In a circuit with a 9V battery and three resistors of 3Ω, 3Ω, and 6Ω in parallel, what is the total current supplied by the battery?

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Q: In a circuit with a 9V battery and three resistors of 3Ω, 3Ω, and 6Ω in parallel, what is the total current supplied by the battery?

Solution: 1/R_eq = 1/3 + 1/3 + 1/6 = 1. Therefore, R_eq = 1Ω. Total current I = V/R_eq = 9V/1Ω = 9A.

Steps: 9

Step 1: Identify the values of the resistors. We have three resistors: 3Ω, 3Ω, and 6Ω.
Step 2: Write the formula for calculating the equivalent resistance (R_eq) for resistors in parallel: 1/R_eq = 1/R1 + 1/R2 + 1/R3.
Step 3: Substitute the values of the resistors into the formula: 1/R_eq = 1/3 + 1/3 + 1/6.
Step 4: Calculate each term: 1/3 = 0.333, 1/3 = 0.333, and 1/6 = 0.167.
Step 5: Add the terms together: 0.333 + 0.333 + 0.167 = 0.833.
Step 6: Take the reciprocal to find R_eq: R_eq = 1/0.833 = 1Ω.
Step 7: Use Ohm's Law to find the total current (I) supplied by the battery: I = V/R_eq.
Step 8: Substitute the values: I = 9V / 1Ω.
Step 9: Calculate the total current: I = 9A.