A solution is prepared by dissolving 58.5 g of NaCl in enough water to make 1 L of solution. What is the molarity of the solution? (Molar mass of NaCl = 58.5 g/mol)
Practice Questions
1 question
Q1
A solution is prepared by dissolving 58.5 g of NaCl in enough water to make 1 L of solution. What is the molarity of the solution? (Molar mass of NaCl = 58.5 g/mol)
1 M
2 M
0.5 M
0.1 M
Moles of NaCl = 58.5 g / 58.5 g/mol = 1 mole. Molarity = 1 mole / 1 L = 1 M.
Questions & Step-by-step Solutions
1 item
Q
Q: A solution is prepared by dissolving 58.5 g of NaCl in enough water to make 1 L of solution. What is the molarity of the solution? (Molar mass of NaCl = 58.5 g/mol)
Solution: Moles of NaCl = 58.5 g / 58.5 g/mol = 1 mole. Molarity = 1 mole / 1 L = 1 M.
Steps: 6
Step 1: Identify the mass of NaCl used, which is 58.5 grams.
Step 2: Find the molar mass of NaCl, which is given as 58.5 g/mol.
Step 3: Calculate the number of moles of NaCl by dividing the mass by the molar mass: 58.5 g / 58.5 g/mol = 1 mole.
Step 4: Determine the volume of the solution, which is given as 1 liter.
Step 5: Calculate the molarity of the solution using the formula: Molarity = moles of solute / liters of solution.
Step 6: Substitute the values: Molarity = 1 mole / 1 L = 1 M.
