Q. What is the hybridization of the central atom in NH4+?
-
A.
sp
-
B.
sp2
-
C.
sp3
-
D.
dsp3
Solution
The central atom nitrogen in NH4+ undergoes sp3 hybridization to form four equivalent bonds with hydrogen.
Correct Answer: C — sp3
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Q. What is the hybridization of the central atom in O3 (ozone)?
-
A.
sp
-
B.
sp2
-
C.
sp3
-
D.
dsp2
Solution
The central oxygen atom in O3 is sp2 hybridized, leading to a bent molecular shape.
Correct Answer: B — sp2
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Q. What is the hybridization of the central atom in ozone (O3)?
-
A.
sp
-
B.
sp2
-
C.
sp3
-
D.
dsp2
Solution
In ozone (O3), the central oxygen atom is sp2 hybridized, resulting in a bent molecular shape.
Correct Answer: B — sp2
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Q. What is the hybridization of the central atom in PCl5?
-
A.
sp
-
B.
sp2
-
C.
sp3
-
D.
sp3d
Solution
In PCl5, phosphorus is sp3d hybridized, allowing for five bonding pairs.
Correct Answer: D — sp3d
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Q. What is the hybridization of the central atom in SO2?
-
A.
sp
-
B.
sp2
-
C.
sp3
-
D.
dsp3
Solution
The sulfur atom in SO2 is sp2 hybridized, forming one double bond and one single bond.
Correct Answer: B — sp2
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Q. What is the hybridization of the central atom in XeF4?
-
A.
sp
-
B.
sp2
-
C.
sp3
-
D.
dsp3
Solution
The xenon atom in XeF4 is dsp3 hybridized, resulting in a square planar geometry.
Correct Answer: D — dsp3
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Q. What is the hybridization of the nitrogen atom in NH3?
-
A.
sp
-
B.
sp2
-
C.
sp3
-
D.
dsp3
Solution
In NH3, nitrogen has three bonds and one lone pair, leading to sp3 hybridization.
Correct Answer: C — sp3
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Q. What is the hybridization of the phosphorus atom in PCl5?
-
A.
sp
-
B.
sp2
-
C.
sp3
-
D.
d2sp3
Solution
In PCl5, phosphorus is surrounded by five chlorine atoms, indicating d2sp3 hybridization.
Correct Answer: D — d2sp3
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Q. What is the molecular geometry of ammonia (NH3)?
-
A.
Linear
-
B.
Trigonal planar
-
C.
Tetrahedral
-
D.
Trigonal pyramidal
Solution
Ammonia has a trigonal pyramidal geometry due to the presence of a lone pair on nitrogen.
Correct Answer: D — Trigonal pyramidal
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Q. What is the molecular geometry of BF3 according to VSEPR theory?
-
A.
Trigonal planar
-
B.
Tetrahedral
-
C.
Octahedral
-
D.
Linear
Solution
BF3 has three bonding pairs and no lone pairs, resulting in a trigonal planar geometry.
Correct Answer: A — Trigonal planar
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Q. What is the molecular geometry of BF3?
-
A.
Linear
-
B.
Trigonal planar
-
C.
Tetrahedral
-
D.
Bent
Solution
BF3 has a trigonal planar geometry due to the three bonding pairs and no lone pairs on the central atom.
Correct Answer: B — Trigonal planar
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Q. What is the molecular geometry of CH4 according to VSEPR theory?
-
A.
Linear
-
B.
Trigonal planar
-
C.
Tetrahedral
-
D.
Octahedral
Solution
According to VSEPR theory, CH4 has four bonding pairs and no lone pairs, resulting in a tetrahedral geometry.
Correct Answer: C — Tetrahedral
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Q. What is the molecular geometry of CH4?
-
A.
Linear
-
B.
Trigonal planar
-
C.
Tetrahedral
-
D.
Octahedral
Solution
CH4 has a tetrahedral geometry due to four bonding pairs around the central carbon atom.
Correct Answer: C — Tetrahedral
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Q. What is the molecular geometry of NH3 according to VSEPR theory?
-
A.
Trigonal planar
-
B.
Tetrahedral
-
C.
Bent
-
D.
Trigonal pyramidal
Solution
NH3 has three bonding pairs and one lone pair, resulting in a trigonal pyramidal geometry.
Correct Answer: D — Trigonal pyramidal
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Q. What is the molecular geometry of SF4?
-
A.
Tetrahedral
-
B.
Trigonal bipyramidal
-
C.
Seesaw
-
D.
Square planar
Solution
SF4 has four bonding pairs and one lone pair, resulting in a seesaw molecular geometry.
Correct Answer: C — Seesaw
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Q. What is the molecular geometry of SO2?
-
A.
Linear
-
B.
Trigonal planar
-
C.
Bent
-
D.
Tetrahedral
Solution
SO2 has two bonding pairs and one lone pair, resulting in a bent molecular geometry.
Correct Answer: C — Bent
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Q. What is the molecular geometry of the molecule with the electronic configuration of 1s2 2s2 2p2?
-
A.
Linear
-
B.
Trigonal Planar
-
C.
Tetrahedral
-
D.
Octahedral
Solution
The electronic configuration corresponds to C2, which has a tetrahedral geometry due to sp3 hybridization.
Correct Answer: C — Tetrahedral
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Q. What is the molecular orbital configuration of F2?
-
A.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)⁴(π*2p)²
-
B.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)⁴
-
C.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(π2p)⁴(π*2p)²
-
D.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)³(π*2p)²
Solution
The correct configuration for F2 is (σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)⁴(π*2p)².
Correct Answer: A — (σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)⁴(π*2p)²
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Q. What is the molecular orbital configuration of O2?
-
A.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)²(π*2p)¹
-
B.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)²(π*2p)²
-
C.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)³
-
D.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)²(π*2p)⁴
Solution
The correct configuration for O2 is (σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)²(π*2p)¹.
Correct Answer: A — (σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)²(π*2p)¹
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Q. What is the molecular orbital configuration of the F2 molecule?
-
A.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)⁴(π*2p)²
-
B.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)⁴(π*2p)⁴
-
C.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)⁴(π*2p)¹
-
D.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)³(π*2p)²
Solution
The correct configuration for F2 is (σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)⁴(π*2p)².
Correct Answer: A — (σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)⁴(π*2p)²
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Q. What is the molecular orbital configuration of the O2 molecule?
-
A.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)²(π*2p)¹
-
B.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)²(π*2p)²
-
C.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)¹(π*2p)¹
-
D.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)¹(π*2p)²
Solution
The correct configuration for O2 is (σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)²(π*2p)¹.
Correct Answer: A — (σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)²(π*2p)¹
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Q. What is the molecular shape of a molecule with the formula AX3E?
-
A.
Trigonal planar
-
B.
Tetrahedral
-
C.
Trigonal pyramidal
-
D.
Bent
Solution
AX3E indicates three bonding pairs and one lone pair, resulting in a trigonal pyramidal shape.
Correct Answer: C — Trigonal pyramidal
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Q. What is the molecular shape of BF3 according to VSEPR theory?
-
A.
Bent
-
B.
Trigonal planar
-
C.
Tetrahedral
-
D.
Octahedral
Solution
BF3 has three bonding pairs and no lone pairs, resulting in a trigonal planar shape.
Correct Answer: B — Trigonal planar
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Q. What is the molecular shape of NH3 according to VSEPR theory?
-
A.
Linear
-
B.
Trigonal planar
-
C.
Tetrahedral
-
D.
Trigonal pyramidal
Solution
NH3 has three bonding pairs and one lone pair, resulting in a trigonal pyramidal shape.
Correct Answer: D — Trigonal pyramidal
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Q. What is the primary type of bonding in sodium chloride (NaCl)?
-
A.
Covalent
-
B.
Ionic
-
C.
Metallic
-
D.
Hydrogen
Solution
Sodium chloride is primarily held together by ionic bonds formed between Na+ and Cl- ions.
Correct Answer: B — Ionic
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Q. What is the shape of a molecule with the formula AX3E?
-
A.
Trigonal planar
-
B.
Tetrahedral
-
C.
Trigonal pyramidal
-
D.
Bent
Solution
AX3E indicates three bonding pairs and one lone pair, resulting in a trigonal pyramidal shape.
Correct Answer: C — Trigonal pyramidal
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Q. What is the shape of the ammonia (NH3) molecule?
-
A.
Linear
-
B.
Trigonal planar
-
C.
Tetrahedral
-
D.
Trigonal pyramidal
Solution
Ammonia has a trigonal pyramidal shape due to the presence of a lone pair on the nitrogen atom.
Correct Answer: D — Trigonal pyramidal
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Q. What is the shape of the molecular orbital in the case of a π bond?
-
A.
Spherical
-
B.
Dumbbell
-
C.
Linear
-
D.
Planar
Solution
π bonds are formed by the side-to-side overlap of p orbitals, resulting in a planar shape.
Correct Answer: D — Planar
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Q. What is the shape of the molecular orbital in the highest occupied molecular orbital (HOMO) of benzene?
-
A.
Linear
-
B.
Trigonal planar
-
C.
Tetrahedral
-
D.
Cyclic
Solution
The HOMO of benzene is cyclic due to the delocalization of π electrons in the ring structure.
Correct Answer: D — Cyclic
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Q. What is the shape of the molecular orbital of the highest energy in O2?
-
A.
spherical
-
B.
dumbbell
-
C.
double dumbbell
-
D.
linear
Solution
The highest energy molecular orbital in O2 is a π* orbital, which has a dumbbell shape.
Correct Answer: B — dumbbell
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