In a circuit with a 24V battery and two resistors of 6Ω and 12Ω in series, what is the voltage across the 12Ω resistor?

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Q: In a circuit with a 24V battery and two resistors of 6Ω and 12Ω in series, what is the voltage across the 12Ω resistor?

Solution: Voltage across R2 = (R2/(R1+R2)) * V = (12/(6+12)) * 24 = 12V.

Steps: 8

Step 1: Identify the total voltage in the circuit, which is given as 24V from the battery.
Step 2: Identify the resistors in the circuit. We have R1 = 6Ω and R2 = 12Ω.
Step 3: Calculate the total resistance in the circuit by adding the two resistors together: Total Resistance = R1 + R2 = 6Ω + 12Ω = 18Ω.
Step 4: Use the formula to find the voltage across the 12Ω resistor (R2). The formula is: Voltage across R2 = (R2 / Total Resistance) * Total Voltage.
Step 5: Substitute the values into the formula: Voltage across R2 = (12Ω / 18Ω) * 24V.
Step 6: Simplify the fraction: 12 / 18 = 2 / 3.
Step 7: Multiply by the total voltage: (2 / 3) * 24V = 16V.
Step 8: Therefore, the voltage across the 12Ω resistor is 16V.