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In a series circuit with a 12 V battery and two resistors of 4 Ω and 8 Ω, what i
In a series circuit with a 12 V battery and two resistors of 4 Ω and 8 Ω, what is the current flowing through the circuit?
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Q1
In a series circuit with a 12 V battery and two resistors of 4 Ω and 8 Ω, what is the current flowing through the circuit?
0.5 A
1 A
1.5 A
2 A
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Total resistance R_total = R1 + R2 = 4 Ω + 8 Ω = 12 Ω. Using Ohm's Law, I = V/R = 12 V / 12 Ω = 1 A.
Questions & Step-by-step Solutions
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Q
Q: In a series circuit with a 12 V battery and two resistors of 4 Ω and 8 Ω, what is the current flowing through the circuit?
Solution:
Total resistance R_total = R1 + R2 = 4 Ω + 8 Ω = 12 Ω. Using Ohm's Law, I = V/R = 12 V / 12 Ω = 1 A.
Steps: 7
Show Steps
Step 1: Identify the voltage of the battery, which is 12 V.
Step 2: Identify the resistors in the circuit, which are 4 Ω and 8 Ω.
Step 3: Calculate the total resistance in the circuit by adding the resistances together: R_total = R1 + R2 = 4 Ω + 8 Ω.
Step 4: Perform the addition: R_total = 4 Ω + 8 Ω = 12 Ω.
Step 5: Use Ohm's Law to find the current: I = V / R_total.
Step 6: Substitute the values into the formula: I = 12 V / 12 Ω.
Step 7: Perform the division: I = 1 A.
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