The rough endoplasmic reticulum is studded with ribosomes and is primarily involved in the synthesis of proteins.

The seminal vesicles produce a fluid that provides nutrients to sperm and helps form semen.

Sepals protect the flower bud before it opens.

Xylem is responsible for the transport of water and minerals from the roots to the rest of the plant.

Villi increase the surface area of the small intestine, enhancing the absorption of nutrients.

The functional group of alcohols is the hydroxyl group (-OH).

The functional group of aldehydes is -CHO.

Phenols contain a hydroxyl group (-OH) directly attached to an aromatic ring.

Alcohols contain a hydroxyl (-OH) functional group.

Phenols contain a hydroxyl group (-OH) directly attached to an aromatic hydrocarbon group.

Phenols contain a hydroxyl group (-OH) directly attached to an aromatic hydrocarbon group.

The general formula for secondary amines is R2NH, where R represents an alkyl or aryl group.

The integrating factor is e^(-4x). The solution is y = Ce^(4x) + 3/4.

The characteristic equation is r^2 - 3r + 2 = 0, which factors to (r - 1)(r - 2) = 0. Thus, the general solution is y = C1 e^(2x) + C2 e^(x).

The geometry is linear when there are two bonding pairs and no lone pairs on the central atom.

The complex [Ag(NH3)2]+ has a linear geometry due to the presence of two ligands around the silver ion.

Gravitational potential energy (PE) is given by PE = mgh. Here, PE = 10 kg * 9.81 m/s² * 10 m = 981 J.

Gravitational potential energy (PE) is given by PE = mgh. Here, m = 10 kg, g = 9.8 m/s², and h = 5 m. PE = 10 * 9.8 * 5 = 490 J.

Gravitational potential energy (PE) = mgh = 2 kg × 9.8 m/s² × 10 m = 196 J.

Alkali metals are located in group 1 of the periodic table.

Halogens are located in group 17 of the periodic table.

Heat required Q = mcΔT = (2000 g)(0.9 J/g°C)(50°C) = 90000 J.

In [Ni(CO)4], the nickel atom undergoes sp3 hybridization to accommodate four CO ligands.

In [Cr(NH3)6]3+, the hybridization is d2sp3 due to the octahedral arrangement of six ligands.

Impedance Z = √(R² + X²) = √(4² + 3²) = √(16 + 9) = √25 = 5 ohms.

Impedance Z = √(R² + (XL)²), where XL = 2πfL = 31.42Ω. Thus, Z = √(10² + 31.42²) = 15.71Ω.

At resonance, the impedance is equal to the resistance, which is 4Ω.

The impedance Z in a series RL circuit is given by Z = √(R² + (2πfL)²).

The impedance Z in a series R-L circuit is given by Z = √(R² + (ωL)²).

The integral of 1/x is ln|x| + C.