Q. What is the voltage across a 5Ω resistor carrying a current of 3A? (2023)
A.
15V
B.
10V
C.
5V
D.
20V
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Solution
Using Ohm's law, V = IR = 3A * 5Ω = 15V.
Correct Answer: A — 15V
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Q. What is the voltage across a 5Ω resistor if a current of 3A flows through it? (2020)
A.
15V
B.
10V
C.
5V
D.
20V
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Solution
Using Ohm's law, V = IR = 3A * 5Ω = 15V.
Correct Answer: A — 15V
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Q. What is the voltage drop across a 10Ω resistor carrying a current of 2A? (2019)
A.
5V
B.
10V
C.
15V
D.
20V
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Solution
Using Ohm's law, V = I * R = 2A * 10Ω = 20V.
Correct Answer: B — 10V
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Q. What is the voltage drop across a 3Ω resistor carrying a current of 4A? (2019)
A.
6V
B.
8V
C.
12V
D.
15V
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Solution
Using Ohm's law, V = I * R = 4A * 3Ω = 12V.
Correct Answer: C — 12V
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Q. What is the volume of 0.2 M NaOH required to neutralize 0.1 M HCl in 250 mL? (2020)
A.
125 mL
B.
250 mL
C.
500 mL
D.
100 mL
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Solution
Using the formula M1V1 = M2V2, (0.1 M)(0.25 L) = (0.2 M)(V2). V2 = 0.125 L = 125 mL.
Correct Answer: A — 125 mL
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Q. What is the volume of 1 M HCl solution needed to obtain 0.5 moles of HCl? (2022)
A.
0.5 L
B.
1 L
C.
2 L
D.
0.25 L
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Solution
Volume = moles / molarity = 0.5 moles / 1 M = 0.5 L.
Correct Answer: A — 0.5 L
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Q. What is the volume of 1 mole of an ideal gas at STP? (2019) 2019
A.
22.4 L
B.
24 L
C.
1 L
D.
10 L
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Solution
At STP, 1 mole of an ideal gas occupies 22.4 liters.
Correct Answer: A — 22.4 L
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Q. What is the volume of a 2 M NaOH solution needed to obtain 4 moles of NaOH? (2021) 2021
A.
2 L
B.
1 L
C.
0.5 L
D.
4 L
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Solution
Volume (L) = moles / molarity = 4 moles / 2 M = 2 L.
Correct Answer: A — 2 L
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Q. What is the volume of a cube with side length 3 units? (2023)
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Solution
Volume = side³ = 3³ = 27 cubic units.
Correct Answer: B — 27
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Q. What is the volume of a cube with side length 4 units? (2020)
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Solution
Volume = side³ = 4³ = 64 cubic units.
Correct Answer: B — 64
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Q. What is the volume of a cylinder with radius 2 and height 5? (2023)
A.
20π
B.
10π
C.
15π
D.
25π
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Solution
Volume = πr²h = π(2²)(5) = 20π cubic units.
Correct Answer: A — 20π
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Q. What is the volume of a cylinder with radius 3 units and height 5 units? (2021)
A.
45π
B.
30π
C.
15π
D.
9π
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Solution
Volume = πr²h = π(3²)(5) = 45π cubic units.
Correct Answer: A — 45π
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Q. What is the volume of a sphere with radius 5 units? (2021)
A.
500/3π
B.
125/3π
C.
100/3π
D.
200/3π
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Solution
Volume = (4/3)πr³ = (4/3)π(5)³ = (4/3)π(125) = 500/3π cubic units.
Correct Answer: A — 500/3π
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Q. What is the wavelength of light emitted when an electron transitions from n=3 to n=1 in a hydrogen atom? (2020)
A.
102.6 nm
B.
656.3 nm
C.
486.1 nm
D.
434.0 nm
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Solution
Using the Rydberg formula, the wavelength for the transition from n=3 to n=1 can be calculated to be approximately 102.6 nm.
Correct Answer: A — 102.6 nm
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Q. What is the wavelength of light emitted when an electron transitions from n=4 to n=2 in a hydrogen atom? (2020)
A.
486 nm
B.
656 nm
C.
434 nm
D.
410 nm
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Solution
Using the Rydberg formula, the wavelength for the transition from n=4 to n=2 can be calculated to be approximately 486 nm.
Correct Answer: A — 486 nm
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Q. What is the wavelength of light if the first-order maximum occurs at an angle of 30° in a double-slit experiment with a slit separation of 0.1 mm and a screen distance of 1 m? (2019)
A.
0.5 mm
B.
0.3 mm
C.
0.2 mm
D.
0.1 mm
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Solution
Using the formula λ = d sin θ / m, where d = 0.1 mm, θ = 30°, and m = 1, we find λ = 0.1 mm * sin(30°) = 0.1 mm * 0.5 = 0.05 mm = 0.2 mm.
Correct Answer: C — 0.2 mm
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Q. What is the work done by a force of 15 N acting at an angle of 60° while moving an object 4 m? (2021)
A.
30 J
B.
60 J
C.
45 J
D.
90 J
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Solution
Work = F × d × cos(θ) = 15 N × 4 m × cos(60°) = 15 × 4 × 0.5 = 30 J.
Correct Answer: C — 45 J
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Q. What is the work done by an ideal gas during an isobaric expansion if it expands from 2 L to 5 L at a pressure of 3 atm? (2022)
A.
9 J
B.
12 J
C.
15 J
D.
18 J
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Solution
Work done (W) = P * ΔV = 3 atm * (5 L - 2 L) = 3 atm * 3 L = 9 atm·L = 15 J (1 atm·L = 101.325 J)
Correct Answer: C — 15 J
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Q. What is the work done by an ideal gas during an isobaric expansion? (2019)
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Solution
The work done by an ideal gas during an isobaric (constant pressure) expansion is given by W = PΔV.
Correct Answer: A — PΔV
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Q. What is the work done by an ideal gas during an isothermal expansion from volume V1 to V2 at temperature T? (2021)
A.
nRT ln(V2/V1)
B.
nRT (V2 - V1)
C.
PV
D.
0
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Solution
The work done during an isothermal expansion is given by W = nRT ln(V2/V1).
Correct Answer: A — nRT ln(V2/V1)
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Q. What is the work done by an ideal gas during isothermal expansion? (2021)
A.
0
B.
nRT ln(Vf/Vi)
C.
nRT (Vf - Vi)
D.
nR (Tf - Ti)
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Solution
For an ideal gas undergoing isothermal expansion, the work done is given by W = nRT ln(Vf/Vi).
Correct Answer: B — nRT ln(Vf/Vi)
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Q. What is the work done on a gas when it is compressed from 4 L to 2 L at a constant pressure of 2 atm?
A.
4 L·atm
B.
2 L·atm
C.
8 L·atm
D.
0 L·atm
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Solution
Work done (W) = P * ΔV = 2 atm * (2 L - 4 L) = 2 atm * (-2 L) = -4 L·atm (work done on the gas is positive).
Correct Answer: A — 4 L·atm
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Q. What is the work done on a gas when it is compressed from 5 L to 2 L at a constant pressure of 200 kPa? (2022)
A.
600 J
B.
800 J
C.
1000 J
D.
1200 J
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Solution
Work done (W) = P * ΔV = 200 kPa * (2 L - 5 L) = 200 kPa * (-3 L) = -600 J (work done on the gas).
Correct Answer: C — 1000 J
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Q. What is the work done when 1 mole of an ideal gas expands isothermally from 10 L to 20 L at 300 K? (2022)
A.
300 J
B.
600 J
C.
150 J
D.
0 J
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Solution
Work done W = nRT ln(Vf/Vi) = 1 * 8.314 * 300 * ln(20/10) = 600 J.
Correct Answer: B — 600 J
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Q. What is the work done when 1 mole of an ideal gas expands isothermally from 10 L to 20 L at a temperature of 300 K? (2020)
A.
1.5 kJ
B.
2.5 kJ
C.
3.5 kJ
D.
4.5 kJ
Show solution
Solution
Work done (W) = nRT ln(Vf/Vi) = 1 mol * 8.314 J/(mol K) * 300 K * ln(20/10) = 2.5 kJ.
Correct Answer: B — 2.5 kJ
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Q. What is the work done when 1 mole of an ideal gas expands isothermally from 10 L to 20 L at 300 K? (R = 8.31 J/mol·K) (2023)
A.
0 J
B.
830 J
C.
1660 J
D.
2490 J
Show solution
Solution
Work done = nRT ln(Vf/Vi) = 1 mol × 8.31 J/mol·K × 300 K × ln(20/10) = 1660 J.
Correct Answer: C — 1660 J
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Q. What is the work done when a 50 N force moves an object 3 m in the direction of the force?
A.
150 J
B.
100 J
C.
50 J
D.
200 J
Show solution
Solution
Work done (W) = F × d = 50 N × 3 m = 150 J.
Correct Answer: A — 150 J
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Q. What is the work done when a force of 10 N moves an object 5 m in the direction of the force? (2016)
A.
50 J
B.
25 J
C.
10 J
D.
5 J
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Solution
Work done (W) = Force × Distance = 10 N × 5 m = 50 J.
Correct Answer: A — 50 J
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Q. What is the work done when a force of 15 N moves an object 3 m at an angle of 0 degrees to the direction of motion?
A.
45 J
B.
30 J
C.
60 J
D.
75 J
Show solution
Solution
Work = Force * Distance * cos(θ) = 15 N * 3 m * cos(0°) = 45 J.
Correct Answer: A — 45 J
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Q. What is the work done when a force of 15 N moves an object 3 m in the direction of the force? (2021)
A.
45 J
B.
30 J
C.
15 J
D.
60 J
Show solution
Solution
Work Done (W) = Force * Distance = 15 N * 3 m = 45 J.
Correct Answer: A — 45 J
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