Vapor pressure lowering = X_solute * P0 = (0.5 / (0.5 + 55.5)) * P0 ≈ 0.25 P0.

Vapor pressure lowering = (moles of solute / moles of solvent) * P0 = (0.5 / 55.5) * P0 ≈ 0.25 P0.

Molality (m) = moles of solute / kg of solvent. Assuming 1 L of water = 1 kg, molality = 0.5 moles / 1 kg = 0.5 m.

Freezing point depression (ΔTf) = i * Kf * m = 1 * 1.86 °C kg/mol * 1 mol/kg = 1.86 °C.

Using Ohm's Law, V = I * R = 2A * 10Ω = 20V.

Using Ohm's Law, V = I * R = 5A * 10Ω = 50V.

Power (P) can be calculated using the formula P = V^2 / R. Here, P = 20^2 / 10 = 400 / 10 = 40W.

Power (P) can be calculated using the formula P = V^2 / R. Here, P = 20V^2 / 10Ω = 40W.

Using F = ma, a = F/m = 10 N / 2 kg = 5 m/s².

Momentum = mass × velocity = 4 kg × 5 m/s = 20 kg m/s.

Kinetic Energy = 0.5 × Mass × Velocity² = 0.5 × 5 kg × (10 m/s)² = 250 J.

Power (P) can be calculated using P = V^2 / R. Here, P = 15V^2 / 5Ω = 45W.

When the voltage is increased to 10 V, the charge on the capacitor increases because charge (Q) is directly proportional to voltage (V) for a given capacitance.

Force F = qE = (1 × 10^-6 C) * (1000 N/C) = 0.001 N.

Force F = qE = (10 × 10^-6 C) * (200 N/C) = 2 N.

Power P = V^2/R = 12^2/3 = 144/3 = 48W.

Power (P) is calculated using P = I^2 * R = (3 A)^2 * 4 ohms = 12 W.

Power (P) can be calculated using P = I² × R = (3 A)² × 4 Ω = 12 W.

Using Ohm's Law, V = I * R = 5 A * 10 Ω = 50 V.

Using Ohm's Law, V = I * R = 5A * 10Ω = 50V.

Power (P) can be calculated using the formula P = I^2 * R = (3A)^2 * 12Ω = 36W.

Using Ohm's law, V = I × R = 3 A × 10 Ω = 30 V.

Using Ohm's law, V = I * R = 3A * 10Ω = 30V.

Using Ohm's law, V = I * R = 2A * 12Ω = 24V.

Using Ohm's law, V = I * R = 3A * 12Ω = 36V.

Using Ohm's law, V = I * R = 2A * 8Ω = 16V.

Using Ohm's law, I = V/R = 24V/6Ω = 4A.

Using Ohm's law, I = V/R = 24V/6Ω = 4A.

Using Ohm's law, I = V/R = 24V/6Ω = 4A.

Using Ohm's law, I = V/R = 24V/8Ω = 3A.