Physical Chemistry
Q. A ladder leans against a wall and is in equilibrium. What forces are acting on the ladder?
A.
Weight, normal force from the ground, and friction
B.
Only weight and normal force
C.
Only weight and friction
D.
Only normal force and friction
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Solution
The ladder experiences weight, a normal force from the ground, and friction at the base.
Correct Answer: A — Weight, normal force from the ground, and friction
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Q. A particle is in equilibrium under the action of three forces. If two forces are known, how can the third force be determined?
A.
By vector addition of the first two forces
B.
By subtracting the first two forces
C.
By multiplying the first two forces
D.
By taking the average of the first two forces
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Solution
The third force can be determined by vector addition of the first two forces to ensure the net force is zero.
Correct Answer: A — By vector addition of the first two forces
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Q. A solution contains 20% (w/w) of glucose. If the total mass of the solution is 200 g, what is the mass of glucose in the solution?
A.
20 g
B.
40 g
C.
60 g
D.
80 g
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Solution
Mass of glucose = (20/100) x 200 g = 40 g.
Correct Answer: B — 40 g
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Q. A solution has a concentration of 0.1 M NaCl. How many grams of NaCl are present in 1 liter of this solution? (Molar mass of NaCl = 58.5 g/mol)
A.
5.85 g
B.
58.5 g
C.
0.1 g
D.
0.585 g
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Solution
Mass = moles x molar mass = 0.1 moles x 58.5 g/mol = 5.85 g.
Correct Answer: B — 58.5 g
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Q. A solution has a concentration of 0.2 M. How many moles of solute are present in 1.5 L of this solution?
A.
0.3 moles
B.
0.5 moles
C.
0.2 moles
D.
0.15 moles
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Solution
Moles of solute = Molarity × Volume = 0.2 M × 1.5 L = 0.3 moles.
Correct Answer: B — 0.5 moles
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Q. A solution has a density of 1.2 g/mL and contains 10% (w/v) NaOH. What is the mass of NaOH in 1 L of this solution?
A.
100 g
B.
120 g
C.
80 g
D.
60 g
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Solution
Mass of NaOH = (10/100) x 1000 mL = 100 g.
Correct Answer: B — 120 g
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Q. A solution has a density of 1.2 g/mL and contains 30 g of solute. What is the molarity if the molar mass of the solute is 60 g/mol?
A.
0.5 M
B.
1 M
C.
2 M
D.
1.5 M
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Solution
Volume of solution = mass / density = 30 g / 1.2 g/mL = 25 mL = 0.025 L. Moles of solute = 30 g / 60 g/mol = 0.5 moles. Molarity = 0.5 moles / 0.025 L = 20 M.
Correct Answer: B — 1 M
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Q. A solution is prepared by dissolving 50 g of glucose (C6H12O6) in 250 g of water. What is the mass percent of glucose in the solution? (Molar mass of glucose = 180 g/mol)
A.
20%
B.
15%
C.
25%
D.
10%
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Solution
Mass percent = (mass of solute / (mass of solute + mass of solvent)) × 100 = (50 g / (50 g + 250 g)) × 100 = 20%.
Correct Answer: A — 20%
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Q. A solution is prepared by dissolving 58.5 g of NaCl in 1 L of water. What is the molarity of the solution? (Molar mass of NaCl = 58.5 g/mol)
A.
1 M
B.
2 M
C.
0.5 M
D.
0.1 M
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Solution
Moles of NaCl = 58.5 g / 58.5 g/mol = 1 mole. Molarity = moles of solute / liters of solution = 1 mole / 1 L = 1 M.
Correct Answer: A — 1 M
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Q. A solution is prepared by dissolving 58.5 g of NaCl in 1 L of water. What is the concentration in terms of molarity? (Molar mass of NaCl = 58.5 g/mol)
A.
1 M
B.
2 M
C.
0.5 M
D.
0.25 M
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Solution
Moles of NaCl = 58.5 g / 58.5 g/mol = 1 mole. Molarity = 1 mole / 1 L = 1 M.
Correct Answer: A — 1 M
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Q. A solution is prepared by dissolving 58.5 g of NaCl in enough water to make 1 L of solution. What is the molarity of the solution? (Molar mass of NaCl = 58.5 g/mol)
A.
1 M
B.
2 M
C.
0.5 M
D.
0.1 M
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Solution
Moles of NaCl = 58.5 g / 58.5 g/mol = 1 mole. Molarity = 1 mole / 1 L = 1 M.
Correct Answer: A — 1 M
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Q. A solution of 0.1 molal urea in water has a freezing point depression of how much? (K_f for water = 1.86 °C kg/mol)
A.
0.186 °C
B.
0.372 °C
C.
0.186 K
D.
0.372 K
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Solution
Freezing point depression = K_f * m = 1.86 * 0.1 = 0.186 °C
Correct Answer: A — 0.186 °C
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Q. According to Boyle's law, if the volume of a gas is doubled at constant temperature, what happens to the pressure?
A.
It doubles
B.
It halves
C.
It remains constant
D.
It quadruples
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Solution
Boyle's law states that pressure is inversely proportional to volume at constant temperature, so if the volume is doubled, the pressure halves.
Correct Answer: B — It halves
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Q. According to Boyle's law, if the volume of a gas is doubled, what happens to its pressure?
A.
It doubles
B.
It halves
C.
It remains constant
D.
It quadruples
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Solution
Boyle's law states that pressure is inversely proportional to volume at constant temperature, so if volume is doubled, pressure is halved.
Correct Answer: B — It halves
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Q. According to Graham's law of effusion, the rate of effusion of a gas is inversely proportional to what?
A.
Molar mass
B.
Temperature
C.
Pressure
D.
Volume
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Solution
Graham's law states that the rate of effusion is inversely proportional to the square root of the molar mass of the gas.
Correct Answer: A — Molar mass
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Q. According to the ideal gas law, which of the following is the correct equation?
A.
PV = nRT
B.
PV = nR
C.
P = nRT/V
D.
V = nP/RT
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Solution
The ideal gas law is represented by the equation PV = nRT.
Correct Answer: A — PV = nRT
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Q. According to the kinetic molecular theory, which of the following statements is true?
A.
Gas particles have significant volume.
B.
Gas particles are in constant motion.
C.
Gas particles attract each other.
D.
Gas particles do not collide.
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Solution
According to the kinetic molecular theory, gas particles are in constant motion.
Correct Answer: B — Gas particles are in constant motion.
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Q. According to VSEPR theory, what is the shape of the molecule with the formula AX2E2?
A.
Linear
B.
Bent
C.
Trigonal planar
D.
Tetrahedral
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Solution
AX2E2 indicates two bonding pairs and two lone pairs, resulting in a bent shape.
Correct Answer: B — Bent
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Q. At constant temperature and pressure, if ΔH is positive and ΔS is negative, what can be said about ΔG?
A.
ΔG is positive
B.
ΔG is negative
C.
ΔG is zero
D.
ΔG can be either positive or negative
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Solution
If ΔH is positive and ΔS is negative, ΔG will be positive.
Correct Answer: A — ΔG is positive
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Q. At constant temperature and pressure, if ΔH is positive and ΔS is negative, what is the sign of ΔG?
A.
Always negative
B.
Always positive
C.
Depends on temperature
D.
Zero
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Solution
If ΔH is positive and ΔS is negative, ΔG will always be positive.
Correct Answer: B — Always positive
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Q. At constant temperature, the volume of a gas is inversely proportional to its pressure. This is known as which law?
A.
Boyle's Law
B.
Charles's Law
C.
Avogadro's Law
D.
Ideal Gas Law
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Solution
Boyle's Law states that for a given mass of gas at constant temperature, the volume is inversely proportional to the pressure.
Correct Answer: A — Boyle's Law
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Q. At what temperature does a reaction become spontaneous if ΔH = 50 kJ and ΔS = 0.1 kJ/K?
A.
500 K
B.
250 K
C.
1000 K
D.
200 K
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Solution
Set ΔG = 0: 0 = ΔH - TΔS; T = ΔH/ΔS = 50 kJ / 0.1 kJ/K = 500 K.
Correct Answer: A — 500 K
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Q. At what temperature does the Gibbs Free Energy change from negative to positive?
A.
At absolute zero
B.
At the melting point
C.
At the boiling point
D.
At the transition temperature
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Solution
The Gibbs Free Energy changes from negative to positive at the transition temperature, where the system shifts from one phase to another.
Correct Answer: D — At the transition temperature
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Q. At what temperature does the volume of a gas become zero according to Charles's Law?
A.
0 K
B.
-273.15 °C
C.
273.15 K
D.
None of the above
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Solution
According to Charles's Law, the volume of a gas approaches zero at absolute zero, which is -273.15 °C.
Correct Answer: B — -273.15 °C
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Q. Calculate the molality of a solution if the boiling point elevation is 1.024 °C. (K_b for water = 0.512 °C kg/mol)
A.
1 mol/kg
B.
2 mol/kg
C.
0.5 mol/kg
D.
0.25 mol/kg
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Solution
Molality = ΔT_b / (i * K_b) = 1.024 / (2 * 0.512) = 1 mol/kg
Correct Answer: B — 2 mol/kg
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Q. Calculate the pH of a 0.1 M acetic acid solution (Ka = 1.8 x 10^-5).
A.
2.87
B.
3.87
C.
4.87
D.
5.87
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Solution
Using the formula for weak acids, pH = 0.5(pKa - log[C]), where pKa = -log(1.8 x 10^-5) ≈ 4.74. Thus, pH = 0.5(4.74 - log(0.1)) = 3.87.
Correct Answer: B — 3.87
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Q. Calculate the pH of a buffer solution containing 0.1 M acetic acid and 0.1 M sodium acetate.
A.
4.76
B.
5.76
C.
6.76
D.
7.76
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Solution
Using Henderson-Hasselbalch equation: pH = pKa + log([A-]/[HA]); pKa of acetic acid = 4.76, so pH = 4.76 + log(1) = 4.76
Correct Answer: B — 5.76
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Q. For a first-order reaction, if the half-life is 10 minutes, what will be the half-life if the initial concentration is doubled?
A.
10 minutes
B.
5 minutes
C.
20 minutes
D.
15 minutes
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Solution
For a first-order reaction, the half-life is independent of the initial concentration. Therefore, it remains 10 minutes.
Correct Answer: A — 10 minutes
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Q. For a first-order reaction, the half-life is independent of the initial concentration. What is the expression for half-life?
A.
t1/2 = 0.693/k
B.
t1/2 = k/0.693
C.
t1/2 = 1/k
D.
t1/2 = k/2
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Solution
For a first-order reaction, the half-life is given by the expression t1/2 = 0.693/k.
Correct Answer: A — t1/2 = 0.693/k
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Q. For a first-order reaction, the half-life is independent of which of the following?
A.
Initial concentration
B.
Rate constant
C.
Temperature
D.
All of the above
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Solution
For a first-order reaction, the half-life is independent of the initial concentration.
Correct Answer: A — Initial concentration
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