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A solution is prepared by dissolving 58.5 g of NaCl in 1 L of water. What is the
A solution is prepared by dissolving 58.5 g of NaCl in 1 L of water. What is the molarity of the solution? (Molar mass of NaCl = 58.5 g/mol)
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Q1
A solution is prepared by dissolving 58.5 g of NaCl in 1 L of water. What is the molarity of the solution? (Molar mass of NaCl = 58.5 g/mol)
1 M
2 M
0.5 M
0.1 M
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Moles of NaCl = 58.5 g / 58.5 g/mol = 1 mole. Molarity = moles of solute / liters of solution = 1 mole / 1 L = 1 M.
Questions & Step-by-step Solutions
1 item
Q
Q: A solution is prepared by dissolving 58.5 g of NaCl in 1 L of water. What is the molarity of the solution? (Molar mass of NaCl = 58.5 g/mol)
Solution:
Moles of NaCl = 58.5 g / 58.5 g/mol = 1 mole. Molarity = moles of solute / liters of solution = 1 mole / 1 L = 1 M.
Steps: 6
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Step 1: Identify the mass of NaCl used, which is 58.5 grams.
Step 2: Identify the molar mass of NaCl, which is given as 58.5 g/mol.
Step 3: Calculate the number of moles of NaCl by dividing the mass by the molar mass: 58.5 g / 58.5 g/mol = 1 mole.
Step 4: Identify the volume of the solution, which is 1 liter.
Step 5: Calculate the molarity of the solution using the formula: Molarity = moles of solute / liters of solution.
Step 6: Substitute the values into the formula: Molarity = 1 mole / 1 L = 1 M.
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