Current Electricity Study Materials for Competitive Exams

Current Electricity

Circuits & Kirchhoff Laws Ohms Law Potentiometer Resistivity Wheatstone Bridge

Q. In a circuit with a 24V battery and two resistors in series (R1 = 8Ω, R2 = 16Ω), what is the voltage across R2?

A. 16V
B. 8V
C. 12V
D. 4V

Solution

Using voltage division, V_R2 = V_total * (R2 / (R1 + R2)) = 24V * (16Ω / (8Ω + 16Ω)) = 16V.

Correct Answer: A — 16V

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Q. In a circuit with a 24V battery and two resistors in series (R1 = 8Ω, R2 = 16Ω), what is the current flowing through the circuit?

A. 1A
B. 2A
C. 3A
D. 4A

Solution

Total resistance R_total = R1 + R2 = 8Ω + 16Ω = 24Ω. The current is I = V/R_total = 24V / 24Ω = 1A.

Correct Answer: B — 2A

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Q. In a circuit with a 24V battery and two resistors of 4Ω and 8Ω in series, what is the voltage across the 8Ω resistor?

A. 8V
B. 12V
C. 16V
D. 20V

Solution

Voltage across R2 = (R2 / (R1 + R2)) * V = (8 / (4 + 8)) * 24 = 16V.

Correct Answer: B — 12V

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Q. In a circuit with a 24V battery and two resistors of 6Ω and 12Ω in series, what is the voltage across the 12Ω resistor?

A. 8V
B. 12V
C. 16V
D. 6V

Solution

Voltage across R2 = (R2/(R1+R2)) * V = (12/(6+12)) * 24 = 12V.

Correct Answer: B — 12V

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Q. In a circuit with a 24V battery and two resistors of 8 ohms and 16 ohms in series, what is the total current in the circuit?

A. 1 A
B. 2 A
C. 3 A
D. 4 A

Solution

Total resistance R_total = 8 + 16 = 24 ohms. Current I = V/R_total = 24V / 24Ω = 1 A.

Correct Answer: B — 2 A

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Q. In a circuit with a 24V battery and two resistors of 8 ohms and 16 ohms in series, what is the current flowing through the circuit?

A. 1 A
B. 2 A
C. 3 A
D. 4 A

Solution

Total resistance R = 8 + 16 = 24 ohms. Current I = V/R = 24V / 24Ω = 1 A.

Correct Answer: B — 2 A

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Q. In a circuit with a 24V battery and two resistors of 8 ohms and 4 ohms in series, what is the current flowing through the circuit?

A. 1 A
B. 2 A
C. 3 A
D. 4 A

Solution

Total resistance R_total = 8 + 4 = 12 ohms. Current I = V/R_total = 24V / 12Ω = 2 A.

Correct Answer: B — 2 A

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Q. In a circuit with a 24V battery and two resistors of 8Ω and 16Ω in series, what is the voltage across the 16Ω resistor?

A. 8V
B. 12V
C. 16V
D. 24V

Solution

Voltage across R2 = (R2/(R1+R2)) * V = (16/(8+16)) * 24 = 16V.

Correct Answer: B — 12V

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Q. In a circuit with a 24V battery and two resistors of 8Ω and 4Ω in series, what is the voltage across the 4Ω resistor?

A. 6V
B. 8V
C. 12V
D. 16V

Solution

Using the voltage divider rule, V_R2 = (R2 / (R1 + R2)) * Vtotal = (4 / (8 + 4)) * 24 = 8V.

Correct Answer: C — 12V

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Q. In a circuit with a 24V battery and two resistors of 8Ω and 4Ω in series, what is the current flowing through the circuit?

A. 2A
B. 3A
C. 4A
D. 6A

Solution

Total resistance R_total = 8Ω + 4Ω = 12Ω. Current I = V/R_total = 24V / 12Ω = 2A.

Correct Answer: B — 3A

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Q. In a circuit with a 5V battery and two resistors in parallel (5Ω and 10Ω), what is the current through the 10Ω resistor?

A. 0.5A
B. 1A
C. 1.5A
D. 2A

Solution

Using Ohm's Law, I = V/R = 5V / 10Ω = 0.5A.

Correct Answer: B — 1A

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Q. In a circuit with a 6Ω and a 3Ω resistor in parallel, what is the equivalent resistance?

A. 2Ω
B. 4Ω
C. 1.5Ω
D. 9Ω

Solution

Using the formula for parallel resistors, 1/R_eq = 1/6 + 1/3 = 1/2, R_eq = 2Ω.

Correct Answer: A — 2Ω

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Q. In a circuit with a 9 V battery and a 3 ohm resistor, what is the current flowing through the circuit?

A. 3 A
B. 2 A
C. 1 A
D. 4 A

Solution

Using Ohm's law, I = V / R = 9 V / 3 ohms = 3 A.

Correct Answer: B — 2 A

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Q. In a circuit with a 9V battery and three resistors (3Ω, 3Ω, and 3Ω) in series, what is the voltage across each resistor?

A. 3V
B. 6V
C. 9V
D. 1V

Solution

In a series circuit, the voltage is divided equally among the resistors. Therefore, V across each 3Ω resistor = 9V / 3 = 3V.

Correct Answer: A — 3V

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Q. In a circuit with a 9V battery and three resistors in series (2Ω, 3Ω, and 5Ω), what is the total resistance?

A. 5Ω
B. 8Ω
C. 10Ω
D. 15Ω

Solution

Total resistance R = R1 + R2 + R3 = 2Ω + 3Ω + 5Ω = 10Ω.

Correct Answer: C — 10Ω

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Q. In a circuit with a 9V battery and three resistors of 3Ω, 3Ω, and 6Ω in parallel, what is the total current supplied by the battery?

A. 1A
B. 2A
C. 3A
D. 4A

Solution

1/R_eq = 1/3 + 1/3 + 1/6 = 1. Therefore, R_eq = 1Ω. Total current I = V/R_eq = 9V/1Ω = 9A.

Correct Answer: C — 3A

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Q. In a circuit with a 9V battery and two resistors (R1 = 3Ω, R2 = 6Ω) in series, what is the current flowing through the circuit?

A. 1A
B. 2A
C. 3A
D. 0.5A

Solution

Total resistance R_total = R1 + R2 = 3Ω + 6Ω = 9Ω. Current I = V/R = 9V/9Ω = 1A.

Correct Answer: B — 2A

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Q. In a circuit with a 9V battery and two resistors in series (R1 = 3Ω, R2 = 6Ω), what is the voltage across R2?

A. 6V
B. 3V
C. 9V
D. 0V

Solution

Using voltage division, V_R2 = (R2 / (R1 + R2)) * V_total = (6Ω / (3Ω + 6Ω)) * 9V = 6V.

Correct Answer: A — 6V

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Q. In a circuit with a 9V battery and two resistors of 3 ohms and 6 ohms in parallel, what is the equivalent resistance?

A. 2 ohms
B. 3 ohms
C. 4 ohms
D. 1.5 ohms

Solution

1/R_eq = 1/R1 + 1/R2 = 1/3 + 1/6 = 1/2, R_eq = 2 ohms.

Correct Answer: A — 2 ohms

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Q. In a circuit with a 9V battery and two resistors of 3 ohms and 6 ohms in series, what is the voltage drop across the 6 ohm resistor?

A. 6V
B. 3V
C. 9V
D. 4.5V

Solution

The total resistance is 9 ohms. The current is I = V/R = 9V / 9 ohms = 1 A. The voltage drop across the 6 ohm resistor is V = I * R = 1 A * 6 ohms = 6V.

Correct Answer: A — 6V

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Q. In a circuit with three resistors in series (2 ohms, 3 ohms, and 5 ohms), what is the total resistance?

A. 10 ohms
B. 5 ohms
C. 3 ohms
D. 2 ohms

Solution

For resistors in series, R_total = R1 + R2 + R3 = 2 + 3 + 5 = 10 ohms.

Correct Answer: A — 10 ohms

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Q. In a circuit with three resistors R1, R2, and R3 connected in series, if R1 = 2Ω, R2 = 3Ω, and R3 = 5Ω, what is the total resistance?

A. 5Ω
B. 10Ω
C. 8Ω
D. 3Ω

Solution

Total resistance in series is R_total = R1 + R2 + R3 = 2Ω + 3Ω + 5Ω = 10Ω.

Correct Answer: B — 10Ω

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Q. In a circuit with two loops, if the current in the first loop is 2 A and in the second loop is 3 A, what is the total current entering a junction where these loops meet?

A. 1 A
B. 5 A
C. 6 A
D. 2 A

Solution

According to Kirchhoff's current law, the total current entering a junction equals the total current leaving it. Therefore, total current = 2 A + 3 A = 5 A.

Correct Answer: B — 5 A

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Q. In a circuit with two loops, if the current in the first loop is 5 A and the second loop is 3 A, what is the current through a shared resistor of 2 ohms?

A. 1 A
B. 2 A
C. 3 A
D. 5 A

Solution

The current through the shared resistor is the difference of the currents in the loops, so 5 A - 3 A = 2 A.

Correct Answer: A — 1 A

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Q. In a circuit with two resistors in parallel, if one resistor is 4 ohms and the other is 6 ohms, what is the equivalent resistance?

A. 2.4 ohms
B. 10 ohms
C. 24 ohms
D. 3.6 ohms

Solution

Using the formula for resistors in parallel, 1/R_eq = 1/4 + 1/6, we find R_eq = 2.4 ohms.

Correct Answer: A — 2.4 ohms

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Q. In a circuit with two resistors in parallel, if one resistor is 4Ω and the other is 12Ω, what is the total current flowing through the circuit when connected to a 24V battery?

A. 2A
B. 3A
C. 4A
D. 6A

Solution

First, find the equivalent resistance: 1/R_eq = 1/4 + 1/12 = 1/3. R_eq = 3Ω. Then, I = V/R = 24V / 3Ω = 8A.

Correct Answer: D — 6A

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Q. In a circuit with two resistors in parallel, if one resistor is 6Ω and the other is 3Ω, what is the total current flowing through the circuit when connected to a 12V battery?

A. 2A
B. 4A
C. 6A
D. 8A

Solution

First, find the equivalent resistance: 1/R_eq = 1/6 + 1/3 = 1/2, R_eq = 2Ω. Then, I = V/R = 12V/2Ω = 6A.

Correct Answer: B — 4A

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Q. In a circuit with two resistors in parallel, if one resistor is 6Ω and the other is 3Ω, what is the total current if a voltage of 12V is applied across the combination?

A. 2A
B. 4A
C. 6A
D. 8A

Solution

Total resistance in parallel: 1/Rtotal = 1/6 + 1/3 = 1/2. Rtotal = 2Ω. Total current I = V/R = 12V/2Ω = 6A.

Correct Answer: B — 4A

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Q. In a circuit with two resistors in parallel, if one resistor is 6Ω and the other is 3Ω, what is the total current flowing if the voltage across the circuit is 12V?

A. 2A
B. 4A
C. 6A
D. 8A

Solution

Total resistance in parallel: 1/Rtotal = 1/6 + 1/3 = 1/2. Rtotal = 2Ω. Total current I = V/R = 12V/2Ω = 6A.

Correct Answer: B — 4A

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Q. In a circuit with two resistors in parallel, if one resistor is 6Ω and the other is 3Ω, what is the total current flowing if the voltage across the parallel combination is 12V?

A. 2A
B. 4A
C. 6A
D. 8A

Solution

Total current I = V / Req; Req = 1/(1/6 + 1/3) = 2Ω; I = 12V / 2Ω = 6A.

Correct Answer: B — 4A

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Current Electricity

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