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A 10 kg object is at rest. A force of 30 N is applied. What is the final velocit
A 10 kg object is at rest. A force of 30 N is applied. What is the final velocity after 3 seconds? (2023)
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Q1
A 10 kg object is at rest. A force of 30 N is applied. What is the final velocity after 3 seconds? (2023)
3 m/s
6 m/s
9 m/s
12 m/s
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Using F = ma, a = F/m = 30 N / 10 kg = 3 m/s². Final velocity v = u + at = 0 + 3 m/s² × 3 s = 9 m/s.
Questions & Step-by-step Solutions
1 item
Q
Q: A 10 kg object is at rest. A force of 30 N is applied. What is the final velocity after 3 seconds? (2023)
Solution:
Using F = ma, a = F/m = 30 N / 10 kg = 3 m/s². Final velocity v = u + at = 0 + 3 m/s² × 3 s = 9 m/s.
Steps: 9
Show Steps
Step 1: Identify the mass of the object. The mass (m) is 10 kg.
Step 2: Identify the force applied to the object. The force (F) is 30 N.
Step 3: Use the formula F = ma to find the acceleration (a). Rearranging gives a = F/m.
Step 4: Substitute the values into the formula: a = 30 N / 10 kg.
Step 5: Calculate the acceleration: a = 3 m/s².
Step 6: Identify the initial velocity (u). Since the object is at rest, u = 0 m/s.
Step 7: Use the formula for final velocity: v = u + at.
Step 8: Substitute the values into the formula: v = 0 + (3 m/s² × 3 s).
Step 9: Calculate the final velocity: v = 9 m/s.
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