Q. A 1 kg block of ice at 0°C is placed in 2 kg of water at 20°C. What will be the final temperature of the mixture? (Assume no heat loss to the surroundings)
A.0°C
B.10°C
C.15°C
D.20°C
Solution
Using the principle of conservation of energy, the heat lost by water equals the heat gained by ice. Final temperature can be calculated to be approximately 10°C.
Q. A 1 kg block of ice at 0°C is placed in 2 kg of water at 20°C. What will be the final temperature of the mixture? (Specific heat of water = 4.2 kJ/kg°C, Latent heat of fusion of ice = 334 kJ/kg) (2021)
A.0°C
B.10°C
C.20°C
D.15°C
Solution
Heat lost by water = Heat gained by ice. Calculate to find the final temperature.
Q. A 1 kg block of ice at 0°C is placed in 2 kg of water at 80°C. What will be the final temperature of the mixture? (Assume no heat loss to the surroundings) (2019)
A.0°C
B.40°C
C.60°C
D.80°C
Solution
Using the principle of conservation of energy, the heat lost by water equals the heat gained by ice. The final temperature will be 0°C as the ice will melt.
Q. A 1 kg block of metal at 100°C is placed in 2 kg of water at 20°C. Assuming no heat loss to the surroundings, what will be the final temperature? (Specific heat of water = 4.2 kJ/kg°C) (2022)
A.25°C
B.30°C
C.35°C
D.40°C
Solution
Using the principle of conservation of energy, set heat lost by metal equal to heat gained by water to find the final temperature.
Q. A 1 kg block of metal at 100°C is placed in 2 kg of water at 20°C. Assuming no heat loss to the surroundings, what is the final temperature of the system? (Specific heat of water = 4.18 kJ/kg°C, specific heat of metal = 0.9 kJ/kg°C) (2020)
A.25°C
B.30°C
C.35°C
D.40°C
Solution
Using the principle of conservation of energy, set heat lost by metal equal to heat gained by water to find the final temperature.
Q. A 1 kg block of metal at 100°C is placed in 2 kg of water at 20°C. If the final temperature of the system is 30°C, what is the specific heat capacity of the metal? (Specific heat of water = 4.18 J/g°C) (2020)
A.0.5 J/g°C
B.1.0 J/g°C
C.1.5 J/g°C
D.2.0 J/g°C
Solution
Using the principle of conservation of energy, calculate the specific heat capacity of the metal.
Q. A 1 kg block of metal at 100°C is placed in 2 kg of water at 20°C. What is the final temperature of the system? (Specific heat of water = 4.18 J/g°C, specific heat of metal = 0.9 J/g°C) (2021)
A.25°C
B.30°C
C.35°C
D.40°C
Solution
Using conservation of energy: m1*c1*(T_initial - T_final) = m2*c2*(T_final - T_initial). Solving gives T_final = 35°C.
Q. A 100 g piece of metal at 100°C is placed in 200 g of water at 20°C. What will be the final temperature of the system? (Specific heat of water = 4.2 J/g°C, specific heat of metal = 0.5 J/g°C) (2023)
A.30°C
B.40°C
C.50°C
D.60°C
Solution
Using the heat transfer equation, we can find the final temperature to be 50°C.
