Oscillations & Waves
Q. A sound wave travels at a speed of 340 m/s in air. If its frequency is 1700 Hz, what is its wavelength?
A.
0.2 m
B.
0.5 m
C.
1.0 m
D.
2.0 m
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Solution
Using the wave equation v = fλ, we can find the wavelength: λ = v/f = 340 m/s / 1700 Hz = 0.2 m.
Correct Answer: B — 0.5 m
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Q. A sound wave travels at a speed of 340 m/s in air. What is the wavelength of a sound wave with a frequency of 680 Hz?
A.
0.5 m
B.
1 m
C.
2 m
D.
4 m
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Solution
Using the wave equation v = fλ, we can find the wavelength: λ = v/f = 340 m/s / 680 Hz = 0.5 m.
Correct Answer: B — 1 m
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Q. A sound wave travels at a speed of 340 m/s. If its frequency is 170 Hz, what is its wavelength?
A.
0.5 m
B.
1 m
C.
2 m
D.
3 m
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Solution
Using the wave equation v = fλ, we can find the wavelength: λ = v/f = 340/170 = 2 m.
Correct Answer: B — 1 m
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Q. A sound wave travels from air into water. What happens to its speed?
A.
Increases
B.
Decreases
C.
Remains the same
D.
Becomes zero
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Solution
Sound travels faster in water than in air, so its speed increases when it enters water.
Correct Answer: A — Increases
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Q. A sound wave travels in air at a speed of 340 m/s. If the frequency of the sound is 1700 Hz, what is the wavelength?
A.
0.2 m
B.
0.5 m
C.
2 m
D.
1 m
Show solution
Solution
Wavelength λ = v/f = 340 m/s / 1700 Hz = 0.2 m.
Correct Answer: A — 0.2 m
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Q. A sound wave travels in air at a speed of 340 m/s. If the frequency of the sound wave is 1700 Hz, what is its wavelength?
A.
0.2 m
B.
0.5 m
C.
2 m
D.
1 m
Show solution
Solution
Wavelength λ = v/f = 340 m/s / 1700 Hz = 0.2 m.
Correct Answer: B — 0.5 m
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Q. A sound wave travels in air at a speed of 340 m/s. If the frequency of the sound is 170 Hz, what is the wavelength?
A.
2 m
B.
1 m
C.
0.5 m
D.
0.2 m
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Solution
Wavelength λ = v/f = 340 m/s / 170 Hz = 2 m.
Correct Answer: A — 2 m
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Q. A sound wave travels through a medium with a speed of 340 m/s and has a frequency of 1700 Hz. What is its wavelength?
A.
0.2 m
B.
0.5 m
C.
2 m
D.
1 m
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Solution
Wavelength = Speed / Frequency = 340 m/s / 1700 Hz = 0.2 m.
Correct Answer: B — 0.5 m
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Q. A sound wave travels through air at a speed of 340 m/s. If the frequency of the sound is 1700 Hz, what is the wavelength?
A.
0.2 m
B.
0.5 m
C.
1 m
D.
2 m
Show solution
Solution
Using the formula v = fλ, we can rearrange to find λ = v/f. Thus, λ = 340 m/s / 1700 Hz = 0.2 m.
Correct Answer: A — 0.2 m
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Q. A sound wave travels through water at a speed of 1500 m/s. If the frequency of the sound wave is 300 Hz, what is the wavelength?
A.
2 m
B.
3 m
C.
4 m
D.
5 m
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Solution
Wavelength λ = v/f = 1500 m/s / 300 Hz = 5 m.
Correct Answer: A — 2 m
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Q. A tuning fork produces a sound wave of frequency 440 Hz. If the speed of sound in air is 340 m/s, what is the wavelength of the sound wave?
A.
0.77 m
B.
0.85 m
C.
0.90 m
D.
1.00 m
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Solution
Using the formula λ = v/f, we find λ = 340 m/s / 440 Hz = 0.7727 m, approximately 0.77 m.
Correct Answer: A — 0.77 m
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Q. A tuning fork produces a sound wave of frequency 440 Hz. What is the period of this wave?
A.
0.00227 s
B.
0.0025 s
C.
0.0023 s
D.
0.0020 s
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Solution
The period T is the reciprocal of frequency f. T = 1/f = 1/440 Hz = 0.00227 s.
Correct Answer: A — 0.00227 s
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Q. A tuning fork produces a sound wave of frequency 440 Hz. What is the period of this sound wave?
A.
0.00227 s
B.
0.00455 s
C.
0.005 s
D.
0.01 s
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Solution
The period T is the reciprocal of frequency f. T = 1/f = 1/440 Hz = 0.00227 s.
Correct Answer: B — 0.00455 s
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Q. A tuning fork produces a sound wave of frequency 440 Hz. What is the wavelength of the sound wave in air (speed of sound = 340 m/s)?
A.
0.77 m
B.
0.85 m
C.
0.90 m
D.
1.00 m
Show solution
Solution
The wavelength λ can be calculated using the formula λ = v/f, where v is the speed of sound and f is the frequency. Thus, λ = 340 m/s / 440 Hz = 0.77 m.
Correct Answer: A — 0.77 m
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Q. A tuning fork produces a sound wave of frequency 440 Hz. What is the wavelength of the sound wave in air at a temperature of 20°C?
A.
0.78 m
B.
0.34 m
C.
0.50 m
D.
0.25 m
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Solution
The speed of sound in air at 20°C is approximately 343 m/s. The wavelength λ is given by λ = v/f. Thus, λ = 343/440 ≈ 0.78 m.
Correct Answer: A — 0.78 m
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Q. A tuning fork produces a sound wave with a frequency of 440 Hz. What is the wavelength of the sound wave in air, given that the speed of sound in air is approximately 340 m/s?
A.
0.77 m
B.
0.85 m
C.
0.90 m
D.
1.00 m
Show solution
Solution
Wavelength λ is given by the formula λ = v/f. Here, v = 340 m/s and f = 440 Hz. Thus, λ = 340/440 = 0.7727 m, approximately 0.77 m.
Correct Answer: A — 0.77 m
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Q. A wave has a frequency of 50 Hz and a wavelength of 2 m. What is its speed?
A.
25 m/s
B.
50 m/s
C.
100 m/s
D.
75 m/s
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Solution
Speed v = f × λ = 50 Hz × 2 m = 100 m/s.
Correct Answer: B — 50 m/s
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Q. A wave has a frequency of 50 Hz and a wavelength of 3 m. What is its speed?
A.
150 m/s
B.
100 m/s
C.
50 m/s
D.
200 m/s
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Solution
Speed v = f × λ = 50 Hz × 3 m = 150 m/s.
Correct Answer: B — 100 m/s
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Q. A wave has a wavelength of 0.5 m and a frequency of 600 Hz. What is the speed of the wave?
A.
300 m/s
B.
600 m/s
C.
1200 m/s
D.
1500 m/s
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Solution
The speed v of a wave is given by v = fλ. Here, v = 600 Hz * 0.5 m = 300 m/s.
Correct Answer: A — 300 m/s
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Q. A wave has an amplitude of 0.5 m and a frequency of 10 Hz. What is the maximum speed of a particle in the wave?
A.
3.14 m/s
B.
6.28 m/s
C.
9.42 m/s
D.
12.56 m/s
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Solution
The maximum speed v_max is given by v_max = ωA, where ω = 2πf. Thus, ω = 2π(10) = 20π and v_max = 20π(0.5) = 10π ≈ 31.42 m/s.
Correct Answer: B — 6.28 m/s
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Q. A wave is described by the equation y(x, t) = 0.2 cos(4x - 5t). What is the amplitude of the wave?
A.
0.1 m
B.
0.2 m
C.
0.3 m
D.
0.4 m
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Solution
The amplitude of the wave is the coefficient of the cosine function, which is 0.2 m.
Correct Answer: B — 0.2 m
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Q. A wave on a string is described by the equation y(x, t) = 0.05 cos(4x - 3t). What is the amplitude of the wave?
A.
0.05 m
B.
0.1 m
C.
0.2 m
D.
0.3 m
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Solution
The amplitude of the wave is the coefficient of the cosine function, which is 0.05 m.
Correct Answer: A — 0.05 m
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Q. A wave on a string is described by the equation y(x, t) = 0.1 sin(2π(0.5x - 10t)). What is the speed of the wave?
A.
5 m/s
B.
10 m/s
C.
20 m/s
D.
25 m/s
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Solution
The speed of the wave v is given by v = fλ. Here, f = 10 Hz and λ = 2 m (from k = 2π/λ). Thus, v = 10 * 2 = 20 m/s.
Correct Answer: B — 10 m/s
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Q. A wave on a string is described by the equation y(x, t) = 0.1 sin(2π(0.5x - 2t)). What is the speed of the wave?
A.
1 m/s
B.
2 m/s
C.
0.5 m/s
D.
4 m/s
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Solution
The speed of the wave v is given by v = ω/k. Here, ω = 2π(2) = 4π rad/s and k = 2π(0.5) = π rad/m. Thus, v = (4π)/(π) = 4 m/s.
Correct Answer: B — 2 m/s
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Q. A wave on a string is described by the equation y(x, t) = 0.1 sin(2πx - 4πt). What is the amplitude of the wave?
A.
0.1 m
B.
0.2 m
C.
0.4 m
D.
1 m
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Solution
The amplitude is the coefficient of the sine function, which is 0.1 m.
Correct Answer: A — 0.1 m
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Q. A wave on a string is described by the equation y(x, t) = A sin(kx - ωt). What does 'A' represent?
A.
Wavelength
B.
Frequency
C.
Amplitude
D.
Wave number
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Solution
'A' represents the amplitude of the wave, which is the maximum displacement from the equilibrium position.
Correct Answer: C — Amplitude
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Q. A wave on a string is described by the equation y(x, t) = A sin(kx - ωt). What does 'k' represent?
A.
Angular frequency
B.
Wave number
C.
Amplitude
D.
Phase constant
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Solution
'k' is the wave number, which is related to the wavelength of the wave.
Correct Answer: B — Wave number
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Q. A wave traveling along a string is described by the equation y(x, t) = 0.1 sin(2π(0.5x - 4t)). What is the wave speed?
A.
2 m/s
B.
4 m/s
C.
8 m/s
D.
1 m/s
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Solution
The wave speed v can be found from the equation v = fλ. Here, f = 4 Hz and λ = 2 m (from k = 2π/λ, k = 1 m⁻¹). Thus, v = 4 Hz * 2 m = 8 m/s.
Correct Answer: B — 4 m/s
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Q. A wave traveling along a string is described by the equation y(x, t) = 0.1 sin(2π(0.5x - 2t)). What is the speed of the wave?
A.
1 m/s
B.
2 m/s
C.
3 m/s
D.
4 m/s
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Solution
The speed of the wave v is given by v = fλ. Here, f = 2 Hz and λ = 1 m (from the wave equation). Thus, v = 2 * 1 = 2 m/s.
Correct Answer: B — 2 m/s
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Q. A wave traveling along a string is described by the equation y(x, t) = A sin(kx - ωt). What does 'A' represent?
A.
Wavelength
B.
Amplitude
C.
Frequency
D.
Speed
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Solution
'A' represents the amplitude of the wave, which is the maximum displacement from the equilibrium position.
Correct Answer: B — Amplitude
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