Showing 1 to 14 of 14 (1 Pages)
